MLT ASCP LATEST EXAM 2025
COMPLETE 200 QUESTIONS AND
DETAILED CORRECT ANSWERS
(VERIFIED ANSWERS) WITH
RATIONALES | A+ GRADE
General Hospital is considering the addition of a new
chemistry panel containing 12 tests. The laboratory is
asked to calculate the total cost of quality control per new
chemistry test panel. Quality control must be performed 3
times per day (every 8 hours). The labor cost per quality
control test for this panel is $2.63. A month's worth of
quality control reagent costs $354.00. What is the total
quality control cost per new chemistry test panel if 76,000
of these new panels are performed each year?
A. $0.01
B. $0.09
C. $0.04
D. $1.70 Correct Answer B;
This scenario's answer can be calculated by first
deciding what the total quality control labor costs are
as well as what the total consumable costs are. In this
case, if quality control is run 3 times per day, a total of
1095 quality control runs are performed each year.
The direct labor cost of $2.63 multiplied by 1095
quality control runs equals $2879.85 per year in
quality control direct labor. The hospital pays $354.00
,per month on quality control consumables, which
equals $4248.00 per year. The total quality control
costs in a year are equal to $2879.85 + $4248.00 =
$7127.85. If 76,000 new chemistry tests panels are
peformed each year, the total quality control cost per
new chemistry test panel will be $0.09.
A normal hemoglobin molecule is comprised of the
following:
A. Ferrous iron and four globin chains
B. Four heme and four globin chains
C. Four heme and one globin chains
D. One heme and four globin chains Correct Answer B;
A normal hemoglobin molecule consists of a tetramer,
of four heme and four globin chains, with a molecular
weight of 64,500 daltons. Each of the four units can
bind a molecule of oxygen for transport to the body's
tissues. In the image shown below, there are four
monomers (2 red globin chains and 2 blue globin
chains) which form the entire hemoglobin tetramer
structure. The green portions represent the 4 heme
groups.
Which of the following immunoglobulin classes is chiefly
responsible for the degranulation of mast cells and
basophils:
A. IgG
B. IgA
C. IgM
,D. IgE Correct Answer D;
IgE levels are often increased in patients with allergic
disease. IgE binds to the membranes of mast cells
and basophils, and if specific antigen is present to
react with the IgE molecule, degranulation of these
cells occurs, releasing histamines, and other
substances into the blood or tissues.
A microscopic examination of a normal urine pH 8.0
shows 2+ yellow-brown thorny spheres which are MOST
probably:
A. ammonium biurate crystals
B. ampicillin crystals
C. amorphous urate crystals
D. crenated red cells
E. waxy casts Correct Answer A;
Ammonium biurate crystalsare typically round,
irregularly spiked and yellow-brown in color.
Electrophoretic separation of hemoglobin fundamentally
relies on:
A. Size differences of molecules
B. Net charge differences of molecules
C. Concentration differences of molecules
D. Shape variations of molecules Correct Answer B;
Hemoglobin electrophoresis uses an electric field to
separate hemoglobin molecules based on differences
in net electrical charge. The rate of electrophoretic
migration is also dependent on the ionic radius of the
, molecule, the viscosity of the solution through which
it is migrating, the electrical field strength,
temperature, and the type of supporting medium used.
True/False
For those facilities that in the interest of safety use a
special calculation for RhIg dosage, regardless if they
round up or round down, they always add one vial. Correct
Answer True
Regardless of rounding up or down, when calculating RhIg
dosage, such facilities always add one vial. For example:
1.4 = 1 +1 = 2 vials
1.5 = 2 +1 = 3 vials
A sample of cerebrospinal fluid is diluted 1:100; the
standard 9 squares of a hemocytometer are counted on
each side for a total of 18 large squares.
Side 1-- 186 nucleated cells counted
Side 2-- 184 nucleated cells counted
total nucleated cells = 370
Using the standard hemocytometer formula shown on the
right, what is the nucleated cell count per microliter (µL)?
A. 1.03 x 10^4
B. 2.06 x 10^4
C. 4.62 x 10^4
D. 9.25 x 10^4 Correct Answer B;
Using the formula on the right,
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