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CS6400 - Exam 3 UPDATED ACTUAL Questions and CORRECT Answers
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CS6400 - Exam 3 UPDATED ACTUAL Questions and CORRECT Answers Natural Join - CORRECT ANSWER- The result of this is the set of all combinations of tuples in R and S that are equal on their common attribute names. A special case of an equijoin. Left Outer Join - CORRECT ANSWER- A construct ope...

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  • November 20, 2024
  • 8
  • 2024/2025
  • Exam (elaborations)
  • Questions & answers

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CS6400 - Exam 3 UPDATED ACTUAL
Questions and CORRECT Answers
Natural Join - CORRECT ANSWER✔✔- The result of this is the set of all combinations of
tuples in R and S that are equal on their common attribute names. A special case of an
equijoin.


Left Outer Join - CORRECT ANSWER✔✔- A construct operator which results in the set of
all combinations of tuples in R and S that are equal on their common attribute names, in
addition (loosely speaking) to tuples in R that have no matching tuples in S.


Insert - CORRECT ANSWER✔✔- A basic SQL operation in which new records are added to
a table.


Delete - CORRECT ANSWER✔✔- A basic SQL operation in which existing records are
removed from a table.


Update - CORRECT ANSWER✔✔- A basic SQL operation in which existing records are
changed in a table.


Select * - CORRECT ANSWER✔✔- A basic SQL operation in which existing records are
chosen from a table.


Select Distinct - CORRECT ANSWER✔✔- A basic SQL operation in which only unique
existing records are chosen from a table.


Intersect - CORRECT ANSWER✔✔- Set operator which includes all tuples that are in both
R and S.


Union - CORRECT ANSWER✔✔- Set operator which includes all tuples that are either in R
or in S or in both R and S. Duplicates are removed.


Union All - CORRECT ANSWER✔✔- set operator which includes all tuples that are either
in R or in S or in both R and S. Duplicates are not removed.

, Count(*) - CORRECT ANSWER✔✔- SQL function which returns the number of rows that
matches the specified criteria.


Group By - CORRECT ANSWER✔✔- SQL operator which rolls up the result set by one or
more columns.


Equijoin - CORRECT ANSWER✔✔- A theta join using the equality operator



Difference / Minus - CORRECT ANSWER✔✔- Set operator which includes all tuples that
are in R but not in S


Theta Join - CORRECT ANSWER✔✔- A construct operator which allows for arbitrary
comparison relationships (such as >=)


Inner Join - CORRECT ANSWER✔✔- Requires each row in the two joined tables to have
matching column values.


Cartesian Product - CORRECT ANSWER✔✔- A construct operator which results in the set
of all combinations of tuples in R and S


Reflexive Inference Rule - CORRECT ANSWER✔✔- If Y is a subset of X, then X -> Y. i.e.
EG -> G


Augmentation Inference Rule - CORRECT ANSWER✔✔- If X -> Y, then XZ -> YZ for any
Z i.e. E->A, therefore EG->AG


Transitive Inference Rule - CORRECT ANSWER✔✔- If X -> Y and Y -> Z, then X -> Z,
i.e. B->E, E->A, therefore B->A


Decomposition Inference Rule - CORRECT ANSWER✔✔- If X -> YZ then X -> Y and X -
>Z

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