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Zusammenfassung Formelsammlung - Allgemeine und anorganische Chemie (1. Semester) $3.21
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Zusammenfassung Formelsammlung - Allgemeine und anorganische Chemie (1. Semester)
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  • Course
  • Allgemeine und anorganische Chemie
  • Institution
  • Hochschule Niederrhein

Das dreiseitige Dokument enthält die vollständige Formelsammlung und Einheiten aus dem Modul "Chemie 1: Allgemeine und anorganische Chemie" aus dem ersten Semester. Damit habe ich damals die Klausur bestanden.

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Document information

  • December 12, 2024
  • 3
  • 2024/2025
  • Summary

Subjects

  • chemie
  • allgemeine chemie
  • anorganische chemie
  • formelsammlung
  • klausurvorbereitung
  • chemie 1
  • erstes semester
  • ernährungswissenschaften
  • hsnr
  • vollständige formelsammlung

Written for

  • Hochschule Niederrhein
  • Ernährungswissenschaften
  • Allgemeine und anorganische Chemie
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Formelsammlung

Formel



Protonenzahl/Elektronenzahl Z = A (Nukleonenzahl) – Neutronenzahl

Nukleonenzahl/Massenzahl A (=Alles) = Z (Protonenzahl/Elektronenzahl) + Neutronenzahl

Neutronenzahl = A (Nukleonenzahl) – Z (Protonenzahl/Elektronenzahl)

Nebenquantenzahl l = Hauptquantenzahl (n) – 1

Magnetquantenzahl m = - l, l-1,…0, …, l+1, +l

Stoffmenge n = m / M
n=c*V

Stoffmengenkonzentration c = n / V (mit konzentriertem Stoff)

c(OH-) = KW / c(H+)

= c(H+) = 10−𝑝𝐻

c(𝐻3 𝑂+ ) = 10−𝑝𝐻

c(𝑂𝐻 − ) = 10−𝑝𝑂𝐻

Massenkonzentration β = c * M

β = m / VLö

Ionenprodukt/Gleichgewichtskonstante KW = 1* 10-14 mol2/L2

Massenanteil w = m / mLö

Dichte ρLö = mLö / VLö

Masse m = c * V * M → Formel in Formel eingesetzt

Gleichung (Verdünnung berechnen) = c1 * V1 = c2 * V2 (2 NaOH → V * 2 rechnen)

Massenzahl/relative Atommasse M = n * relative Atommasse + n * relative Atommasse …..

n = Anzahl des Atoms

Löslichkeitsprodukt KL(AB) = c(A+) * c(B-)

KL(molx+y/Lx+y) = c(Kation+)x * c(Anion-)y

pKL = -log(KL) (negativer dekadischer Logarithmus von KL)

pH-Wert von starken Säuren (pKS – Wert niedrig)

pH= -log (molare Konzentration)

pH-Wert von starken Basen (pKB – Wert niedrig)

pOH= -log (molare Konzentration)

pH= 14 – pOH

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