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MATH 215 Introduction to Statistics Assignment 1 passed new update Athabasca University
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MATH 215 Introduction to Statistics Assignment 1 passed new update Athabasca University
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MATH 215 Athabasca UniversityIntroduction to
Statistics Assignment 1
(Revision 10)
Overview
Total marks: / 75
This assignment covers content from Unit 1 of the course. It assesses your knowledge of many of the
statistical terms that will be used throughout the course, as well as your ability to organize, display and
summarize data.
Instructions
Show all your work and justify all of your answers and conclusions, except for the TRUE/FALSE
questions.
Keep your work to 4 decimals, unless otherwise stated.
(22 total marks)
1. Observations from the first 25 days of the year showed that the following number of pedestrians
used a particular crosswalk on each day:
19 132 25 78 62 101 84 32 99 71 43 56 64 81 59 67 43 97 105 91 31 66 76 87 125
(8 marks)
Construct a frequency distribution for this data using a lower limit for the first class of 15 and a
class width of 20. Indicate the class limits, boundaries, midpoints, frequencies and cumulative
frequencies.
Lower limit:15
Upper limit:135
Number of Frequency Relative Cumulative Class midpoints Boundaries
pedestrians frequency frequency
15 to less than 35 4 4/25x100=16% 4/25=0.16 (15+35)/2=25 (36-35)/2 =0.5
15-.5=14.5
35+.5=35.5
14.5-35.5
36 to less than 55 2 2/25x100=8% 6/25=0.24 (36+55)/2=45.5 (56-55)/2 =0.5
56-.5=55.5
36-.5=35.5
, 55.5-75.5
76 to less than 95 6 6/25x100=24% 19/25=0.76 (76+95)/2=85.5 (76-75)/2= .5
76-.5=75.5
95+.5=95.5
75.5-95.5
96 to less than 4 4/25x100=16% 23/25=0.92 (96+115)/2=105.5 (96-95)/2= 0.5
115
96-.5=95.5
115+.5=115.5
95.5-115.5
116 to less than 2 2/25x100=8% 25/25=1.00 (116+135)/2=125.5 (116-115)/2= 0.5
135
116-.5=115.5
135+.5=135.5
115.5-135.5
Total f=25 =100%
(4 marks)
Create a relative frequency polygon of the number of pedestrians.
(4 marks)
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