Exam (elaborations)
Solutions Manual for Structural Analysis 9th Edition Hibbeler
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- Alderson-Broaddus College
Solutions Manual for Structural Analysis 9th Edition Hibbeler
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SOLUTIONS MANUAL FORSTRUCTURAL ANALYSIS 9TH
EDITION HIBBELER
,Structural Analysis 9th Edition Hibbeler Solutions Manual
© 2014 Pearson Education, Inc., Upper Saddle River, NJ. All rights reserved. This material is protected under all copyright laws as they currently
exist. No portion of this material may be reproduced, in any form or by any means, without permission in writing from the publisher.
2–1. The steel framework is used to support the C
reinforced stone concrete slab that is used for an office. The
slab is 200 mm thick. Sketch the loading that acts along B D
members BE and FED. Take a = 2 m, b = 5 m. Hint: See
Tables 1.2 and 1.4. A
a
E
b a
F
Solution
b 5m
Beam BE. Since = = 2.5, the concrete slab will behave as a one-way slab.
a 2m
Thus, the tributary area for this beam is rectangular, as shown in Fig. a, and the
intensity of the uniform distributed load is
200 mm thick reinforced stone concrete slab:
(23.6 kN>m3)(0.2 m)(2 m) = 9.44 kN>m
. We or
Live load for office: (2.40 kN>m2)(2 m) = 4.80 kN>m
m W ina g
b)
ed e n
in
no W iss ea s
itt id tio
is e D t w
t p or em ch
14.24 kN>m Ans.
d th g. in t la
an on in rs h
Due to symmetry the vertical reactions at B and E are
k g rn to rig
or in a uc y
w d le tr p
er ld
By = Ey = (14.24 kN>m)(5)>2 = 35.6 kN
e lu nt ns co
th inc de f i es
The loading diagram for beam BE is shown in Fig. b.
of rk ( stu e o tat
ity o g us d S
Beam FED. The only load this beam supports is the vertical reaction of beam BE
te is ss th ite
at E, which is Ey = 35.6 kN. The loading diagram for this beam is shown in Fig. c.
in f th se for Un
gr w in e
th t o a ly by
y ar d le d
ro p an o te
st ny s d s ec
de f a rse de ot
s
ill o u vi pr
w le co ro is
sa eir is p rk
th d wo
an his
e
T
26
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,© 2014 Pearson Education, Inc., Upper Saddle River, NJ. All rights reserved. This material is protected under all copyright laws as they currently
exist. No portion of this material may be reproduced, in any form or by any means, without permission in writing from the publisher.
2–2. Solve Prob. 2–1 with a = 3 m, b = 4 m. C
B D
A
a
E
b a
F
Solution
b 4
Beam BE. Since = 6 2, the concrete slab will behave as a two-way slab. Thus,
a 3
the tributary area for this beam is the hexagonal area shown in Fig. a, and the
maximum intensity of the distributed load is
200 mm thick reinforced stone concrete slab: (23.6 kN>m3)(0.2 m)(3 m)
= 14.16 kN>m
Live load for office: [(2.40 kN>m2)(3 m)] = 7.20 kN>m
21.36 kN>m Ans.
. We or
m W ina g
b)
ed e n
in
no W iss ea s
Due to symmetry, the vertical reactions at B and E are
itt id tio
is e D t w
t p or em ch
d th g. in t la
1
2c (21.36 kN>m)(1.5 m) d + (21.36 kN>m)(1 m)
an on in rs h
2
k g rn to rig
B y = Ey = or in a uc y
2
w d le tr p
er ld
e lu nt ns co
= 26.70 kN
th inc de f i es
of rk ( stu e o tat
The loading diagram for beam BE is shown in Fig. b.
ity o g us d S
Beam FED. The loadings that are supported by this beam are the vertical reaction
te is ss th ite
of beam BE at E which is Ey = 26.70 kN and the triangular distributed load of which
in f th se for Un
gr w in e
its tributary area is the triangular area shown in Fig. a. Its maximum intensity is
th t o a ly by
y ar d le d
200 mm thick reinforced stone concrete slab: (23.6 kN>m3)(0.2 m)(1.5 m)
ro p an o te
st ny s d s ec
= 7.08 kN>m
de f a rse de ot
s
3.60 kN>m
ill o u vi pr
Live load for office: (2.40 kN>m2)(1.5 m) Ans.
w le co ro is
=
10.68 kN>m
sa eir is p rk
th d wo
The loading diagram for beam FED is shown in Fig. c.
an his
e
T
27
, © 2014 Pearson Education, Inc., Upper Saddle River, NJ. All rights reserved. This material is protected under all copyright laws as they currently
exist. No portion of this material may be reproduced, in any form or by any means, without permission in writing from the publisher.
2–3. The floor system used in a school classroom consists E
of a 4-in. reinforced stone concrete slab. Sketch the loading b
a
that acts along the joist BF and side girder ABCDE. Set
a
a = 10 ft, b = 30 ft. Hint: See Tables 1.2 and 1.4. D
a
C
a
B
F
A
Solution
b 30 ft
Joist BF. Since = = 3, the concrete slab will behave as a one-way slab.
a 10 ft
Thus, the tributary area for this joist is the rectangular area shown in Fig. a, and the
intensity of the uniform distributed load is
4
4-in.-thick reinforced stone concrete slab: (0.15 k>ft3) a ftb (10 ft) = 0.5 k>ft
12
. We or
Live load for classroom: (0.04 k>ft2)(10 ft) = 0.4 k>ft
m W ina g
b)
ed e n
in
no W iss ea s
itt id tio
is e D t w
t p or em ch
0.9 k>ft
d th g. in t la
Ans.
an on in rs h
k g rn to rig
Due to symmetry, the vertical reactions at B and F are
or in a uc y
w d le tr p
er ld
e lu nt ns co
By = Fy = (0.9 k>ft)(30 ft)>2 = 13.5 k Ans.
th inc de f i es
of rk ( stu e o tat
The loading diagram for joist BF is shown in Fig. b.
ity o g us d S
Girder ABCDE. The loads that act on this girder are the vertical reactions of the
te is ss th ite
in f th se for Un
joists at B, C, and D, which are By = Cy = Dy = 13.5 k. The loading diagram for
gr w in e
this girder is shown in Fig. c.
th t o a ly by
y ar d le d
ro p an o te
st ny s d s ec
de f a rse de ot
s
ill o u vi pr
w le co ro is
sa eir is p rk
th d wo
an his
e
T
28
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