Correct Answers
What best describes a tree system? Right Ans - Cross mains and the branch
lines are not tied together, providing only one path of water flow.
Factors that define Occupancy Group Hazard 2 include: Right Ans -
Quantity and combustibility of contents are moderate to high.
Stockpiles of contents with moderate rates of heat release do not exceed 12 ft
and stockpiles with high heat release do not exceed 8 ft
(Ref NFPA 13 Sec. 5.3.2)
Which of the following standards contain reqs. pertaining to the installation of
underground piping? Right Ans - NFPA 13 & 24 (Both in Chapter 10)
Which of the following should you inspect on an extension cord before each
use? Right Ans - The grounding prong & the insulation for nicks, cuts, or
damage
________ indicates a mandatory req. according to NFPA definitions. Right Ans
- Shall.
(Ref. NFPA 13 2016, Sec. 3.2.4.)
100 GPM is flowing through 100' of 1 1/4 in. Sch. 40 pipe. How many feet of 1
1/2 in. pipe will produce the same friction loss? Right Ans - Assume this is
Schedule 40 pipe, C = 120. Use the Hazen-Williams formula to calculate the
friction loss for the 1 ¼ in. pipe and the 1 ½ in. pipe.
For 1 ¼ in. pipe (ID = 1.38):
P friction loss = 4.52 x Q 1.85
c 1.85 x d 4.87
, P friction loss = 4.52 x 100 1.85
120 1.85 x 1.38 4.87
P friction loss = 0.672 psi/ft
For 1 ½ in. pipe (ID = 1.61):
P friction loss = 4.52 x Q 1.85
c 1.85 x d 4.87
P friction loss = 4.52 x 100 1.85
120 1.85 x 1.61 4.87
P friction loss = 0.317 psi/ft
Step #2: Determine the total friction loss for 100 gpm flowing through 100 ft.
of 1 ¼ in. Schedule 40 black steel pipe: 100 ft. x 0.672 psi/ft = 67.2 psi
Step #3: Determine the pipe length to produce the same friction loss in the 1
½ in. pipe:
y ft. x 0.317 psi/ft = 67.2 psi
y = 67.2 ÷ 0.317
y = 212 ft.