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MATH 225N Week 5 Assignment / MATH225 Week 5 Assignment: Central Limit Theorem for Means (Latest, 2020): Chamberlain College of Nursing | 100 % VERIFIED ANSWERS, GRADE A$20.49
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MATH 225N / MATH225 Statistical Reasoning For Health Sciences (MATH225)
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MATH 225N Week 5 Assignment / MATH225 Week 5 Assignment: Central Limit Theorem for Means (Latest, 2020): Chamberlain College of Nursing | 100 % VERIFIED ANSWERS, GRADE A
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MATH 225N / MATH225 Statistical Reasoning For Health Sciences (MATH225)
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CHAMBERLAIN COLLEGE OF NURSING
MATH 225 Week 5 Assignment: Central Limit Theorem for Means (Latest): Statistical reasoning for health sciences: Chamberlain College of Nursing
MATH225N Week 5 Assignment: Central Limit Theorem for Means (Latest): Statistical reasoning for health sciences: Chamberlain College of Nursing
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MATH 225N / MATH225 Statistical Reasoning For Health Sciences (MATH225)
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MATH225 Week 5 Assignment: Central Limit Theorem for Means
1. Question
A family of statisticians is trying to decide if they can afford for their child to play youth
baseball. The cost of joining a team is normally distributed with a mean of $750and a
standard deviation of $185. If a sample of 40teams is selected at random from the
population, select the expected mean and standard deviation of the sampling
distribution below.
Correct answer:
σx¯=$29.25
μx¯=$750
The standard deviation of the sampling distribution
σx¯=σn−−√=$18540−−√=$29.25
When the distribution is normal the mean of the sampling distribution is equal to the
mean of the population μx¯=μ=$750.
Question
A cupcake baker is planning a supplies order and needs to know how much flour he
needs. He knows that his recipes use an average of 100grams of flour, normally
distributed, with a population standard deviation of 15grams. If he is consulting a
sample size of 30recipes, select the mean and standard deviation of the sampling
distribution to help him order his supplies from the options below.
σx¯=2.74grams
μx¯=100grams
The standard deviation of the sampling distribution is
σx¯=σn−−√=1530−−√=2.74 grams
, Likewise, when the distribution is normal the mean of the sampling distribution is equal
to the mean of the population μx¯=μ=100grams.
Question
A head librarian for a large city is looking at the overdue fees per user system-wide to
determine if the library should extend its lending period. The average library user has
$19.67in fees, with a standard deviation of $7.02. The data is normally distributed and
a sample of 72library users is selected at random from the population. Select the
expected mean and standard deviation of the sampling distribution from the options
below.
Correct answer:
σx¯=$0.83
μx¯=$19.67
The standard deviation of the sampling distribution is
σx¯=σn−−√=$7.0272−−√=$0.83
When the distribution is normal, the mean of the sampling distribution is equal to the
mean of the population μx¯=μ=$19.67.
2. Question
A well known social media company is looking to expand their online presence by
creating another platform. They know that they current average 2,500,000users each
day, with a standard deviation of 625,000users. If they randomly sample 50days to
analyze the use of their existing technology, identify each of the following, rounding to
the nearest whole number if necessary:
We are given population mean μ=2,500,000and population standard deviation
σ=625,000, and want to find the mean and standard error of the sampling
distribution, μx¯and σx¯for samples of size n=50.
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