ECE 160
University Of California - Davis
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ECE 160Solution09. Modern Digital and Analog Communication Systems
- Exam (elaborations) • 257 pages • 2021
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2.1-1 Both ϕ(t) and w0(t) are periodic.
The average power of ϕ(t) is Pg = T1 R0T ϕ2(t) dt = π1 R0π e-t/22 dt = 1-πe-π .
The average power of w0(t) is Pg = T10 RoT0 wo2(t) dt = T10 R0T0 1 · dt = 1.
2.1-2
(a) Since x(t) is a real signal, Ex = R02 x2(t) dt.
Solving for Fig. S2.1-2(a), we have
Ex = R02(1)2 dt = 2, Ey = R01(1)2 dt + R12(-1)2 dt = 2
Ex+y = R01(2)2 dt = 4, Ex-y = R12(2)2 dt = 4
Therefore, Ex±y = Ex + Ey.
Solving for Fig. S2.1-2(b), we have
Ex = R0π(1)2 dt + Rπ2π(...
Exam (elaborations)
ECE 160Solution09. Modern Digital and Analog Communication Systems
Last document update:
ago
2.1-1 Both ϕ(t) and w0(t) are periodic. The average power of ϕ(t) is Pg = T1 R0T ϕ2(t) dt = π1 R0π e-t/22 dt = 1-πe-π . The average power of w0(t) is Pg = T10 RoT0 wo2(t) dt = T10 R0T0 1 · dt = 1. 2.1-2 (a) Since x(t) is a real signal, Ex = R02 x2(t) dt. Solving for Fig. S2.1-2(a), we have Ex = R02(1)2 dt = 2, Ey = R01(1)2 dt + R12(-1)2 dt = 2 Ex+y = R01(2)2 dt = 4, Ex-y = R12(2)2 dt = 4 Therefore, Ex±y = Ex + Ey. Solving for Fig. S2.1-2(b), we have Ex = R0π(1)2 dt + Rπ2π(...
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