Chem 103 lab exam 4 - Study guides, Class notes & Summaries

What does it mean that the heat of a reaction is an extensive property? 2. (3 points) Does the following reaction give off heat or absorb heat? Explain briefly. C D H = +263Kcal/mol 3. (4 points) In one experiment in the video, room temperature water was mixed with water at about 38 degrees. To what temperature (about) did the mixture of the two water samples come to after setting for a few minutes? Answer: 1. The heat depends on the amount of substance. If the amount of substance is d...

Chem 103 Lab Exam 5 Review Question 1 8 / 10 pts 1. (2 points) In the Boyle’s law experiment, what pressure unit was used to gauge the pressure? 2. (2 points) According to Boyle’s law, as the volume of a gas increases, the pressure . 3. (6 points) A sample of gas occupies a volume of 10.5 L when the pressure is 14.3 psi. Use Boyle’s Law to calculate the volume (L) when the pressure is increased to 19.6psi. Show the calculation. Your Answer: Millimeters of mercu...

CHEM 103 Lab Exam 4 – Portage Learning. How much heat was gained by the tap water if the specific heat of water is 4.18 J/K-g? 2. (3 points) In one experiment in the video, HCl was mixed with another substance. What other substance was mixed with HCl? 3. (4 points) One student conducts an acid-base reaction where he finds the following results. What is the enthalpy of the reaction (in KJ/mol)? Heat gained by solution 3875 J

CHEM 103 Lab Exam 4 – Portage Learning. What does it mean that the heat of a reaction is an extensive property? 2. (3 points) Does the following reaction give off heat or absorb heat? Explain briefly. C D H = +263Kcal/mol 3. (4 points) In one experiment in the video, room temperature water was mixed with water at about 38 degrees. To what temperature (about) did the mixture of the two water samples come to after setting for a few minutes? Answer: 1. The heat depends on the amount of s...

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CHEM 103 Module 2 Exam (Portage Learning) Show the calculation of the molecular weight for the following compounds, reporting your answer to 2 places after the decimal. 1. Al (SO ) 2. C H NOBr 2 4 3 7 5 1. Al (SO ) Al = 2 x 26.98 = 53.96 S = 3 x 32.07 = 96.21 O = 12 x 16.00 = 192 2 4 3 M2: Exam - Requires Respondus LockDown Browser + Webcam: General Chemistry I w/Lab-2021- Kozminski 3/18 Total Molecular Weight for Al (SO ) = 342.17 2. C H NOBr C = 7 x 12.01 = 84.07 H = 5 x 1.008 ...

CHEM 103 Module 2 Exam (General Chemistry) – Portage Learning. Total Molecular Weight for Al (SO ) = 342.17 2. C H NOBr C = 7 x 12.01 = 84.07 H = 5 x 1.008 = 5.04 N = 1 x 14.01 = 14.01 O = 1 x 16.00 = 16.00 Br = 1 x 79.90 = 79.90 Total Molecule Weight for C H NOBr= 199.02 2 4 3 7 5 7 5 1. 2Al + 3S + 12O = 342.17 2. 7C + 5H + N + O + Br = 199.02 Question 2 10 / 10 pts You may find the following resources helpful: Scientific Calculator ( Periodic Table ( Equation Table ( downloa...

CHEM 103 Module 2 Exam (General Chemistry) – Portage Learning. Al (SO ) Al = 2 x 26.98 = 53.96 S = 3 x 32.07 = 96.21 O = 12 x 16.00 = 192 2 4 3 M2: Exam - Requires Respondus LockDown Browser + Webcam: General Chemistry I w/Lab-2021- Kozminski 3/18 Total Molecular Weight for Al (SO ) = 342.17 2. C H NOBr C = 7 x 12.01 = 84.07 H = 5 x 1.008 = 5.04 N = 1 x 14.01 = 14.01 O = 1 x 16.00 = 16.00 Br = 1 x 79.90 = 79.90 Total Molecule Weight for C H NOBr= 199.02