Nao volume 2 - Study guides, Class notes & Summaries

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CHEM120 Final Exam (Version-2, Latest-2023)|Verified and 100% Correct Q & A|WITH WELL ELABORATE WORKINGS AND CALCULATIONS:- Chamberlain College of Nursing
  • CHEM120 Final Exam (Version-2, Latest-2023)|Verified and 100% Correct Q & A|WITH WELL ELABORATE WORKINGS AND CALCULATIONS:- Chamberlain College of Nursing

  • Exam (elaborations) • 23 pages • 2023
  • 6. (TCO 6) A gas at a temperature of 95 degrees C occupies a volume of 165 mL. Assuming constant pressure, determine the volume at 25 degrees C. Show your work. (Points : 5) Using Charles’ Law, (V1/T1) = (V2/T2). First, convert temperature to KELVIN (T1 = t1 +273) Thus, T1 = 95 + 273 = 368. We have V1 (165 mL) & T2 = (25 + 273) = 298. V2 = (V1*T2)/T1 = (165 mL*298)/368 = 133.6 mL. 0 Short 16 7. (TCO 6) A sample of helium gas occupies 1021 mL at 719 mmHg. For a gas sample at constant...
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CHEM 120 Week 8 Final Exam COMPLETE (100% CORRECT SOLUTIONS) | Already GRADED A.
  • CHEM 120 Week 8 Final Exam COMPLETE (100% CORRECT SOLUTIONS) | Already GRADED A.

  • Exam (elaborations) • 22 pages • 2021
  • Available in package deal
  • 6. (TCO 6) A gas at a temperature of 95 degrees C occupies a volume of 165 mL. Assuming constant pressure, determine the volume at 25 degrees C. Show your work. (Points : 5) Using Charles’ Law, ( V1/T1) = (V2/T2). First, convert temperature to KELVIN (T1 = t1 +273) Thus, T1 = 95 + 273 = 368. We have V1 (165 mL) & T2 = (25 + 273) = 298. V2 = (V1*T2)/T1 = (165 mL*298)/368 = 133.6 mL. 0 7 Short 16 7. (TCO 6) A sample of helium gas occupies 1021 mL at 719 mmHg. For a gas sample at constant tempera...
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CHEM 120 Week 8 Final Exam (Solved Q & A) | Highly Rated Paper | Already Graded A+
  • CHEM 120 Week 8 Final Exam (Solved Q & A) | Highly Rated Paper | Already Graded A+

  • Exam (elaborations) • 22 pages • 2021
  • Available in package deal
  • 6. (TCO 6) A gas at a temperature of 95 degrees C occupies a volume of 165 mL. Assuming constant pressure, determine the volume at 25 degrees C. Show your work. (Points : 5) Using Charles’ Law, ( V1/T1) = (V2/T2). First, convert temperature to KELVIN (T1 = t1 +273) Thus, T1 = 95 + 273 = 368. We have V1 (165 mL) & T2 = (25 + 273) = 298. V2 = (V1*T2)/T1 = (165 mL*298)/368 = 133.6 mL. 0 7 Short 16 7. (TCO 6) A sample of helium gas occupies 1021 mL at 719 mmHg. For a gas sample at constant tempera...
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CHEM 120 Week 8 Final Exam graded A
  • CHEM 120 Week 8 Final Exam graded A

  • Exam (elaborations) • 23 pages • 2021
  • CHEM 120 Week 8 Final Exam 1.(TCO 6) A gas at a temperature of 95 degrees C occupies a volume of 165 mL. Assuming constant pressure, determine the volume at 25 degrees C. Show your work. (Points : 5) Using Charles’ Law, (V1/T1) = (V2/T2). First, convert temperature to KELVIN (T1 = t1 +273) Thus, T1 = 95 + 273 = 368. We have V1 (165 mL) & T2 = (25 + 273) = 298. V2 = (V1*T2)/T1 = (165 mL*298)/368 = 133.6 mL. 0 7 Short 16 2.(TCO 6) A sample of helium gas occupies 1021 mL at 719 mmHg. F...
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