Chem 103 lab exam 4 - Study guides, Class notes & Summaries

CHEM 103 Module 2 Exam (Portage Learning) Show the calculation of the molecular weight for the following compounds, reporting your answer to 2 places after the decimal. 1. Al (SO ) 2. C H NOBr 2 4 3 7 5 1. Al (SO ) Al = 2 x 26.98 = 53.96 S = 3 x 32.07 = 96.21 O = 12 x 16.00 = 192 2 4 3 M2: Exam - Requires Respondus LockDown Browser + Webcam: General Chemistry I w/Lab-2021- Kozminski 3/18 Total Molecular Weight for Al (SO ) = 342.17 2. C H NOBr C = 7 x 12.01 = 84.07 H = 5 x 1.008 ...

CHEM 103 Module 2 Exam (General Chemistry) – Portage Learning. Show the calculation of the molecular weight for the following compounds, reporting your answer to 2 places after the decimal. 1. Al (SO ) 2. C H NOBr 2 4 3 7 5 1. Al (SO ) Al = 2 x 26.98 = 53.96 S = 3 x 32.07 = 96.21 O = 12 x 16.00 = 192 2 4 3 M2: Exam - Requires Respondus LockDown Browser + Webcam: General Chemistry I w/Lab-2021- Kozminski 3/18 Total Molecular Weight for Al (SO ) = 342.17 2. C H NOBr C = 7 x 12.01 ...

CHEM 103 Lab Exam 1 – Portage Learning. What is the wide-mouthed glass container shown below? Your Answer: 2. Why is glass so often used as a material for lab containers? 3. What is the metal device used to hold hot containers? 4. What is the weighing dish used for solids? 5. What device is used to smother small fires?

Chem 103 portage learning Lab Exam 4

CHEM MISC General Chemistry I Spring 2020 – Exam 3 Version A Questions and Answers Instructions: 1. Do NOT open this exam until you are told to do so. Opening the exam before the start of the exam is considered an act of Academic Dishonesty. 2. All answers must be bubbled into the scantron answer sheet. 3. No credit will be given for answers written on this exam. 4. You must use a #2 pencil to bubble in the answers on your scantron. 5. This is a multiple-choice exam consisting of 31 ...

NURS 6531 FINAL EXAM STUDY GUIDE NURS 6531 FINAL EXAM STUDY GUIDE PLEASE DO NOT SHARE IN THE GROUP AS A POST. EVERY MEMBER WHO HAS CONTRIBUTED HAS RECEIVED A COPY. THOSE WHO HAVE NOT CONTRIBUTED THEIR ASSIGNED PORTIONS HAVE BEEN EXCLUDED. Still waiting for: 79. Severe depression 80. GAD When I receive these topics, I will post them in the group and you can just copy them and paste them into the study guide. If these topics are not received by next weekend, I will t...

CHEM 102 Winter 18 Final Exam (A) Questions and Answers Potentially useful data: x  1 atm = 760 torr = 760 mm Hg 2 a [A]t = – kt + [A]o ΔG° = ΔH° – T ΔS° ln[A]t = – kt + ln[A]o ΔG = ΔG° + RT ln Q 1/[A]t = kt +1/[A]o ΔG° = – RT ln K First order half-life: t1/2 = ln2 / k ΔG° = – nFE° pH  pKa  log base acid  E  E  R T ln Q n F R = 8.314 J mol-1 K-1 F = 96500 C/mol e- 1. Please choose the letter “A” as your a...

CHEM 102 Winter 18 Final Exam (A) Questions and Answers Potentially useful data: x  1 atm = 760 torr = 760 mm Hg 2 a [A]t = – kt + [A]o ΔG° = ΔH° – T ΔS° ln[A]t = – kt + ln[A]o ΔG = ΔG° + RT ln Q 1/[A]t = kt +1/[A]o ΔG° = – RT ln K First order half-life: t1/2 = ln2 / k ΔG° = – nFE° pH  pKa  log base acid  E  E  R T ln Q n F R = 8.314 J mol-1 K-1 F = 96500 C/mol e- 1. Please choose the letter “A” as your a...

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