Chem 103 module 2 exam - Study guides, Class notes & Summaries

Chem 103 Module 1 to 6 Exam with Verified answers (100 OUT OF 100) Portage learning (Latest Update) MODULE 1 EXAM Question 1 Click this link to access the Periodic Table. This may be helpful throughout the exam. 1. Convert 845.3 to exponential form and explain your answer. 2. Convert 3.21 x 10-5 to ordinary form and explain your answer. 1. Convert 845.3 = larger than 1 = positive exponent, move decimal 2 places = 8.453 x 102 2. Convert 3.21 x 10-5 = negative exponent = smalle...

CHEM 103 Module 1 Exam, CHEM 103 Module 2 Exam, CHEM 103 Module 3 Exam, CHEM 103 Module 4 Exam, CHEM 103 Module 5 Exam, CHEM 103 Module 6 Exam & CHEM 103 Final Exam (Up-to-date, ): Portage Learning (QUESTIONS & ANSWERS) CHEM103 Module 1 Exam, CHEM103 Module 2 Exam, CHEM103 Module 3 Exam, CHEM103 Module 4 Exam, CHEM103 Module 5 Exam, CHEM103 Module 6 Exam ,CHEM103 Final Exam (Up-to-date, ): Portage Learning (QUESTIONS & ANSWERS) CHEM 103 Module 1, 2, 3, 4, 5, 6 Exam, CHEM 103 Final Exam (Up...

Show the calculation of the molecular weight for the following compounds, reporting your answer to 2 places after the decimal. 1. (NH4)2CO3 2. C8H6NO4Br

CHEM 103 Module 1, 2, 3, 4, 5, 6 Exam (Latest-2023)/ CHEM103 Module 1, 2, 3, 4, 5, 6 Exam: General Chemistry II: Portage Learning |100% Correct Q & A|

Exam CHEM 103 Final Exam (Version-1, Latest-2023)/ CHEM103 Final Exam / CHEM 103 General Chemistry Final Exam/ CHEM103 General Chemistry Final Exam: Portage Learning |100 % Correct Q & A| Exam CHEM 103 Final Exam (Version-1, Latest-2023)/ CHEM103 Final Exam / CHEM 103 General Chemistry Final Exam/ CHEM103 General Chemistry Final Exam: Portage Learning |100 % Correct Q & A| ...

Show the calculation of the molecular weight for the following compounds, reporting your answer to 2 places after the decimal. 1. Al (SO ) 2. C H NOBr 2 4 3 7 5 1. Al (SO ) Al = 2 x 26.98 = 53.96 S = 3 x 32.07 = 96.21 O = 12 x 16.00 = 192 2 4 3 M2: Exam - Requires Respondus LockDown Browser + Webcam: General Chemistry I w/Lab-2021- Kozminski 3/18 Total Molecular Weight for Al (SO ) = 342.17 2. C H NOBr C = 7 x 12.01 = 84.07 H = 5 x 1.008 = 5.04 N = 1 x 14.01 = 14.01 O = 1 x 16....

Click this link to access the Periodic Table. This may be helpful throughout the exam. 1. Convert 845.3 to exponential form and explain your answer. 2. Convert 3.21 x 10-5 to ordinary form and explain your answer. 1. Convert 845.3 = larger than 1 = positive exponent, move decimal 2 places = 8.453 x 102 2. Convert 3.21 x 10-5 = negative exponent = smaller than 1, move decimal 5 places = 0. Question 2 Click this link to access the Periodic Table. This may be helpful throughout the exam. ...

CHEM 103 Module 1 Exam, CHEM 103 Module 2 Exam, CHEM 103 Module 3 Exam, CHEM 103 Module 4 Exam, CHEM 103 Module 5 Exam, CHEM 103 Module 6 Exam (Latest-2022): Portage Learning |Verified Q & A| CHEM103 Module 1 Exam, CHEM103 Module 2 Exam, CHEM103 Module 3 Exam, CHEM 103 Module 4 Exam, CHEM 103 Module 5 Exam, CHEM 103 Module 6 Exam (Latest-2022): Portage Learning |Verified Q & A| CHEM 103 Module 1, 2, 3, 4, 5, 6 Exam (Latest-2022)/ CHEM103 Module 1, 2, 3, 4, 5, 6 Exam: General Chemistry II: ...

Chem 103 Module 1 to 6 Exam answers Portage learning latest complete update MODULE 1 EXAM Question 1 Click this link to access the Periodic Table. This may be helpful throughout the exam. 1. Convert 845.3 to exponential form and explain your answer. 2. Convert 3.21 x 10-5 to ordinary form and explain your answer. 1. Convert 845.3 = larger than 1 = positive exponent, move decimal 2 places = 8.453 x 102 2. Convert 3.21 x 10-5 = negative exponent = smaller than 1, move decimal...

CHEM 121 Module 1 Exam Questions and Answers - Portage Learning. Complete the two problems below: 1. Convert 1005.3 to exponential form and explain your answer. 2. Convert 4.87 x 10-6 to ordinary form and explain your answer. 1. Convert 1005.3 = larger than 1 = positive exponent, move decimal 3 places = 1.0053 x 103 2. Convert 4.87 x 10-6 =negative exponent =smaller than 1, move decimal 6 places = 0. Question 2 You may find the following resources helpful: Scientific Calculator (Links t...