Chem 1520 exam - Study guides, Class notes & Summaries
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Chem 1520 Exam 3 – Questions & Answers (100% Correct)
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Chem 1520 Exam 3 – Questions & Answers (100% Correct) 
Chem 1520 Exam 3 – Questions & Answers (100% Correct) 
 
a weak organic acid whose color differs from that of its conjugate base - ANSWER - acid-base indicator 
 
the color of an indicator changes over a specific, narrow ____ range, a range of about 2 units - ANSWER - pH 
 
in an acid-base titration, the concentration of an acid (or a base) is determined by _________________ the acid (or base) with a solution of a base (or acid) of a kno...
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Exam 3 - Chem 1520 Questions And Answers
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Exam 3 - Chem 1520 Questions And Answers 
acid-base indicator - ANS-a weak organic acid whose color differs from that of its conjugate base 
pH - ANS-the color of an indicator changes over a specific, narrow ____ range, a range of about 2 units 
neutralizing - ANS-in an acid-base titration, the concentration of an acid (or a base) is determined by 
_________________ the acid (or base) with a solution of a base (or acid) of a known concentration 
equivalence - ANS-The ______________ point of the...
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QSP EXAM 3: CHEM 1520 Q&A RATED A.
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QSP EXAM 3: CHEM 1520 Q&A RATED A.QSP EXAM 3: CHEM 1520 Q&A RATED A.QSP EXAM 3: CHEM 1520 Q&A RATED A.QSP EXAM 3: CHEM 1520 Q&A RATED A.QSP EXAM 3: CHEM 1520 Q&A RATED A.QSP EXAM 3: CHEM 1520 Q&A RATED A.QSP EXAM 3: CHEM 1520 Q&A RATED A.QSP EXAM 3: CHEM 1520 Q&A RATED A.QSP EXAM 3: CHEM 1520 Q&A RATED A.QSP EXAM 3: CHEM 1520 Q&A RATED A.QSP EXAM 3: CHEM 1520 Q&A RATED A.QSP EXAM 3: CHEM 1520 Q&A RATED A.
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Chem 1520 Exam: Types of Calculation Questions & Answers (100% Correct)
- Exam (elaborations) • 15 pages • 2023
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Chem 1520 Exam: Types of Calculation Questions & Answers (100% Correct) 
Chem 1520 Exam: Types of Calculation Questions & Answers (100% Correct) 
 
Calorimetry Calculations: 
 
1. 2.50 kJ of energy changes the temperature of a sample of lead by 8.52 degrees C. What is the mass of the sample? - ANSWER - Q = mcΔT 
m=Qc/Δt 
m = 2500/0.13(8.52) 
= 2.3×103 g 
 
2. 950.3 J of energy is removed from 28.5 g of water at 80.3 degrees C. What is the final temperature? - ANSWER - Q = mcΔT 
−950.3 = ...
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