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MATH 110 Module 4 Exam.| PORTGE LEARNING Module 4 Exam

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MATH 110 Module 4 Exam.| PORTGE LEARNING Module 4 Exam

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  • uploaded  11-03-2024
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MATH 110 – Module 1 (Book Exam) Limespring.com Questions 1-18

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MATH 110 – Module 1 (Book Exam) L Questions 1-18

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MATH 110 Module 1 Exam.| PORTGE LEARNING Module 1 Exam

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MATH 110 Module 1 Exam.| PORTGE LEARNING Module 1 Exam Define each of the following: a) Observation. When a study is conducted, "observation" is known as all the info gathered and/or observed for each element in the study. b) Element. In a study, the "element" is described as the individual and/or particular entry of the data set in which the data is being collected for. The data of the element will be collected, analyzed, and presented in a same manner to differentiate.

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MATH 110 Module 1 Exam.| PORTGE LEARNING Module 1 Exam

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MATH 110 Module 1 Exam.| PORTGE LEARNING Module 1 Exam Define each of the following: a) Observation. When a study is conducted, "observation" is known as all the info gathered and/or observed for each element in the study. b) Element. In a study, the "element" is described as the individual and/or particular entry of the data set in which the data is being collected for. The data of the element will be collected, analyzed, and presented in a same manner to differentiate.

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MATH 110 TEST 3- PORTAGE LEARNING

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MATH 110 TEST 3- PORTAGE LEARNING Suppose A and B are two events with probabilities: P(Ac )=.70,P(B)=.65,P(A∪B)=.80. Find the following: a) P(A∩B). For P(A∩B). Use P(A∪B)=P(A)+P(B)-P(A∩B) and rearrange to P(A∩B)=P(A)+P(B)-P(A∪B). But for this equation, we need P(A) which we can find by using P(A)=1-P(Ac ). So, P(A)=1-.70= .30. P(A∩B)=.30+.65-.80=.15.

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MATH 110 TEST 3- PORTAGE LEARNING

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MATH 110 TEST 3- PORTAGE LEARNING Suppose A and B are two events with probabilities: P(Ac )=.70,P(B)=.65,P(A∪B)=.80. Find the following: a) P(A∩B). For P(A∩B). Use P(A∪B)=P(A)+P(B)-P(A∩B) and rearrange to P(A∩B)=P(A)+P(B)-P(A∪B). But for this equation, we need P(A) which we can find by using P(A)=1-P(Ac ). So, P(A)=1-.70= .30. P(A∩B)=.30+.65-.80=.15. b) P(A). P(A) was found above as .30. c) P(Bc).

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CHAPTER 3 MATH 110| PORTAGE LEARNING

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CHAPTER 3 MATH 110| PORTAGE LEARNING Chapter 3 math 110 Exam Page 1 Suppose A and B are two events with probabilities: P(A)=.35,P(Bc )=.45,P(A∩B)=.25. Find the following: a) P(A∪B). P (AUB)=P(AP+P (B)-P(A⋂B) P(B∁) => P(B)=1-P(b∁)=1-0.45=0.55 P(AUB)=0.35+0.55-0.25=0.65

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MATH 110 MODULE 7 EXAM. | PORTAGE LEARNING

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MATH 110 MODULE 7 EXAM. | PORTAGE LEARNING Module 7 Exam Exam Page 1 a) Define the null and alternative hypothesis for the following. Also, explain what it would mean to make a Type I error and explain what it would mean to make a Type II error. The newspaper in a certain city had a circulation of 19,000 per day in 2010. You believe that the newspaper’s circulation is different than 19,000 today. Ho: u = 19000 H1: u ≠ 19000

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MATH 110 Module 2 Exam.| PORTGE LEARNING

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MATH 110 Module 2 Exam.| PORTGE LEARNING Module 2 Exam Exam Page 1 During an hour at a fast food restaurant, the following types of sandwiches are ordered: Cheeseburger Fish Cheeseburger Hamburger Fish Chicken Hamburger Cheeseburger Fish Hamburger Turkey Fish Chicken Chicken Fish Turkey Fish Hamburger Fish Cheeseburger Fish Cheeseburger Hamburger Fish Fish Cheeseburger Hamburger Fish Turkey Turkey Chicken Fish Chicken Cheeseburger Fish Turkey Fish Fish Hamburger Fish Fish Tur...

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