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Mark Scheme (Pre-Standardisation) Summer 2024 Pearson Edexcel in GCE History (8HI0/2F) Advanced Subsidiary Paper 2: Depth study Option 2F.1: India, c1914-48: the road to independence Option 2F.2: South Africa, 1948-94: from apartheid state to ‘rainbow nat
1 1–2 • Demonstrates surface level comprehension of the source material 
without analysis, selecting some material relevant to the question, but 
in the form of direct quotations or paraphrases. 
• Some relevant contextual knowledge is included, with limited linkage to 
the source material. 
• Evaluation of the source material is assertive with little if any 
substantiation. Concepts of utility may be addressed, but by making 
stereotypical judgements. 
2 3–5 • Demonstrates some unde...
- Exam (elaborations)
- • 31 pages •
1 1–2 • Demonstrates surface level comprehension of the source material 
without analysis, selecting some material relevant to the question, but 
in the form of direct quotations or paraphrases. 
• Some relevant contextual knowledge is included, with limited linkage to 
the source material. 
• Evaluation of the source material is assertive with little if any 
substantiation. Concepts of utility may be addressed, but by making 
stereotypical judgements. 
2 3–5 • Demonstrates some unde...
Mark Scheme (Results) Summer 2024 Pearson Edexcel In GCE History (8HI0/2G) Advanced Subsidiary Paper 2: Depth study Option 2G.1: The rise and fall of fascism in Italy, c1911–46 Option 2G.2: Spain, 1930–78: republicanism, Francoism and the re-establishment
1 1–2 • Demonstrates surface level comprehension of the source material 
without analysis, selecting some material relevant to the question, but 
in the form of direct quotations or paraphrases. 
• Some relevant contextual knowledge is included, with limited linkage to 
the source material. 
• Evaluation of the source material is assertive with little if any 
substantiation. Concepts of utility may be addressed, but by making 
stereotypical judgements. 
2 3–5 • Demonstrates some unde...
- Exam (elaborations)
- • 50 pages •
1 1–2 • Demonstrates surface level comprehension of the source material 
without analysis, selecting some material relevant to the question, but 
in the form of direct quotations or paraphrases. 
• Some relevant contextual knowledge is included, with limited linkage to 
the source material. 
• Evaluation of the source material is assertive with little if any 
substantiation. Concepts of utility may be addressed, but by making 
stereotypical judgements. 
2 3–5 • Demonstrates some unde...
Mark Scheme (Results) Summer 2024 Pearson Edexcel In GCE History (8HI0/2H) Advanced Subsidiary Paper 2: Depth study Option 2H.1: The USA, c1920–55: boom, bust and recovery Option 2H.2: The USA, 1955–92: conformity and challenge
1 1–2 • Demonstrates surface level comprehension of the source material 
without analysis, selecting some material relevant to the question, but 
in the form of direct quotations or paraphrases. 
• Some relevant contextual knowledge is included, with limited linkage to 
the source material. 
• Evaluation of the source material is assertive with little if any 
substantiation. Concepts of utility may be addressed, but by making 
stereotypical judgements. 
2 3–5 • Demonstrates some unde...
- Exam (elaborations)
- • 22 pages •
1 1–2 • Demonstrates surface level comprehension of the source material 
without analysis, selecting some material relevant to the question, but 
in the form of direct quotations or paraphrases. 
• Some relevant contextual knowledge is included, with limited linkage to 
the source material. 
• Evaluation of the source material is assertive with little if any 
substantiation. Concepts of utility may be addressed, but by making 
stereotypical judgements. 
2 3–5 • Demonstrates some unde...
Mark Scheme (Results) Summer 2024 Pearson Edexcel GCE In Geography (9GE0) Paper 3
1 AO1 (4 marks) 
Award 1 mark for explaining a key basic reason why TNCs 
benefit from globalisation and up to a further 3 marks for 
extending and developing that explanatory point up to a 
maximum of 4 marks. 
Also allow more than one basic reason for 1 mark each and 
extensions of those basic reasons for a 
For example: 
TNCs outsource to reduce (manufacturing) costs (1) because of 
cheaper labour overseas (1) and cheaper land overseas (1) and 
lower taxes and/or subsidies from governments (1...
- Exam (elaborations)
- • 21 pages •
1 AO1 (4 marks) 
Award 1 mark for explaining a key basic reason why TNCs 
benefit from globalisation and up to a further 3 marks for 
extending and developing that explanatory point up to a 
maximum of 4 marks. 
Also allow more than one basic reason for 1 mark each and 
extensions of those basic reasons for a 
For example: 
TNCs outsource to reduce (manufacturing) costs (1) because of 
cheaper labour overseas (1) and cheaper land overseas (1) and 
lower taxes and/or subsidies from governments (1...
Mark Scheme (Results) Summer 2024 Pearson Edexcel GCE In Geography (9GE0) Paper 2
1(a) AO1 (4 marks) 
Award 1 mark for a way in which globalisation has increased 
connections and flows between countries, with up to a further 3 marks 
for an explanation to a maximum of 4 marks. 
For example: 
• Globalisation has led to increased flow of commodities/goods (1) 
through the use of containerisation (1) which are intermodal 
allowing for greater speed (1) contributing to a shrinking world 
effect/time-space compression. (1) 
• Globalisation has also resulted in the increased sp...
- Exam (elaborations)
- • 39 pages •
1(a) AO1 (4 marks) 
Award 1 mark for a way in which globalisation has increased 
connections and flows between countries, with up to a further 3 marks 
for an explanation to a maximum of 4 marks. 
For example: 
• Globalisation has led to increased flow of commodities/goods (1) 
through the use of containerisation (1) which are intermodal 
allowing for greater speed (1) contributing to a shrinking world 
effect/time-space compression. (1) 
• Globalisation has also resulted in the increased sp...
Mark Scheme (Results) Summer 2024 Pearson Edexcel GCE In Geography (9GE0) Paper 1
1 (a) 
(i) 
(ii) 
AO3 (4 marks) 
Method (1) 
Sum the 11 death totals 21,942 +689 + etc = 44327 then divide by 
11 = 4029.727 
Answer = 4029.7 (to 1 decimal place) (1) 
Method (1) 
List the 11 death totals in ascending order: 
 ,535 9,624 21,942 
and identify the middle (6th) number 
Answer = 1297 (1)
- Exam (elaborations)
- • 39 pages •
1 (a) 
(i) 
(ii) 
AO3 (4 marks) 
Method (1) 
Sum the 11 death totals 21,942 +689 + etc = 44327 then divide by 
11 = 4029.727 
Answer = 4029.7 (to 1 decimal place) (1) 
Method (1) 
List the 11 death totals in ascending order: 
 ,535 9,624 21,942 
and identify the middle (6th) number 
Answer = 1297 (1)
Mark Scheme (Results) Summer 2024 Pearson Edexcel GCE In French (9FR0) Paper 03 Speaking
Task 1 − Discussion on a theme 
Three mark grids are applied to task 1: 
● knowledge and understanding of society and culture (AO4) 
● accuracy and range of language (AO3) 
● interaction (AO1) 
The knowledge and understanding of society and culture mark grid assesses the 
students’ ability to communicate information about and demonstrate appreciation of 
different aspects of culture and society related to the countries/communities where the 
language is spoken. They are also assessed o...
- Exam (elaborations)
- • 33 pages •
Task 1 − Discussion on a theme 
Three mark grids are applied to task 1: 
● knowledge and understanding of society and culture (AO4) 
● accuracy and range of language (AO3) 
● interaction (AO1) 
The knowledge and understanding of society and culture mark grid assesses the 
students’ ability to communicate information about and demonstrate appreciation of 
different aspects of culture and society related to the countries/communities where the 
language is spoken. They are also assessed o...
Mark Scheme (Results) Summer 2024 Pearson Edexcel GCE In A Level Further Mathematics (9FM0) Paper 4D Pure Mathematics
1(a) (i) x = 10 B1 1.1b 
(ii) y = 7 B1 1.1b 
(2) 
(b) 32 B1 1.1b 
(1) 
(c) Cut B1 1.1b 
(1) 
(d) SCDFET B1 1.1b 
(1) 
(e) Use of max-flow min-cut theorem 
Identification of cut through AE, DE, DT, EF and FT 
Value of flow = 36 
It follows that flow is maximal
- Exam (elaborations)
- • 23 pages •
1(a) (i) x = 10 B1 1.1b 
(ii) y = 7 B1 1.1b 
(2) 
(b) 32 B1 1.1b 
(1) 
(c) Cut B1 1.1b 
(1) 
(d) SCDFET B1 1.1b 
(1) 
(e) Use of max-flow min-cut theorem 
Identification of cut through AE, DE, DT, EF and FT 
Value of flow = 36 
It follows that flow is maximal
Mark Scheme (Results) Summer 2024 Pearson Edexcel GCE In A Level Further Mathematics (9FM0) Paper 4C Further Mechanics 2
1a 
( )3 
96 
d 1d ... 
3 5 
t v v 
t 
= = 
+ 
 
 M1 2.1 
96 ( )2 ( ) 
2 3 3 5 
C v 
t 
 − + = 
 + 
A1 1.1b 
Use limits v t = = 0, 0 M1 1.1b 
( )2 2 2 ( ) ( ) 
 
6 5 6 3 5 3 5 25 
v 
t t 
 = − = − 
 + + 
* A1* 2.2a 
(4) 
1b 
16 ( 0.64) 
25 
t v → → = B1ft 2.2a 
(1) 
1c 
( )2 
16 16 1 
1d d 
25 3 5 3 5 
x t x rt s 
t t 
= − = + 
 + + M1 2.1 
16 16 ( ) ( ) 
25 3 3 5 
x t D 
t 
= + + 
+ 
A1ft 1.1b 
( ) 
2 0 
16 16 
25 3 3 5 
x t 
t ...
- Exam (elaborations)
- • 20 pages •
1a 
( )3 
96 
d 1d ... 
3 5 
t v v 
t 
= = 
+ 
 
 M1 2.1 
96 ( )2 ( ) 
2 3 3 5 
C v 
t 
 − + = 
 + 
A1 1.1b 
Use limits v t = = 0, 0 M1 1.1b 
( )2 2 2 ( ) ( ) 
 
6 5 6 3 5 3 5 25 
v 
t t 
 = − = − 
 + + 
* A1* 2.2a 
(4) 
1b 
16 ( 0.64) 
25 
t v → → = B1ft 2.2a 
(1) 
1c 
( )2 
16 16 1 
1d d 
25 3 5 3 5 
x t x rt s 
t t 
= − = + 
 + + M1 2.1 
16 16 ( ) ( ) 
25 3 3 5 
x t D 
t 
= + + 
+ 
A1ft 1.1b 
( ) 
2 0 
16 16 
25 3 3 5 
x t 
t ...
Mark Scheme (Results) Summer 2024 Pearson Edexcel GCE In A Level Further Mathematics (9FM0) Paper 4B Further Statistics
1(a) 338.83 
4.52 
b − 
= = −74.96... M1 3.3 
626 22.47 
" " 
10 10 
a b = − = 231.04..... M1 1.1b 
t h − = + − 40 "231.04..." " "74.96..." ( ) dM1 3.1a 
t h = − 271.04... 74.96... A1 1.1b 
(4) 
(b) Residual = 47 "271.04..." "74.96..." 9 − − ( ) M1 3.4 
= 0.8466… A1 1.1b 
(2) 
(c) 
RSS = .4 6262 ( 338.83 338.83 )2 2 ( ) 
10 4.52 4.52 
 − − 
 − − = − M1 1.1b 
= 90.89…[s2] A1 1.1b 
(2) 
(...
- Exam (elaborations)
- • 16 pages •
1(a) 338.83 
4.52 
b − 
= = −74.96... M1 3.3 
626 22.47 
" " 
10 10 
a b = − = 231.04..... M1 1.1b 
t h − = + − 40 "231.04..." " "74.96..." ( ) dM1 3.1a 
t h = − 271.04... 74.96... A1 1.1b 
(4) 
(b) Residual = 47 "271.04..." "74.96..." 9 − − ( ) M1 3.4 
= 0.8466… A1 1.1b 
(2) 
(c) 
RSS = .4 6262 ( 338.83 338.83 )2 2 ( ) 
10 4.52 4.52 
 − − 
 − − = − M1 1.1b 
= 90.89…[s2] A1 1.1b 
(2) 
(...