Summary
Summary Graad 12 Kwartaal 1 + 2 Fisika opsommings (en graad 11 werk vir Junie eksamen)
- Course
- Fisiese Wetenskap
- Institution
- 12th Grade
Kwartaal een en twee werk opgesom van fisiese wetenskappe vraestel 1
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- 13 m.g
0.4 m.S-1 4. 7 m.3-
B B
A A SKALAAR
2kg 2k9
1k9 1179
Fres= ma
2mv 2
Ein =
P mv
=
P
VE KTOR DIAGRAM A F net= ELASTIES ONE LAS TIES
t
Kg.
=
m. S-1
pf pi R
=
P -
·
Netto Kragi's die TEMPO ⑧ ⑧ ⑧
-
9,4 1
= -
0,4 33
waarteen momentum
-Vektor rigting
-
4,4
=
-
0,47 9 v er and er
· Die in
produk van
P voorwerp se mass a
en snelheid
Ios m e ka a r
~as aan
*e aar
Pb pe
va n
nie ~ e r vo r m
ve r
o
vo r m
Ex Ek na E
k vo o r Ek na
nin
vo o r =
Resep vir
p vektor
diagramme
VERTOR
work met p pG- pi
=
DIAGRAMME
-
SOORTY
ignoreer pf BIND
·
Bro",e
-
Begin tussen
met
grootste waarde
pen pi
·
Voltooi
pf /kop-en-stert
LOS LOS
Die totale liniere momentum
~ A S
in geslote
n
sisteem bly ↳0S
Konstant.
⑧ ⑧ ⑧ ⑧
pvoor
=
pna
⑧ ⑧ ⑧
Momentum word altyd behou,
nie Saak dit
of elasties m, vi+mz Vi m,vf M2V +
+
maak
ve
is nie
of m, +
m2 mivf m2 Vf
+
LOS v AS VOOR IV A
205:
pvoor - 10 n a
!
-
= ⑧ ⑧
mi Vi+(mz Vi M,Vf m2Vf
+
vi+ We
vf
⑧
me 2
⑧
m, m2
+
m1
GESLOTE
SISTEEM
⑧
eksterne net to v AS
↳ Sisteem Wat geen ↳OS
Krag underwind nie, dus Slegs
interne is
anwesig. m2,V,
a mivi
kragte V6
+
re1 on 2
+
, 1. Impuls is die verandering in
p
-
1
4 m. 5 -1
7 m.S
F - F
Impuls
=
I
P
M 8.
P ↑
4 kg & 4 kg
muf -mvi
=
L
S
Albei voel Kg. m.3"
=
N.S
1mpulS= F t dieself de impuls
2.
Impus isde Produce in99 en die
zyd
Produk die
va n netto Krag en tyd F net t
Impuls
wa a r in die Krag werksaam is
·vektor
3. Impuls -
momentum begin sel
· eenheid N.S.
Fret t
P
=
F/N
10
asso
enation
3 E FOR E
5
i n c re m e n t " re p e r i s
0
t/S Onthou die minus as
4 ⑧
righting verandering
gaar
AFTER
oppervlak= impuls
I
I
0pV
=
2 b. h Fret z =
mr -
inve
I
m
=
v6-vil
=
2 8 18
Slegs een voorwerp se massa!
MOMENTUM
=
40 Die Einste
N.S voorwerp wie
Sekrag botsing
inlighting vo o r en na die
bereken word. Al die Vue mass as
se gebruik
vf-vi
=
Impuls m
"
NEWTON 3 "TRIEK
40 2 IMPULS
vf c
=
-
As jy die I vw Se krag net, het
jy
In
lighting tydens botsings
in die ander een massa gebruik
elk geval ook. Slegs1 vn
se
-
vf 20
=
m.g
, 2
g 9,8m.5
- -
=
-
1 2
+
H
2.
=
I
m.g
+
v 0
+
I max hoogtel H:k i e s som Serigting, dan die verwysing spunt,
sinne dit
as of
y die t we e
are the
een
Stebewegine" inan e
i
+
-
2
...g 4,8m.g
=
-
-
x
versit 8
Ther !
ve r w. punt
E
er
O
ins V
s
+
-
V
verplasing
Posse
met
0
Vi -
as Saam die son
serigting wo r k
y
=
as te e n die som serigting we r k
one
minnesse
begin
V
dieselfde as
-
~
-
2
y
= -
9,8m.5
9,8
9:a s afwaar ts positief is
-
9
gekies
=
want
het
verby
-
y
=
g
-
=
4,8
die begin punt geval
-
as opwaarts positiefgekies is
- a,8
"as
y
=
ve
x v 0 2
=
vi = T N V -
I
V + 9
-
Raaklyn positief: V
Racklyn negatief:V-
+ 9
x V 0
=
9
:a
! V
-
=
5 M and is sad Mond is negatief:a
-
vi 5
=
.
⑧. .
vi 5 =
Vf -
=
5 vf 10
=
8
vf 0 =
L A A T VAL
GROND GROND
x
x I
RAAKLYN =
MOND]1E a
=
5
G 5
V
C
-
18
-
5
m"- 8.
&
⑧
⑧
I a -
9,8
m.3-2
Raaklyn negatief V
Raaklyn positiefv t
-
n Mond is happy:a t Mond positief:a t
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