Examen
Elevator Mechanic Exam 2024 Questions and Answers (Verified Answers by Expert).
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Liberty University
Elevator Mechanic Exam 2024 Questions and Answers (Verified Answers by Expert).
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13 de agosto de 2024
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2024/2025
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Institución
Liberty University
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Elevator Mechanic
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Elevator Mechanic Exam 2024 Questions and
Answers (Verified Answers by Expert)
A .Latching .relay: .Used .for .call .registration,direction .selection .or .as .selector .relays
Two .types .are: .Set/Rest .are .electrical .and .Mechanical .Latching .relays .
Need .to .know .latching .relay .symbol, .Its .a .box .with .shaded .triangle .in .lower .right .hand .corner. .- .
(correct .answer) .-Which .relay .do .you .need .to .Order
710 .Pg, .7
RPM .= .60 .∙ .ƒ .÷ .P÷2 .=
Step .1. .60 .x .Frequency .(Hz.) .= .
Step .2. .Poles .÷ .2 .=
Take .answer .1 .and .÷ .by .answer .2 .= .- .(correct .answer) .-Know .the .formula .for .RPM
435 .Pg. .5
If .you .are .referring .to .a .megohm .meter, .it .is .a .test .of .the .insulation .properties .of .such .things .as .ele
ctric .wiring, .motor .windings .and .high .power .antenna .mounts. .
We .use .a ."megger" .or ."meg .out" .electrical .wiring .and .equipment .to .see .if .it .is .shorted .to .ground .o
r .the .frame .in .any .way. .
The .megger .uses .much .higher .voltages .to .check .resistance .than .a .normal .Volt-ohm .meter. .
,Minimum .resistance .is .1 .Meg .Ohm .- .(correct .answer) .-Know .what .a .Megger .is .and .what .it .does
636 .Pg. .13
(1) .A .parallel .connection. .
(2) .A .resistive .element .placed .across .the .terminals .of .an .armature .to .bypass .a .portion .of .the .curren
t. .
(3) .A .flexible .electrical .conductor .designed .to .conduct .current .around .the .mechanical .joint .between
.two .conductors. .(4) .The .resistive .element .(Usually .of .very .low .resistance) .used .in .parallel .with .a .DC
.ammeter .movement .to .bypass .a .calibrated .portion .of .the .total .circuit .current. .- .(correct .answer) .-
Shunt .Overloads
425 .All .Pages
Bad .Ground .- .(correct .answer) .-You .are .using .a .Temp .Run .Box .and .you .get .shocked! .Why!
520 .Pg. .4
The .bridle .hitch .can .consist .of .two,three, .or .four .single .hitches .(fig. .3-
22), .used .together .to .form .a .bridle .hitch .for .hoisting .an .object
A .sling .with .two .legs .used .to .lift .a .1,000 .pound .object .will .have .500 .pounds .of .the .load .on .each .le
g .when .the .sling .angle .is .90 .degrees. .The .load .stress .on .each .leg .increases .as .the .angle .decreases; .
and .if .the .sling .angle .was .30 .degrees .lifting .the .same .1,000 .pound .object, .the .load .will .be .1,000 .po
unds .on .each .leg. .Try .to .keep .all .sling .angles .greater .than .45 .degrees; .sling .angles .approaching .30 .
degrees .are .considered .extremely .hazardous .and .must .be .avoided .at .all .cost. .- .(correct .answer) .-
Bridal .Hitch
128 .Pg .17
Scaffolding .should .be .tied .to .the .structure .using
#9 .wire .or .tie-in .devices. .The .first .vertical .tie
should .be .at .the .maximum .height .of .4 .times .the
narrowest .base .dimension. .Additional .ties .are .not
,to .exceed .26' .vertically. .Maximum .horizontal
distance .between .ties .is .not .to .exceed .30'. .- .(correct .answer) .-
Scaffolding, .You .have .32' .of .rise, .you .are .using .3x5 .scaffolding. .Where .will .the .tie .off .points .be .?
140 .PG. .287-288
Counterweights .
(Typically) .are .hung .to .counter .balance .the .weight .of .the .car .PLUS .40% .of .Capacity .Load. .- .
(correct .answer) .-How .much .should .Counterweight .way?
240 .Pg. .14
Note: .We .do .not .use .wire .smaller .than .#20 .in .travelling .cables .and .#24 .outside .travelers.
Largest .wires .are .feeders .to .Hoist ./Pump .motor
We .always .have .10 .% .spares
10% .of .52 .= .5.2
On .a .calculator .Multiply .the .percent .10 .by .the .number .you .have .and .÷ .by .100
10 .X .52 .÷ .100 .= .5.2 .- .(correct .answer) .-Pulling .Spare .Wires .(Example) .10% .of .52 .Wires
515 .Pg.26
The .correct .lube .must .be .used .on .chains. .- .(correct .answer) .-
The .freight .door .motor .is .spinning .but .the .door .wont .move, .Why?
535 .Pg. .9
Lula: .Limited .use/Limited .Access .(Example .Wheelchair .Lifts)
Max .Rise .25'
Max .Speed .30 .Ft/Min
Max .Capacity .1400 .Lbs.
Max .Platform .Area .18 .Sq/Ft.
, Residential .Elevator:
Max .Rise .50 .'
Max .Speed .40 .Ft/min
Max .Capacity .940 .Lbs.
Max .Platform .Area .19 .Sq/Ft .
840 .Pg .2
Dumbwaiters:
Platform .limited .to .9 .Sq/Ft
Inside .height .is .limited .to .no .more .than .4 .Feet
Capacity .is .limited .to .500Lbs
No .Riders .- .(correct .answer) .-Read .Lula .and .Dumb .waiters
545 .Pg .1
You .never .get .on .top .and .you .work .only .partially .in .with .the .main .line .OFF .- .(correct .answer) .-
If .you .get .on .top .of .Dumbwaiter .what .must .be .done?
545 .Pg .14
Notes:(Pi) .π .is .3.1416 .and .231 .Cubic .inches .to .the .Gallon
Area:
Remember .to .÷ .6" .÷ .2 .= .3 .to .get .Radius
Area .= .π∙ .r²
Area .= .3.1416 .x .3 .x .3 .= .28.27 .inches .or .3.146 .x .9 .= .28.27
Volume
Multiple .are .times .height .to .solve .for .Volume
V .= .A∙H