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Examen

NCSSM placement test Exam with questions and answers

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Subido en
25-02-2025
Escrito en
2024/2025

NCSSM placement test Exam with questions and answers

Institución
Math Placement
Grado
Math Placement










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Institución
Math Placement
Grado
Math Placement

Información del documento

Subido en
25 de febrero de 2025
Número de páginas
30
Escrito en
2024/2025
Tipo
Examen
Contiene
Preguntas y respuestas

Temas

Vista previa del contenido

NCSSM placement test Exam with questions
and answers.


Tangent - (correct answer) - intersects a circle in only 1 place.
gf gf gf gf gfgf gf gf gf gf gf gf




Secant - (correct answer) - intersects a circle in 2 places.
gf gf gf gf gfgf gf gf gf gf gf




Intersection of a tangent and a radius - (correct answer) - form right angles when they intersect.
gf gf gf gf gf gf gf gf gf gf gfgf gf gf gf gf gf




Equation of a circle - (correct answer) - x minus h squared plus y minus k squared equals radius squared.
gf gf gf gf gf gf gf gfgf gf gf gf gf gf gf gf gf gf gf gf




Circumference of a circle - (correct answer) - 2 times pi times radius or pi times diameter.
gf gf gf gf gf gf gf gfgf gf gf gf gf gf gf gf gf




Area of a circle - (correct answer) - pi times radius squared.
gf gf gf gf gf gf gf gfgf gf gf gf




Central angle - (correct answer) - is equal to its intercepted arc.
gf gf gf gf gf gfgf gf gf gf gf gf




Inscribed angle - (correct answer) - is equal to ½ its intercepted arc.
gf gf gf gf gf gfgf gf gf gf gf gf gf




Angle formed by 2 chords intersecting in a circle - (correct answer) -
gf gf gf gf gf gf gf gf gf gf gf gf




is equal to the sum of the arcs divided by 2.
gfgf gf gf gf gf gf gf gf gf gf gf




Angle formed by 2 secants - (correct answer) -
gf gf gf gf gf gf gf gf




is equal to the major arc minus the minor arc divided by 2.
gfgf gf gf gf gf gf gf gf gf gf gf gf gf




Angle formed by a secant and a tangent - (correct answer) -
gf gf gf gf gf gf gf gf gf gf gf




is equal to the major arc minus the minor arc divided by 2.
gfgf gf gf gf gf gf gf gf gf gf gf gf gf




Angle formed by two tangents - (correct answer) -
gf gf gf gf gf gf gf gf




is equal to the major arc minus the minor arc divided by 2.
gfgf gf gf gf gf gf gf gf gf gf gf gf gf




Lengths of 2 intersecting chords - (correct answer) -
gf gf gf gf gf gf gf gf




part of the first chord times the other part of the first chord equals a part of the second chord times the
gfgf gf gf gf gf gf gf gf gf gf gf gf gf gf gf gf gf gf gf gf gf gf gf




other part of the second chord.
gf gf gf gf gf




Lengths of an intersecting diameter and chord that meet at right angles (perpendicular) -
gf gf gf gf gf gf gf gf gf gf gf gf gf




(correct answer) -
gf gf gf




if a diameter meets a chord at a right angle (perpendicular), the diameter divides the chord into 2 equal
gfgf gf gf gf gf gf gf gf gf gf gf gf gf gf gf gf gf gf gf gf




parts.

,Lengths of 2 intersecting secants - (correct answer) -
gf gf gf gf gf gf gf gf




the whole length of the first secant times the outside length of the first secant equals the whole length
gfgf gf gf gf gf gf gf gf gf gf gf gf gf gf gf gf gf gf gf gf




of the second secant times the outside length of the second secant.
gf gf gf gf gf gf gf gf gf gf gf




Lengths of an instersecting secant and tangent - (correct answer) -
gf gf gf gf gf gf gf gf gf gf




the whole length of the first secant times the outside length of the first secant equals the length of the t
gfgf gf gf gf gf gf gf gf gf gf gf gf gf gf gf gf gf gf gf gf gf




angent squared. gf




Lengths of intersecting tangents - (correct answer) -
gf gf gf gf gf gf gf




Tangents to a circle sharing a common vertex are equal.
gfgf gf gf gf gf gf gf gf gf gf




Angles - (correct answer) -
gf gf gf gf




acute angles are less than 90 degrees. Right angles are 90 degrees. obtuse angles are between 90 and 1
gfgf gf gf gf gf gf gf gf gf gf gf gf gf gf gf gf gf gf gf




80 degrees. Straight angles are 180 degrees and reflex angles are greater than 180 degrees.
gf gf gf gf gf gf gf gf gf gf gf gf gf gf




Adjacent angles - (correct answer) - gf gf gf gf gf




share a common vertex, a common side, but not common interior points.
gfgf gf gf gf gf gf gf gf gf gf gf gf




Complementary angles - (correct answer) - 2 angles when added together that equal 90 degrees.gf gf gf gf gf gfgf gf gf gf gf gf gf gf gf




They do not have to be adjacent angles.
gf gf gf gf gf gf gf




Supplementary angles - (correct answer) - gf gf gf gf gf




2 angles when added together that equal 180 degrees.They do not have to be adjacent angles.
gfgf gf gf gf gf gf gf gf gf gf gf gf gf gf gf gf




Vertical angles - (correct answer) - vertical angles are congruent.
gf gf gf gf gf gfgf gf gf gf




Alternate interior angles - (correct answer) - alternate interior angles are congruent.
gf gf gf gf gf gf gfgf gf gf gf gf




Corresponding angles - (correct answer) - corresponding angles are congruent. gf gf gf gf gf gfgf gf gf gf




Sum of the angles in a triangle - (correct answer) - the 3 angles of a triangle add up to 180 degrees.
gf gf gf gf gf gf gf gf gf gf gfgf gf gf gf gf gf gf gf gf gf gf




Triangles classified by sides - (correct answer) - scalene triangles have no equal sides.
gf gf gf gf gf gf gf gfgf gf gf gf gf gf




isosceles triangles have at least 2 equal sides.
gf gf gf gf gf gf gf




equilateral triangles have 3 equal sides. gf gf gf gf gf




Triangles classified by angles - (correct answer) - acute triangles have 3 acute angles.
gf gf gf gf gf gf gf gfgf gf gf gf gf gf




right triangles have a 90 degree and 2 acute angles.
gf gf gf gf gf gf gf gf gf




obtuse triangles have an obtuse and 2 acute angles.
gf gf gf gf gf gf gf gf




Exterior angle of a triangle - (correct answer) -
gf gf gf gf gf gf gf gf




the exterior angle of a triangle equals the sum of the 2 opposite interior angles.
gfgf gf gf gf gf gf gf gf gf gf gf gf gf gf gf

, Isosceles triangles - (correct answer) - sides opposite congruent angles are congruent.
gf gf gf gf gf gfgf gf gf gf gf gf




angles opposite congruent sides are congruent.
gf gf gf gf gf




Triangle inequality theorem - (correct answer) - gf gf gf gf gf gf




the sum of 2 sides of a triangle must be greater than the 3rd side.
gfgf gf gf gf gf gf gf gf gf gf gf gf gf gf gf




Mid segment of a triangle - (correct answer) -
gf gf gf gf gf gf gf gf




a mid segment connects the midpoint of 2 sides of a triangle and is equal to ½ the side not containing th
gfgf gf gf gf gf gf gf gf gf gf gf gf gf gf gf gf gf gf gf gf gf gf




e 2 midpoints.
gf gf




Median - (correct answer) - bisects the opposite side into 2 congruent line segments.
gf gf gf gf gfgf gf gf gf gf gf gf gf gf




they meet in a triangle at a point called the centroid.
gf gf gf gf gf gf gf gf gf gf




median segments are in a ratio of 2 to 1. gf gf gf gf gf gf gf gf gf




Angle bisector - (correct answer) - bisects an angle into 2 congruent angles.
gf gf gf gf gf gfgf gf gf gf gf gf gf




they meet in a triangle at a point called the incenter.
gf gf gf gf gf gf gf gf gf gf




Altitude - (correct answer) - makes a right angle with the opposite side.
gf gf gf gf gfgf gf gf gf gf gf gf gf




they meet in a triangle at a point called the orthocenter.
gf gf gf gf gf gf gf gf gf gf




Perpendicular bisector - (correct answer) - gf gf gf gf gf




bisects and makes a right angle with a side of a triangle.They meet in a triangle at a point called the circ
gfgf gf gf gf gf gf gf gf gf gf gf gf gf gf gf gf gf gf gf gf gf gf




umcenter.

Similar triangles - (correct answer) - angles in similar (∼) triangles are congruent.
gf gf gf gf gf gfgf gf gf gf gf gf gf




sides are in proportion. gf gf gf




angles are in a proportion of one to one. (1:1)
gf gf gf gf gf gf gf gf gf




Proving triangles similar - (correct answer) -
gf gf gf gf gf gf




need only 2 angles to be congruent to probe 2 triangles similar.
gfgf gf gf gf gf gf gf gf gf gf gf gf




Proving triangles congruent - (correct answer) -
gf gf gf gf gf gf




can not be angle angle side (A.S.S.) or side side angle(S.S.A.).
gfgf gf gf gf gf gf gf gf gf gf gf




C.P.C.T.C. - (correct answer) - corresponding parts of congruent triangles are congruent.
gf gf gf gf gfgf gf gf gf gf gf gf




Pythagorean theorem - (correct answer) - a squared plus b squared equals c squared.
gf gf gf gf gf gfgf gf gf gf gf gf gf gf




the hypotenuse is always c.
gf gf gf gf




Proving right triangles congruent - (correct answer) - hypotenuse leg.
gf gf gf gf gf gf gf gfgf gf
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