QNT 501 EXAM 7.

QNT 501 EXAM 7.1. Solve for the unknown in the equation. 11A = 77 Divide both sides of the equation by the known factor to isolate the unknown value. 11 A 11 = 77 11 Now simplify. A= 7 Check. 11(7) = 77 77 = 77 Therefore, the solution of the equation is 7. 2. Solve for the unknown in the equation. B + 5 = 21 Subtract the known value from both sides of the equation to isolate the unknown value. B + 5 (5) = 21 (5) Now simplify. B = 16 Check. 16 + 5 = 21 21 = 21 Therefore, the solution of the equation is 16. 3. Solve for the unknown in the equation. X 53 = 27 Add the known value to both sides of the equation. X 53 + (53) = 27 + (53) Now simplify. X = 80 Check. 80 53 = 27 27 = 27 Therefore, the solution of the equation is 80. 4. Solve for the unknown in the equation. 5(X - 4) = 25 Eliminate the parentheses. 5X 20 + (20) = 25 + (20) Now simplify. 5X = 45 Divide both sides of the equation by the known factor to isolate the unknown value. 5X 5 = 45 5 Now simplify. X=9 Check the solution by substituting the answer in the original equation and verifying that a true statement result. The answer checks, so the solution of the equation is 9. 5. Many plans to save 1 14 of this salary each week . If his weekly salary is $ 434, find the amount he will save each week S= 1 1 ($31) S = $31 To check the solution, replace S with $31 and see if the sides are equal . ¿ $ 31 ¿ ? ¿ 1 ( $ 434 ) 14 ¿ $ 31 ¿ ? ¿ 1 ($ 434) 14 $31= $31 The answer checks Thus, Manny will save $31 each week. 6. Last week at a festival, a man sold 4 times as many tie dyed T- shirt as silk screened shirts. He sold 225 shirts altogether. How many tie-dyed shirts did he sell? Both the number of tie-dyed T-shirts and silk screened shirts are unknown, but choose one, silk-screened shirts, to be represented by a letter, N. Since the number of tie-dyed shirts is 4 times the number silk-screened shirts, represent the number of tie-dyed Tshirts as 4N. Tie-dyed shirts plus silk screened shirts equals total shirts. Write this information in symbols.