Number the RNA processing steps in order from 1-6 to generate mRNA transcript.
a) ___ 3' end cleavage and polyadenylation
b)__ binding of the U1 and U2 snRNPs
c)__ generating 7-methylguanosine at 5' end
d)__ mRNA export from the nucleus to cytosol
e) __ribozyme cleavage of the intron lariat
f...
BIOC 385 Exam 4 || very Flawless.
Number the RNA processing steps in order from 1-6 to generate mRNA transcript.
a) ___ 3' end cleavage and polyadenylation
b)__ binding of the U1 and U2 snRNPs
c)__ generating 7-methylguanosine at 5' end
d)__ mRNA export from the nucleus to cytosol
e) __ribozyme cleavage of the intron lariat
f)__ dissociation of RNA Pol 2 from DNA correct answers a) _4_ 3' end cleavage and
polyadenylation
b)_2_ binding of the U1 and U2 snRNPs
c)_1_ generating 7-methylguanosine at 5' end
d)_6_ mRNA export from the nucleus to cytosol
e) _3_ribozyme cleavage of the intron lariat
f)_5_ dissociation of RNA Pol 2 from DNA
Using the 9 nucleotide DNA base pairs, determine the mRNA and the protein sequences correct
answers 5' CCA UAC CGC 3'
Pro-Tyr-Arg
The RNA polymerase II C- terminal domain (CTD) consists of multiple repeats of the
heptapeptide sequence YSPTSPS, with the number of repeats varying among organisms.
Hyperphosphorylation of the CTD is a key step in the transition of the enzyme complex from the
initiation to the elongation stage. What does the term "hyperphosphorylation" mean in this
context?
A. The CTD is super-activated by the presence of multiple phosphate groups that synergize to
generate a negatively-charged protein domain that binds to the positively-charged DNA
backbone.
B.Serine, threonine, and tyrosine within one copy of the repeat all contain multiple
phosphorylations.
C. Multiple copies of the heptapeptide repeat are phosphorylated on all serines, leucines, and
tyrosines.
D. None of the serine, threonine, and tyrosine residues within one copy of the repeat are
phosphorylated.
E. The heptapeptide repeats are phosphorylated on some serine, th correct answers E. The
heptapeptide repeats are phosphorylated on some serine, threonine, and tyrosine residues
How does histone acetylation on lysine residues lead to transcriptional activation?
A. Histone acetylation adds another positive charge on the lysine side chain that weakens the
interaction between the histone tail and DNA to increase transcriptional activity and inhibits
binding sites for transcription factors.
,B. Histone acetylation adds another positive charge on the lysine side chain that weakens the
interaction between the histone tail and DNA to increase transcriptional activity and allows
binding sites for transcription factors
C. Histone acetylation adds another positive charge on the lysine side chain that strengthens the
interaction between the histone tail and DNA to increase transcriptional activity and allows more
binding sites for transcription factors
D. Histone acetylation removes the positive charge on the lysine side chain that weakens the
interaction between the histone tail and DNA to increase correct answers D. Histone acetylation
removes the positive charge on the lysine side chain that weakens the interaction between the
histone tail and DNA to increase transcriptional activity and allows binding sites for transcription
factors.
Number the protein synthesis steps in order from a to f to generate a polypeptide
a) __ peptide bond is formed between fMet-AA2
b) __ mRNA termination codon is in the A site
c)__ Tu-GTP/AA2-tRNA binds to A site
d)__ tRNA dissociated at the E site
e)__ fMet-tRNA binds to the P site
f)__ EF-GTP/GDP promoted translocation correct answers a) _3_ peptide bond is formed
between fMet-AA2
b) _6_ mRNA termination codon is in the A site
c)_2_ Tu-GTP/AA2-tRNA binds to A site
d)_5_ tRNA dissociated at the E site
e)_1_ fMet-tRNA binds to the P site
f)_4_ EF-GTP/GDP promoted translocation
Circle the underlined words describing the process of DNA synthesis and record the number.
(1) DNA Pol I / (2) DNA Pol III has 5' to 3' (3) endonuclease / (4) exonuclease activity to
complete DNA replication on the (5) leading / (6) lagging strand. The (7) trombone / (8) trumpet
model of DNA replication explains how a dimer of (9) DNA Pol II / (10) DNA Pol III is needed
for fork movement. DNA synthesis is 5' to 3' on the lagging strand and in (11) 3' to 5' / (12) 5' to
3' on the leading strand. correct answers 1) DNA pol 1
4) exonuclease
6) lagging
7) trombone
10) DNA Pol 3
12) 5' to 3'
What is the function of the resolvase enzyme in DNA recombination?
A. Base excision repair of DNA mutations.
B. Repair of Holliday junctions.
C. Adenylation of DNA parental strands.
D. Methylation of DNA daughter strands.
E. Mismatch repair of DNA mutations. correct answers B. Repair Holliday junction
What function do HAT and HDAC enzymes perform in the chromatin-modifying process?
, A. HAT acetylates and represses the gene. HDAC deacetylates and activates the gene.
B. HAT acetylates the gene and HDAC deacetylates the gene. Both repress the gene.
C. HAT enzymes methylate DNA, HDAC enzymes do not.
D. HAT acetylates the gene and HDAC deacetylates the gene. Both activate the gene.
E. HAT acetylates and activates the gene. HDAC deacetylates and represses the gene. correct
answers E. HAT acetylates and activates the gene. HDAC deacetylates and represses the gene.
Choose the correct statement about group I and group II introns.
A. With both splicing is initiated at the 5' splice site. group I attack results in the release of an
intron linear structure while group II attack results in the release of a lariat intron structure.
B. With both splicing is initiated at the 3' splice site. group I attack results in the release of an
intron lariat structure while group II attack results in the release of a linear intron structure.
C. With both splicing is initiated at the 3' splice site. group I attack results in the release of an
intron linear structure while group II attack results in the release of a lariat exon structure.
D. With both splicing is initiated at the 5' splice site. group I attack results in the release of an
intron lariat structure while group II attack results in the release of a linear intron structure.
E. With both splicing is initiated at the 3' splice site. g correct answers E. With both splicing is
initiated at the 3' splice site. group I attack results in the release of an intron linear structure while
group II attack results in the release of a lariat intron structure.
Match the bacterial DNA replication with its primary function
1) Clamp protein ___
2) Topoisomerase ___
3) DNA helicase ___
4) Single-strand binding protein ___
5) Primase ___
6) DNA A protein ___
a) Unwind the DNA at OriC
b) Unwind the DNA double helix
c) synthesize a RNA primer
d) maximize processivity of DNA Pol
e) Remove super coils ahead of fork
f) Prevent DNA strand reannealing correct answers 1) Clamp protein __d_
2) Topoisomerase __e_
3) DNA helicase __b_
4) Single-strand binding protein _f__
5) Primase __c_
6) DNA A protein __a_
Prokaryotic gene expression can be regulated by nutrient levels.
For each scenario, indicated if lac operon activity would be high or low
1) High glucose, low lactose
Les avantages d'acheter des résumés chez Stuvia:
Qualité garantie par les avis des clients
Les clients de Stuvia ont évalués plus de 700 000 résumés. C'est comme ça que vous savez que vous achetez les meilleurs documents.
L’achat facile et rapide
Vous pouvez payer rapidement avec iDeal, carte de crédit ou Stuvia-crédit pour les résumés. Il n'y a pas d'adhésion nécessaire.
Focus sur l’essentiel
Vos camarades écrivent eux-mêmes les notes d’étude, c’est pourquoi les documents sont toujours fiables et à jour. Cela garantit que vous arrivez rapidement au coeur du matériel.
Foire aux questions
Qu'est-ce que j'obtiens en achetant ce document ?
Vous obtenez un PDF, disponible immédiatement après votre achat. Le document acheté est accessible à tout moment, n'importe où et indéfiniment via votre profil.
Garantie de remboursement : comment ça marche ?
Notre garantie de satisfaction garantit que vous trouverez toujours un document d'étude qui vous convient. Vous remplissez un formulaire et notre équipe du service client s'occupe du reste.
Auprès de qui est-ce que j'achète ce résumé ?
Stuvia est une place de marché. Alors, vous n'achetez donc pas ce document chez nous, mais auprès du vendeur FullyFocus. Stuvia facilite les paiements au vendeur.
Est-ce que j'aurai un abonnement?
Non, vous n'achetez ce résumé que pour €12,57. Vous n'êtes lié à rien après votre achat.
