Chem 104 module 3 - Study guides, Class notes & Summaries

Portage Learning CHEM 104 Module 3 ExamQuestion 1 Show the calculation of the molar solubility (mol/L) of BaF2, Ksp of BaF2 = 1.0 x 10-6. Your Answer: Ksp = [Ba+2] [F-]2 = 1.0x10-6 1.0x10-6 = [s] [2s]2 1.0x10-6 = 4s3 s = 6.3x10-3 mol/L Question 2 Show the calculation of the Ksp of MnS if the solubility of MnS is 0.0001375 g/100 ml. MW of MnS = 87.01 MnS (s) Mn+2 (aq) + S-2 (aq) Your Answer: molar solubility of MnS = (0.0001375 g/100 ml) x (1000 mL) x (1 mol/87.01 g MnS) molar solubi...

Portage Learning CHEM 104 Module 3 Exam

Portage Learning / CHEM 104 / Module 1 to 6 Exams . MODULE 1 EXAM Question 1 Convert 845.3 to exponential form and explain your answer. 1. Convert 3.21 x 10-5 to ordinary form and explain your answer. 1. Convert 845.3 = larger than 1 = positive exponent, move decimal 2 places = 8.453 x 102 2. Convert 3.21 x 10-5 = negative exponent = smaller than 1, move decimal 5 places = 0. Question 2 Using the following information, do the conversions shown below, showing all work:...

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CHEM 104 MODULE 1 – MODULE 6 Exam Newest Questions and Answers (2023 / 2024) (Verified by Expert)

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CHEM 104 MODULE 1 LATEST Exam Questions And Answers Updated 2024/2025. Kinetics - the study of rates of reactions and how they are influenced by certain factors Influences Reactions Rates - Concentration, temperature, catalysts, surface area Temperature/Reaction Rate - Increase, higher temperature provides higher kinetic energy Catalyst/Reaction Rate - Increase, without being consumed Surface Area/Reaction Rate - Increase, increased surface area of particles increases reaction rate becau...