Math 110 module 3 exam - Study guides, Class notes & Summaries

MATH 110 Module 8 Exam Scored 100% - Portage Learning. Suppose we have independent random samples of size n1 = 615 and n2 = 505. The proportions of success in the two samples are p1= .53 and p2 = .45. Find the 90% confidence interval for the difference in the two population proportions. Answer the following questions: 1. Multiple choice: Which equation would you use to solve this problem? A. B. C. D. 2. List the values you would insert into that equation. 3. State the final answer to the problem...

MATH 110 Module 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 Exam (Latest-2023) / MATH110 Module 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 Exam: Introduction to Statistics: Portage Learning |100% Correct Q & A| MATH 110 Module 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 Exam (Latest-2023) / MATH110 Module 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 Exam: Introduction to Statistics: Portage Learning |100% Correct Q & A| MATH 110 Exam 1 to 10 Questions and Answers- Portage Learning

MATH 110 MODULE 3 EXAM Module 3 Exam Exam Page 1 Suppose A and B are two events with probabilities: P(Ac )=.40,P(B)=.45,P(A∪B)=.60. Find the following: a) P(A∩B). p(anb) = p(a) + p(b) - p(aub) p(a) = 1 - p(a^c) p(a^c) = 0.40 1 - 0.40 = 0.60 p(a) = 0.60 0.60 + 0.45 - 0.60 = 0.45 P(AnB) = 0.45 b) P(A). p(a) = 1 - p(a^c) p(a^c) = 0.40 1 - 0.40 = 0.60 P(A) = 0.60 c) P(Bc). p(b) = 1 - p(b^c) rearranged to find p(b^c) = 1 - p(b) 1 - 0.45 = 0....

MATH 110 Module 3 Exam (Latest update, ) / MATH110 Module 3 Exam/ MATH 110 Statistics Module 3 Exam/ MATH110 Statistics Module 3 Exam: Portage Learning (QUESTIONS & ANSWERS)

Find the answer to each of the following by first reducing the fractions as much as possible: a) P(660,3)= b) C(397,5)= Your Answer: A. P(n,r)= �!(�−�)! P(660,3)= 660!(660−3)! =286,190,520 B. C(n,r)=�!�!(�−�)! C=397!5!�(397−5)! C=80,129,109,159 a. b. Very good. Question 2

MATH 110 Module 3 Exam Questions and Answers – Portage Learning. Exam Page 1 Suppose A and B are two events with probabilities: P(Ac )=.40,P(B)=.45,P(A∪B)=.60. Find the following: a) P(A∩B). p(anb) = p(a) + p(b) - p(aub) p(a) = 1 - p(a^c) p(a^c) = 0.40 1 - 0.40 = 0.60 p(a) = 0.60 0.60 + 0.45 - 0.60 = 0.45 P(AnB) = 0.45 b) P(A). p(a) = 1 - p(a^c) p(a^c) = 0.40 1 - 0.40 = 0.60 P(A) = 0.60 c) P(Bc ). p(b) = 1 - p(b^c) rearranged to find p(b^c) = 1 - p(b) 1 - 0.45 = 0.55...

Portage Learning Math 110 Module 3 Exam 1. Find the answer to each of the following by first reducing the fractions as much as possible: a) P(412,3)= b) C(587,585)= 2. Suppose you are going to make a password that consists of 5 characters chosen from {1,2,4,9,d,i,k,m,n,w,z}.How many different passwords can you make if you cannot use any character more than once in each password? 3. Suppose A and B are two events with probabilities: P(A)=.35, P(Bc )=.45, P(A∩B)=.25. Find the followin...

MATH 110 Module 3 Exam Questions and Answers – Portage Learning. Exam Page 1 Suppose A and B are two events with probabilities: P(Ac )=.40,P(B)=.45,P(A∪B)=.60. Find the following: a) P(A∩B). p(anb) = p(a) + p(b) - p(aub) p(a) = 1 - p(a^c) p(a^c) = 0.40 1 - 0.40 = 0.60 p(a) = 0.60 0.60 + 0.45 - 0.60 = 0.45 P(AnB) = 0.45 b) P(A). p(a) = 1 - p(a^c) p(a^c) = 0.40 1 - 0.40 = 0.60 P(A) = 0.60 c) P(Bc ). p(b) = 1 - p(b^c) rearranged to find p(b^c) = 1 - p(b) 1 - 0.45 = 0.55...

MATH 110 Module 3 Exam Questions and Answers – Portage Learning. Exam Page 1 Suppose A and B are two events with probabilities: P(Ac )=.40,P(B)=.45,P(A∪B)=.60. Find the following: a) P(A∩B). p(anb) = p(a) + p(b) - p(aub) p(a) = 1 - p(a^c) p(a^c) = 0.40 1 - 0.40 = 0.60 p(a) = 0.60 0.60 + 0.45 - 0.60 = 0.45 P(AnB) = 0.45 b) P(A). p(a) = 1 - p(a^c) p(a^c) = 0.40 1 - 0.40 = 0.60 P(A) = 0.60 c) P(Bc ). p(b) = 1 - p(b^c) rearranged to find p(b^c) = 1 - p(b) 1 - 0.45 = 0.55...

MATH110 MODULE 3 EXAM | MATH 110 MODULE 3EXAM QUESTIONS AND ANSWERS- PORTAGE LEARNING