Chem 104 module 5 - Study guides, Class notes & Summaries
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CHEM 104 Module 1, 2, 3, 4, 5, 6 Exam (Latest-2023)/ CHEM104 Module 1, 2, 3, 4, 5, 6 Exam: General Chemistry: Portage Learning |100% Verified and Correct Q & A|
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CHEM 104 Module 1, 2, 3, 4, 5, 6 Exam (Latest-2023)/ CHEM104 Module 1, 2, 3, 4, 5, 6 Exam: General Chemistry: Portage Learning |100% Verified and Correct Q & A|
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CHEM 104 Module 1, 2, 3, 4, 5, 6 Exam (Latest update, 2023-2024)/ CHEM104 Module 1, 2, 3, 4, 5, 6 Exam: General Chemistry: Portage Learning (QUESTIONS & ANSWERS)
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CHEM 104 Module 1, 2, 3, 4, 5, 6 Exam (Latest update, )/ CHEM104 Module 1, 2, 3, 4, 5, 6 Exam: General Chemistry: Portage Learning (QUESTIONS & ANSWERS) 
CHEM 104 General Chemistry Module 1, 2, 3, 4, 5, 6 Exam (Latest update, )/ CHEM104 General Chemistry Module 1, 2, 3, 4, 5, 6 Exam/ CHEM 104 Module 1 to 6 Exam : Portage Learning (QUESTIONS & ANSWERS) 
CHEM 104 Chemistry Module 1, 2, 3, 4, 5, 6 Exam (Latest update, )/ CHEM104 Chemistry Module 1, 2, 3, 4, 5, 6 Exam/ CHEM104 Module 1 to 6 Exam...
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CHEM 104 MODULE 1 Exam Questions And Answers Updated 2024/2025 | 100% Correct.
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CHEM 104 MODULE 1 Exam Questions And Answers Updated 2024/2025 | 100% Correct. Kinetics - the study of rates of reactions and how they are 
influenced by certain factors 
Influences Reactions Rates - Concentration, temperature, 
catalysts, surface area 
Temperature/Reaction Rate - Increase, higher temperature 
provides higher kinetic energy 
Catalyst/Reaction Rate - Increase, without being consumed 
Surface Area/Reaction Rate - Increase, increased surface area 
of particles increases reaction ra...
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CHEM 104 Module 1, 2, 3, 4, 5, 6 Exam (Latest-2023)/ CHEM104 Module 1, 2, 3, 4, 5, 6 Exam: General Chemistry: Portage Learning |100% Correct Q & A|
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CHEM 104 Module 1 Exam, CHEM 104 Module 2 Exam, CHEM 104 Module 3 Exam, CHEM 104 Module 4 Exam, CHEM 104 Module 5 Exam, CHEM 104 Module 6 Exam (Latest-2023): Portage Learning |100% Correct Q & A| 
 
CHEM104 Module 1 Exam, CHEM104 Module 2 Exam, CHEM104 Module 3 Exam, CHEM 104 Module 4 Exam, CHEM 104 Module 5 Exam, CHEM 104 Module 6 Exam (Latest-2023): Portage Learning |100% Correct Q & A| 
 
CHEM 104 Module 1, 2, 3, 4, 5, 6 Exam (Latest-2023)/ CHEM104 Module 1, 2, 3, 4, 5, 6 Exam: General Chemis...
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CHEM 104 General Chemistry Module 1, 2, 3, 4, 5, 6 Exam (Latest-2023)/ CHEM104 General Chemistry Module 1, 2, 3, 4, 5, 6 Exam/ CHEM 104 Module 1 to 6 Exam : Portage Learning |100% Correct Q & A|
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CHEM 104 Module 1 Exam, CHEM 104 Module 2 Exam, CHEM 104 Module 3 Exam, CHEM 104 Module 4 Exam, CHEM 104 Module 5 Exam, CHEM 104 Module 6 Exam (Latest-2023): Portage Learning |100% Correct Q & A| 
 
CHEM104 Module 1 Exam, CHEM104 Module 2 Exam, CHEM104 Module 3 Exam, CHEM 104 Module 4 Exam, CHEM 104 Module 5 Exam, CHEM 104 Module 6 Exam (Latest-2023): Portage Learning |100% Correct Q & A| 
 
CHEM 104 Module 1, 2, 3, 4, 5, 6 Exam (Latest-2023)/ CHEM104 Module 1, 2, 3, 4, 5, 6 Exam: General Chemis...
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Chem 104 - Module 5 review with complete solution
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Chem 104 - Module 5 review with complete solution
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Portage Learning CHEM 104 Module 4 Exam
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Portage Learning CHEM 104 Module 4 Exam.Question 1 
For the cell described by the following cell diagram. 
Cr (s) | Cr+3 (aq, 1 M) || Al+3 (aq, 1 M) | Al (s) 
Al+3 + 3e- → Al E0 = - 1.66 v 
Cr+3 + 3e- → Cr E0 = - 0.73 v 
(1) The anode half reaction is 
(2) The cathode half reaction is 
(3) The overall cell reaction is 
(4) Show the calculation for the total cell potential 
(5) State and explain whether the cell is voltaic or electrolytic 
Your Answer: 
1) Cr (s) → Cr+3 (aq) + 3e- 
2) Al+3 ...
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Portage Learning CHEM 104 Module 4 Exam
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Portage Learning CHEM 104 Module 4 ExamQuestion 1 
For the cell described by the following cell diagram. 
Cr (s) | Cr+3 (aq, 1 M) || Al+3 (aq, 1 M) | Al (s) 
Al+3 + 3e- → Al E0 = - 1.66 v 
Cr+3 + 3e- → Cr E0 = - 0.73 v 
(1) The anode half reaction is 
(2) The cathode half reaction is 
(3) The overall cell reaction is 
(4) Show the calculation for the total cell potential 
(5) State and explain whether the cell is voltaic or electrolytic 
Your Answer: 
1) Cr (s) → Cr+3 (aq) + 3e- 
2) Al+3 (...
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Chem 104 - Module 5 review With correct scholarly solution
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Chem 104 - Module 5 review With correct scholarly solution
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Portage Learning CHEM 104 Module 3 Exam
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Portage Learning CHEM 104 Module 3 ExamQuestion 1 
Show the calculation of the molar solubility (mol/L) of BaF2, Ksp of BaF2 = 1.0 x 10-6. 
Your Answer: 
Ksp = [Ba+2] [F-]2 = 1.0x10-6 
1.0x10-6 = [s] [2s]2 
1.0x10-6 = 4s3 
s = 6.3x10-3 mol/L 
Question 2 
Show the calculation of the Ksp of MnS if the solubility of MnS is 0.0001375 g/100 ml. 
MW of MnS = 87.01 
MnS (s) Mn+2 (aq) + S-2 (aq) 
Your Answer: 
molar solubility of MnS = (0.0001375 g/100 ml) x (1000 mL) x (1 mol/87.01 g MnS) 
molar solubi...
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