Chem 120 week t - Study guides, Class notes & Summaries

CHEM 120 WEEK 7 DISCUSSION QUESTIONS WITH ANSWERS CHEM 120 Week 7 DQ 1 – Carbohydrate, Lipid, and Protein Structures Carbohydrates, lipids, and proteins! Take a look around your home. Describe an example of a carbohydrate, lipid, and/or protein found in your home. Let’s see how many different examples can be described. CHEM-120 Week 7 DQ 2 – Nucleic Acid Structure and Flow of Genetic Information In the news, we often hear examples of how DNA or the transfer of genetic information ...

CHEM 120 Week 8 Final Exam A+ GRADED 6. (TCO 6) A gas at a temperature of 95 degrees C occupies a volume of 165 mL. Assuming constant pressure, determine the volume at 25 degrees C. Show your work. (Points : 5) Using Charles’ Law, (V1/T1) = (V2/T2). First, convert temperature to KELVIN (T1 = t1 +273) Thus, T1 = 95 + 273 = 368. We have V1 (165 mL) & T2 = (25 + 273) = 298. V2 = (V1*T2)/T1 = (165 mL*298)/368 = 133.6 mL. 7. (TCO 6) A sample of helium gas occupies 1021 mL at 719 mmHg. Fo...

Mini-Cog - ANSWER-This consists of 3-item recall and Clock-Drawing Test (CDT). and assists nurses with early assessment of cognitive problems problems like language comprehension, visual-motor skills and executive function, and recall in a less stressful way as it can be done in 5 minutes or less. Confusion Assessment Method (CAM) - ANSWER-This tool helps the nurse quickly identify delirium. Nurses - ANSWER-Who are in key positions to provide disease prevention health promotion, promote po...

CHEM 120 FINAL EXAM – WEEK 8# PAGE 2 Question: (TCO 8) 35.0 mL of 0.25 M NaOH is neutralized by 23.6 mL of an HCl solution. The molarity of the HCl solution is (show your work): Question: (TCO 1) How many mL are in 3.5 pints? Show your work. Question: (TCO 3) What is the name of the following compound: Zn3P2? Question: (TCO 3) What is the name of the following compound: AgNO3? Question: (TCO 6) Calculate the pressure, in atmospheres, of 2.78 mol CO(g) in a 4.25 L tank at 51 degrees C. ...

CHEM 120 FINAL EXAM 6. (TCO 6) A gas at a temperature of 95 degrees C occupies a volume of 165 mL. Assuming constant pressure, determine the volume at 25 degrees C. Show your work. (Points : 5) 7. (TCO 6) A sample of helium gas occupies 1021 mL at 719 mmHg. For a gas sample at constant temperature, determine the volume of helium at 745 mmHg. Show your work. (Points : 5) 8. (TCO 12) If one strand of a DNA double helix has the sequence T T A G C G A C G C, what is the sequenc...

CHEM120 Week 1 to Week 7 Quizzes (Latest-2022)/ CHEM 120 Week 1 to Week 7 Quizzes / CHEM120 Unit 1 to Unit 7 Quiz: Chamberlain College of Nursing |Verified and 100% Correct Q & A| CHEM120 Unit 1 to Unit 7 Quiz (Latest-2022)/ CHEM 120 Unit 1 to Unit 7 Quiz / CHEM120 Week 1 to Week 7 Quizzes : Chamberlain College of Nursing |Verified and 100% Correct Q & A|

CHEM 120 Week 8 Final Exam A+ GRADED 6. (TCO 6) A gas at a temperature of 95 degrees C occupies a volume of 165 mL. Assuming constant pressure, determine the volume at 25 degrees C. Show your work. (Points : 5) Using Charles’ Law, (V1/T1) = (V2/T2). First, convert temperature to KELVIN (T1 = t1 +273) Thus, T1 = 95 + 273 = 368. We have V1 (165 mL) & T2 = (25 + 273) = 298. V2 = (V1*T2)/T1 = (165 mL*298)/368 = 133.6 mL. 7. (TCO 6) A sample of helium gas occupies ...

CHEM-120 Week # 2 DQ 2 – Chemical Structures The electron configuration of an atom determines the number of electrons available to participate in bonding with another atom. One method of depicting the valence electrons that an atom has is through the Lewis structure. To begin this discussion, pick an element from the periodic table of elements. Identify the valence electrons and the orbitals in which they reside. You can use the textbook and lecture. Pick a peers post and answer each of ...

Chem. 120: week 4 Question 1: (TCO 6) A sample of helium gas occupies 520 mL at 79 mmHg. For a gas sample at constant temperature, determine the volume of helium at 45 mmHg. Student Answer: Boyles Law P1V1=P2V2 Temp is constant 79 mmHg x 520 mL= 45 mmHg x V2 41080= 45 mmHg x V2 912.88 mL=V2 Instructor Explanation: Chapter 6; Using Boyle’s law, P1V1 = P2V2. We have V1 (520 mL), P1 (79 mmHg) and P2 (45 mmHg). We want to determine V2, so V2 = (P1 x V1)/P2 = (520 mL * 79 ...

CHEM 120 Week 8 Final Exam 1.(TCO 6) A gas at a temperature of 95 degrees C occupies a volume of 165 mL. Assuming constant pressure, determine the volume at 25 degrees C. Show your work. (Points : 5) Using Charles’ Law, (V1/T1) = (V2/T2). First, convert temperature to KELVIN (T1 = t1 +273) Thus, T1 = 95 + 273 = 368. We have V1 (165 mL) & T2 = (25 + 273) = 298. V2 = (V1*T2)/T1 = (165 mL*298)/368 = 133.6 mL. 0 7 Short 16 2.(TCO 6) A sample of helium gas occupies 1021 mL at 719 mmHg. F...