Chem 103 module 2 - Samenvattingen en Aantekeningen

CHEM 121 Module 1 Exam Questions and Answers - Portage Learning. Complete the two problems below: 1. Convert 1005.3 to exponential form and explain your answer. 2. Convert 4.87 x 10-6 to ordinary form and explain your answer. 1. Convert 1005.3 = larger than 1 = positive exponent, move decimal 3 places = 1.0053 x 103 2. Convert 4.87 x 10-6 =negative exponent =smaller than 1, move decimal 6 places = 0. Question 2 You may find the following resources helpful: Scientific Calculator (Links t...

Renewed version of Portage Learning CHEM 103 General Chemistry I with Lab Module 2. Don’t waste time and money on outdated materials—this updated study guide reflects Portage Learning's latest format changes, ensuring accuracy and relevance for efficient CHEM 103 exam preparation. *Disclaimer: This covers exam content only; lab materials are not included.

Chem 103 Module 1 to 6 Exam with Verified answers (100 OUT OF 100) Portage learning (Latest Update) MODULE 1 EXAM Question 1 Click this link to access the Periodic Table. This may be helpful throughout the exam. 1. Convert 845.3 to exponential form and explain your answer. 2. Convert 3.21 x 10-5 to ordinary form and explain your answer. 1. Convert 845.3 = larger than 1 = positive exponent, move decimal 2 places = 8.453 x 102 2. Convert 3.21 x 10-5 = negative exponent = smalle...

Show the calculation of the molecular weight for the following compounds, reporting your answer to 2 places after the decimal. 1. (NH4)2CO3 2. C8H6NO4Br

Exam CHEM 103 Final Exam (Version-1, Latest-2023)/ CHEM103 Final Exam / CHEM 103 General Chemistry Final Exam/ CHEM103 General Chemistry Final Exam: Portage Learning |100 % Correct Q & A| Exam CHEM 103 Final Exam (Version-1, Latest-2023)/ CHEM103 Final Exam / CHEM 103 General Chemistry Final Exam/ CHEM103 General Chemistry Final Exam: Portage Learning |100 % Correct Q & A| ...

Show the calculation of the molecular weight for the following compounds, reporting your answer to 2 places after the decimal. 1. Al (SO ) 2. C H NOBr 2 4 3 7 5 1. Al (SO ) Al = 2 x 26.98 = 53.96 S = 3 x 32.07 = 96.21 O = 12 x 16.00 = 192 2 4 3 M2: Exam - Requires Respondus LockDown Browser + Webcam: General Chemistry I w/Lab-2021- Kozminski 3/18 Total Molecular Weight for Al (SO ) = 342.17 2. C H NOBr C = 7 x 12.01 = 84.07 H = 5 x 1.008 = 5.04 N = 1 x 14.01 = 14.01 O = 1 x 16....

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Click this link to access the Periodic Table. This may be helpful throughout the exam. 1. Convert 845.3 to exponential form and explain your answer. 2. Convert 3.21 x 10-5 to ordinary form and explain your answer. 1. Convert 845.3 = larger than 1 = positive exponent, move decimal 2 places = 8.453 x 102 2. Convert 3.21 x 10-5 = negative exponent = smaller than 1, move decimal 5 places = 0. Question 2 Click this link to access the Periodic Table. This may be helpful throughout the exam. ...

Chem 103 Module 2 Exam Study Guide 100% Verified. Atom - AnswerBasic unit of matter; made of protons, neutrons, and electrons; have a nucleus that contains p and n and an electron cloud that surrounds it proton - AnswerA subatomic particle that has a positive charge and that is found in the nucleus of an atom neutron - AnswerA subatomic particle that has no charge and that is found in the nucleus of an atom electron - AnswerA subatomic particle that has a negative charge and is found out...

CHEM 103 Module 2 Problem Set (100 out of 100) Questions and Verified Elaborations (GRADED A)