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Portage Learning CHEM 104 Module 3 Exam
Portage Learning CHEM 104 Module 3 Exam.Question 1 Show the calculation of the molar solubility (mol/L) of BaF2, Ksp of BaF2 = 1.0 x 10-6. Your Answer: Ksp = [Ba+2] [F-]2 = 1.0x10-6 1.0x10-6 = [s] [2s]2 1.0x10-6 = 4s3 s = 6.3x10-3 mol/L Question 2 Show the calculation of the Ksp of MnS if the solubility of MnS is 0.0001375 g/100 ml. MW of MnS = 87.01 MnS (s) Mn+2 (aq) + S-2 (aq) Your Answer: molar solubility of MnS = (0.0001375 g/100 ml) x (1000 mL) x (1 mol/87.01 g MnS) molar solub...
- Exam (elaborations)
- • 7 pages •
Portage Learning CHEM 104 Module 3 Exam.Question 1 Show the calculation of the molar solubility (mol/L) of BaF2, Ksp of BaF2 = 1.0 x 10-6. Your Answer: Ksp = [Ba+2] [F-]2 = 1.0x10-6 1.0x10-6 = [s] [2s]2 1.0x10-6 = 4s3 s = 6.3x10-3 mol/L Question 2 Show the calculation of the Ksp of MnS if the solubility of MnS is 0.0001375 g/100 ml. MW of MnS = 87.01 MnS (s) Mn+2 (aq) + S-2 (aq) Your Answer: molar solubility of MnS = (0.0001375 g/100 ml) x (1000 mL) x (1 mol/87.01 g MnS) molar solub...
Portage Learning CHEM 104 Module 2 Exam
Portage Learning CHEM 104 Module 2 ExamQuestion 1 Identify each of the compounds below as ACID, BASE or SALT on the basis of their formula and explain your answer. (1) Cr(OH)3 (2) HAsO4 (3) CoCO3 Your Answer: 1. base - contains Cr metal + OH polyatomic group 2. acid - contains H + polyatomic group (AsO4) 3. salt - contains Co metal + polyatomic group (CO3) Question 2 For the Brønsted-Lowry acid base reactions shown below, list the stronger acid, stronger base, weaker acid and weaker...
- Exam (elaborations)
- • 10 pages •
Portage Learning CHEM 104 Module 2 ExamQuestion 1 Identify each of the compounds below as ACID, BASE or SALT on the basis of their formula and explain your answer. (1) Cr(OH)3 (2) HAsO4 (3) CoCO3 Your Answer: 1. base - contains Cr metal + OH polyatomic group 2. acid - contains H + polyatomic group (AsO4) 3. salt - contains Co metal + polyatomic group (CO3) Question 2 For the Brønsted-Lowry acid base reactions shown below, list the stronger acid, stronger base, weaker acid and weaker...
Portage Learning CHEM 104 Module 1 Exam:
Portage Learning CHEM 104 Module 1 Exam:Question 1 In the reaction of gaseous N2O5 to yield NO2 gas and O2 gas as shown below, the following data table is obtained: → 4 NO2 (g) + O2 (g) 1. Using the [O2] data from the table, show the calculation of the instantaneous rate early in the reaction (0 secs to 300 sec). 2. Using the [O2] data from the table, show the calculation of the instantaneous rate late in the reaction (2400 secs to 3000 secs). 3. Explain the relative values of the earl...
- Exam (elaborations)
- • 10 pages •
Portage Learning CHEM 104 Module 1 Exam:Question 1 In the reaction of gaseous N2O5 to yield NO2 gas and O2 gas as shown below, the following data table is obtained: → 4 NO2 (g) + O2 (g) 1. Using the [O2] data from the table, show the calculation of the instantaneous rate early in the reaction (0 secs to 300 sec). 2. Using the [O2] data from the table, show the calculation of the instantaneous rate late in the reaction (2400 secs to 3000 secs). 3. Explain the relative values of the earl...
Portage Learning CHEM 103 Final Exam
Portage Learning CHEM 103 Final Exam.Complete the two problems below: 1. Convert 0.0000726 to exponential form and explain your answer. 2. Convert 5.82 x 103 to ordinary form and explain your answer. Answer: 1. Convert 0.0000726 = smaller than 1 = negative exponent, move decimal 5 places = 7.26 x 10-5 2. Convert 5.82 x 103 = positive exponent = larger than 1, move decimal 3 places = 5820 Question 2 Do the conversions shown below, showing all work: 1. 358oK = ? oC 2. 53oC = ? oF 3. 15...
- Exam (elaborations)
- • 7 pages •
Portage Learning CHEM 103 Final Exam.Complete the two problems below: 1. Convert 0.0000726 to exponential form and explain your answer. 2. Convert 5.82 x 103 to ordinary form and explain your answer. Answer: 1. Convert 0.0000726 = smaller than 1 = negative exponent, move decimal 5 places = 7.26 x 10-5 2. Convert 5.82 x 103 = positive exponent = larger than 1, move decimal 3 places = 5820 Question 2 Do the conversions shown below, showing all work: 1. 358oK = ? oC 2. 53oC = ? oF 3. 15...
Portage Learning BIOD 171 Essential Microbiology Final Exam 2023
Portage Learning BIOD 171 Essential Microbiology Final Exam 2023.1. A virus is classified as a microbe. True. Although viruses are not living and as such are not considered microorganisms, they can, however, be classified as microbes, a more general term that includes microorganisms and viruses. 2. True or False: The smallest biological unit of life is the molecule. False. The smallest biological unit of life is the cell. 3. What are the 4 main types of macromolecules found i...
- Exam (elaborations)
- • 11 pages •
Portage Learning BIOD 171 Essential Microbiology Final Exam 2023.1. A virus is classified as a microbe. True. Although viruses are not living and as such are not considered microorganisms, they can, however, be classified as microbes, a more general term that includes microorganisms and viruses. 2. True or False: The smallest biological unit of life is the molecule. False. The smallest biological unit of life is the cell. 3. What are the 4 main types of macromolecules found i...
Portage Learning NURS 251 Module 2: Problem Set
Portage Learning NURS 251 Module 2: Problem SetDefine the following terms: Alternative medicine, complementary medicine, dietary supplement, and herbal medicine. Your Answer: Alternative medicine can be defined as herbal medicine, chiropractic, acupuncture, massage, reflexology, and any other therapies traditionally not emphasized in Western medical schools. Complementary medicine is defined as alternative medicine when used simultaneously with, rather than instead of, standard Western med...
- Exam (elaborations)
- • 12 pages •
Portage Learning NURS 251 Module 2: Problem SetDefine the following terms: Alternative medicine, complementary medicine, dietary supplement, and herbal medicine. Your Answer: Alternative medicine can be defined as herbal medicine, chiropractic, acupuncture, massage, reflexology, and any other therapies traditionally not emphasized in Western medical schools. Complementary medicine is defined as alternative medicine when used simultaneously with, rather than instead of, standard Western med...
Portage Learning CHEM 104 Module 6 Exam
Portage Learning CHEM 104 Module 6 ExamQuestion 1 1. List the four main classes of biochemicals. 2. which are also called polypeptides are formed from monomer molecules. Your Answer: 1. Carbohydrates, proteins, lipids and nucleic acids 2. Proteins amino acid Question 2 1. The oxygen transport protein in blood is (name). 2. Globular proteins are in water. Your Answer: 1. hemoglobin 2. soluble Question 3 What are names of the four nucleoside bases found in RNA? Your Answer: adenin...
- Exam (elaborations)
- • 6 pages •
Portage Learning CHEM 104 Module 6 ExamQuestion 1 1. List the four main classes of biochemicals. 2. which are also called polypeptides are formed from monomer molecules. Your Answer: 1. Carbohydrates, proteins, lipids and nucleic acids 2. Proteins amino acid Question 2 1. The oxygen transport protein in blood is (name). 2. Globular proteins are in water. Your Answer: 1. hemoglobin 2. soluble Question 3 What are names of the four nucleoside bases found in RNA? Your Answer: adenin...
Portage Learning CHEM 104 Module 5 Exam
Portage Learning CHEM 104 Module 5 ExamQuestion 1 Hexene is a hydrocarbon containing (#) carbons and a (type) bond. Your Answer: 6 C=C double Question 2 The compound below is a type of hydrocarbon called a/an . Your Answer: aromatic hydrocarbon Question 3 The compound below is called (#s)-dimethyl . Your Answer: 1,4 cyclohexane
- Exam (elaborations)
- • 8 pages •
Portage Learning CHEM 104 Module 5 ExamQuestion 1 Hexene is a hydrocarbon containing (#) carbons and a (type) bond. Your Answer: 6 C=C double Question 2 The compound below is a type of hydrocarbon called a/an . Your Answer: aromatic hydrocarbon Question 3 The compound below is called (#s)-dimethyl . Your Answer: 1,4 cyclohexane
Portage Learning CHEM 104 Module 4 Exam
Portage Learning CHEM 104 Module 4 ExamQuestion 1 For the cell described by the following cell diagram. Cr (s) | Cr+3 (aq, 1 M) || Al+3 (aq, 1 M) | Al (s) Al+3 + 3e- → Al E0 = - 1.66 v Cr+3 + 3e- → Cr E0 = - 0.73 v (1) The anode half reaction is (2) The cathode half reaction is (3) The overall cell reaction is (4) Show the calculation for the total cell potential (5) State and explain whether the cell is voltaic or electrolytic Your Answer: 1) Cr (s) → Cr+3 (aq) + 3e- 2) Al+3 (...
- Exam (elaborations)
- • 11 pages •
Portage Learning CHEM 104 Module 4 ExamQuestion 1 For the cell described by the following cell diagram. Cr (s) | Cr+3 (aq, 1 M) || Al+3 (aq, 1 M) | Al (s) Al+3 + 3e- → Al E0 = - 1.66 v Cr+3 + 3e- → Cr E0 = - 0.73 v (1) The anode half reaction is (2) The cathode half reaction is (3) The overall cell reaction is (4) Show the calculation for the total cell potential (5) State and explain whether the cell is voltaic or electrolytic Your Answer: 1) Cr (s) → Cr+3 (aq) + 3e- 2) Al+3 (...
Portage Learning CHEM 104 Module 3 Exam
Portage Learning CHEM 104 Module 3 ExamQuestion 1 Show the calculation of the molar solubility (mol/L) of BaF2, Ksp of BaF2 = 1.0 x 10-6. Your Answer: Ksp = [Ba+2] [F-]2 = 1.0x10-6 1.0x10-6 = [s] [2s]2 1.0x10-6 = 4s3 s = 6.3x10-3 mol/L Question 2 Show the calculation of the Ksp of MnS if the solubility of MnS is 0.0001375 g/100 ml. MW of MnS = 87.01 MnS (s) Mn+2 (aq) + S-2 (aq) Your Answer: molar solubility of MnS = (0.0001375 g/100 ml) x (1000 mL) x (1 mol/87.01 g MnS) molar solubi...
- Exam (elaborations)
- • 7 pages •
Portage Learning CHEM 104 Module 3 ExamQuestion 1 Show the calculation of the molar solubility (mol/L) of BaF2, Ksp of BaF2 = 1.0 x 10-6. Your Answer: Ksp = [Ba+2] [F-]2 = 1.0x10-6 1.0x10-6 = [s] [2s]2 1.0x10-6 = 4s3 s = 6.3x10-3 mol/L Question 2 Show the calculation of the Ksp of MnS if the solubility of MnS is 0.0001375 g/100 ml. MW of MnS = 87.01 MnS (s) Mn+2 (aq) + S-2 (aq) Your Answer: molar solubility of MnS = (0.0001375 g/100 ml) x (1000 mL) x (1 mol/87.01 g MnS) molar solubi...
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ATI Renal / Urinary Exam 2023.
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