100% satisfaction guarantee Immediately available after payment Both online and in PDF No strings attached
logo-home
Previously searched by you
Previously searched by you
logo
CHEM 103 Final Exam (100 out of 100) Questions and Answers (New Update) Verified Elaborations | 100% Correct Answers $10.99
Add to cart
Quickly navigate to
Preview
  2.  
  3. Chem 103
  4.  
  5. Chem 103

Exam (elaborations)

CHEM 103 Final Exam (100 out of 100) Questions and Answers (New Update) Verified Elaborations | 100% Correct Answers
 0 purchase
  • Course
  • Chem 103
  • Institution
  • Chem 103

CHEM 103 Final Exam (100 out of 100) Questions and Answers (New Update) Verified Elaborations | 100% Correct Answers

Preview 2 out of 5  pages

Document information

  • March 14, 2024
  • 5
  • 2023/2024
  • Exam (elaborations)
  • Questions & answers

Subjects

  • chem 103 final exam 100 out of 100 questions and

Written for

  • Chem 103
  • Chem 103

Seller

avatar-seller
JOLLY007ACE

Reviews received

Content preview

This study source was downloaded by 100000880877832 from CourseHero.com on 02 -15-2024 03:00:05 GMT -06:00 https://www.coursehero.com/file/189588951/CHEM -103-Final -Examdocx/ CHEM 103 Final Exa m (100 out of 100) Question s and Answers (New Update) Verified Elaborations. Question 1 Complete the two problems below: 1. Convert 0.0000726 to exponential form and explain your answer. 2. Convert 5.82 x 103 to ordinary form and explain your answer. Answer: 1. Convert 0.0000726 = smaller than 1 = negative exponent, move decimal 5 places = 7.26 x 10-5 2. Convert 5.82 x 103 = positive exponent = larger than 1, move decimal 3 places = 5820 Question 2 Do the conversions shown below, showing all work: 1. 358oK = ? oC 2. 53oC = ? oF 3. 158oF = ? oK Answer: 1. 358oK - 273 = 85 oC oK → oC (make smaller) -273 2. 53oC x 1.8 + 32 = 127.4 oF oC → oF (make larger) x 1.8 + 32 3. 158oF - 32 ÷ 1.8 = 70 + 273 = 343 oK oF → oC → oK Question 3 Show the calculation of the number of moles in the given amount of the following substances. Report your answer to 3 significant figures. 1. 12.0 grams of Ca 3(PO 4)2 This study source was downloaded by 100000880877832 from CourseHero.com on 02 -15-2024 03:00:05 GMT -06:00 https://www.coursehero.com/file/189588951/CHEM -103-Final -Examdocx/ 2. 15.0 grams of C9H8NO 4Cl Answer: 1. Moles = grams / molecular weight = 12.0 / 310.18 = 0.0387 mole 2. Moles = grams / molecular weight = 15.0 / 229.61 = 0.0653 mole Question 4 Show the calculation of the percent of each element present in the following compounds. Report your answer to 2 places after the decimal. 1. Al 2(SO 4)3 2. C7H5NOBr Answer: 1. %Al = 2 x 26.98/342.17 x 100 = 15.77% %S = 3 x 32.07/342.17 x 100 = 28.12% %O = 12 x 16/342.17 = 56.11% 2. %C = 7 x 12.01/ 199.02 x 100 = 42.24% %H = 5 x 1.008/ 199.02 x 100 = 2.53% %N = 1 x 14.01/199.02 = 7.04% %O = 1 x 16.00/199.02 x 100 = 8.04% %Br = 79.90/199.02 x 100 = 40.15% Question 5 Show the calculation of the heat of reaction (ΔH rxn) for the reaction: CH 4 (g) + 2 O 2 (g) → CO 2 (g) + 2 H 2O (l) by using the following thermochemical data: ΔH f0 CH 4 (g) = -74.6 kJ/mole, ΔH f0 CO 2 (g) = -393.5 kJ/mole, ΔH f0 H2O (l) = -285.8 kJ/mole Answer:

The benefits of buying summaries with Stuvia:

Guaranteed quality through customer reviews

Guaranteed quality through customer reviews

Stuvia customers have reviewed more than 700,000 summaries. This how you know that you are buying the best documents.

Quick and easy check-out

Quick and easy check-out

You can quickly pay through credit card or Stuvia-credit for the summaries. There is no membership needed.

Focus on what matters

Focus on what matters

Your fellow students write the study notes themselves, which is why the documents are always reliable and up-to-date. This ensures you quickly get to the core!

Frequently asked questions

What do I get when I buy this document?

You get a PDF, available immediately after your purchase. The purchased document is accessible anytime, anywhere and indefinitely through your profile.

Satisfaction guarantee: how does it work?

Our satisfaction guarantee ensures that you always find a study document that suits you well. You fill out a form, and our customer service team takes care of the rest.

Who am I buying these notes from?

Stuvia is a marketplace, so you are not buying this document from us, but from seller JOLLY007ACE. Stuvia facilitates payment to the seller.

Will I be stuck with a subscription?

No, you only buy these notes for $10.99. You're not tied to anything after your purchase.

Can Stuvia be trusted?

4.6 stars on Google & Trustpilot (+1000 reviews)

67479 documents were sold in the last 30 days

Founded in 2010, the go-to place to buy study notes for 15 years now

Start selling
$10.99
  • (0)
Add to cart
Added