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IICRC S500 Water Mitigation Exam Questions and Answers Latest Update

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IICRC S500 Water Mitigation

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IICRC S500 Water Mitigation

Four principles of water damage restoration: - ANSWER-Provide for health and safety of workers and occupants; Document everything; Mitigate, and Dry Four principles of drying - ANSWER-Extract, Evaporate, dehumidify, control temp Extraction - ANSWER-is removing excess water and is the first st...

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iicrc s500 water mitigation exam questions and ans
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the homeowner answer is responsible to take the

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IICRC S500 Water Mitigation Exam
Questions and Answers Latest Update

The homeowner - ANSWER-is responsible to take the necessary steps to preserve and
protect their property from further damage

Four principles of water damage restoration: - ANSWER-Provide for health and safety
of workers and occupants; Document everything; Mitigate, and Dry

Four principles of drying - ANSWER-Extract, Evaporate, dehumidify, control temp

Extraction - ANSWER-is removing excess water and is the first step in mitigation

Evaporation - ANSWER-is achieved by using energy (heat) to transform water trapped
in porous materials into a vapor, thereby releasing the moisture from the materials.

Dehumidification - ANSWER-the process of removing water vapor from the air.

Rate of Dehumidification - ANSWER-must be at least equal to the rate of evaporation.

True or False - ANSWER-Elevated vapor pressure in a room Can cause secondary
damage to hygroscopic materials

True or False - ANSWER-The control of temperature is important to enhance both
evaporation and dehumidification for effective drying

True or False - ANSWER-When temperature increases evaporation of absorbed water
increases and water vapor suspended in air also increases.

Classification of Water Intrusion - ANSWER-described as Class 1, 2, 3, or 4. Must be
determined to calculate the amount of dehumidification required in drying process,

, based on the amount of wet surface area, permeance/porosity of materials in drying
area.

Class 1 - ANSWER-is the least amount of water absorption and evaporation load,
affecting less 5% of porous materials with minimal absorption into low evaporation
materials.

Class 2 - ANSWER-has a significant amount of water absorption and evaporation load,
affection 5-40% porous materials, with minimal absorption into low evaporated materials

Class 3 - ANSWER-has the greatest amount of water absorption and evaporation load,
affecting more than 40% porous materials and minimal absorption into low evaporated
materials

Class 4 - ANSWER-has deeply held or bound water, and significant absorption into low
evaporation materials.

Determine the Class of water for a 20' x 20' x 8 ' room, with an entirely wet floor.. -
ANSWER-Affected area/Total SF = % affected

400/1440 = .27777 x 100 = 28%

28% = Class 2

Determine the Class of Water for a 20' x 20' x 8' room, with only half the floor affected
and arriving within 24 hours of loss. - ANSWER-Affected area/total sf = % affected

200/1440 = .13888 x 100 = 14%

14% = Class 2

Determine Class of water for a 20' x 20' x 8' room, with entirely wet plywood subfloor
arriving 48 hours after loss - ANSWER-affected area/total sf = % affected

Class 4 due to deeply bound water sitting for long time

Categories of Water - ANSWER-there are four categories - determined by range of
contamination of the source and quality of water

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