AFOQT PRACTICE TEST (MATH SECTION) Top Questions and answers. Accurate.

AFOQT PRACTICE TEST (MATH SECTION) Top Questions and answers. Accurate. if the volume of a cube is 8cm^3, what is the length of the cube? a. 1 cm b. 2 cm c. 3 cm d. 4 cm e. 8 cm - B. 2 cm Simplify the following expression: (2x2 + 3) (2x - 1) a. 4x3 - 2x2 +6x - 3 b. 2x2 +6x - 3 c. 4x3 - 2x2 +6x + 3 d. 4x3 - 2x2 - 6x - 3 e. 2x2 - 6x + 3 - A. 4x3 - 2x2 +6x - 3 Simplify the following expression: (2x4y7m2z) * (5x2y3m8) a. 10x6y9m10z b. 7x6y10m10z c. 10x5y10m10z d. 10x6y10m10z e. 7x5y9m10z - D. 10x6y10m10z A classroom contains 13 boys and 18 girls. If a student's name is chosen randomly, what is the probability it will be a girl's name? a. 36% b. 42% c. 58% d. 72% e. 84% - c. 58% If x - 9 = 2x + 10, what is the value of x? a. -19 b. 19 c. 6.3 d. -6.3 e. none of the above - a. -19 A rectangle has a width of 7 cm and a length of 9 cm. What is its perimeter? a. 16 cm b. 32 cm c. 48 cm d. 62 cm e . 63 cm - b. 32 The perimeter of a figure is the sum of all of its sides. Since a rectangle's width and length will be the same on opposite sides, the perimeter of a rectangle can be calculated by using the following formula: perimeter = 2(width) + 2(length) Using the numbers given in the question: perimeter = 2(7cm) + 2(9cm) perimeter = 14cm + 18cm perimeter = 32cm In the following inequality, solve for q. -3q + 12 ≥ 4q - 30 a. q ≥ 6 b. q = 6 c. q ≠ 6 d. q ≤ 6 e. q does not exist - D: First, gather the like terms on opposite sides of the equation to make it easier to solve: -3q - 4q ≥ -30 - 12 -7q ≥ -42 Then, divide both sides by -7 to solve for q: -7q/-7 ≥ -42/-7 q ≥ 6 Finally, when both sides are divided by a negative number, the direction of the sign must be reversed: q ≤ 6 If x - 6 = 0, then x is equal to a. 0 b. 3 c. 6 d. 9 e. 12 - C: To solve for x, it is necessary to add 6 to both sides to isolate the variable: x - 6 + 6 = 0 + 6 x = 6 If x = -3, calculate the value of the following expression: 3x3 + (3x + 4) - 2x2 a. -104 b. -58 c. 58 d. 104 e. 0 - A: To calculate the value of this expression, substitute -3 for x each time it appears in the expression: 3(-3)3 + (3(-3)+ 4) - 2(-3)2 According to the order of operations, any operations inside of brackets must be done first: 3(-3)3 + (-9+ 4) - 2(-3)2 3(-3)3 + -5 - 2(-3)2 Then, the value of the expression can be calculated: 3(-27) + -5 - 2(9) -81 + -5 - 18 -104 If 3x - 30 = 45 - 2x, what is the value of x? a. 5 b. 10 c. 15 d. 20 e. 25 - C: First, combine like terms to make the equation easier to solve: 3x + 2x = 45 + 30 5x = 75 Then, divide both sides by 5 to solve for x: 5x/5 = 75/5 x = 15 Solve for x in the following inequality: 1/4x - 25 ≥ 75 a. x ≥ 400 b. x ≤ 400 c. x ≥ 25 d. x ≤ 25 e. x ≥ 50 - A: First, add 25 to both sides to isolate x: 1/4x - 25 + 25 ≥ 75 + 25 1/4x ≥ 100 Then, multiply both sides by 4 to solve for x: 1/4x * 4 ≥ 100 * 4 x ≥ 400 If x2 - 5 = 20, what is possible value of x? a. 5 b. 10 c. 12.5 d. 15 e. 25 - A: First, add 5 to both sides to isolate x: x2 - 5 + 5 = 20 + 5 x2 = 25 Then, take the square root of both sides to solve for x v√x² = √25 x = 5 What is the area of a square that has a perimeter of 8 cm? a. 2 cm2 b. 4 cm2 c. 32 cm2 d. 64 cm2 e. 160 cm2 - B: First, we must calculate the length of one side of the square. Since we know the perimeter is 8cm, and that a square has 4 equal sides, the length of each side can be calculated by dividing the perimeter (8cm) by 4: 8cm / 4 = 2cm The formula for the area of a square is length2 Therefore, to calculate the area of this