CHEM 108 (CHEM108)

Module 5 Exam Exam Page 1 In the reaction of gaseous N2O5 to yield NO2 gas and O2 gas as shown below the following data table is obtained: 2 N2O5 (g) → 4 NO2 (g) + O2 (g) Data Table #1 Time (sec) [N2O5] [O2] 0 0.200 M 0 300 0.182 M 0.009 M 600 0.166 M 0.017 M 900 0.152 M 0.024 M 1200 0.140 M 0.030 M 1800 0.122 M 0.039 M 2400 0.112 M 0.044 M 3000 0.108 M 0.046 M Complete the following three problems: Using the [O2] data from the table show the calculation of the average rate ov...

Module 1: Question 1 In the reaction of gaseous N2 O5 to yield NO2 gas and O2 gas as shown below, the following data table is obtained: 2 N2 O5 (g) → 4 NO2 (g) + O2 (g) Data Table #2 Time (sec) [N2 O5 ] [O2 ] 0 0.300 M 0 300 0.272 M 0.014 M 600 0.224 M 0.038 M 900 0.204 M 0.048 M 1200 0.186 M 0.057 M 1800 0.156 M 0.072 M 2400 0.134 M 0.083 M 3000 0.120 M 0.090 M 1. Using the [O2 ] data from the table, show the calculation of the instantaneous rate early in the reaction (0 secs to 300 sec). 2. ...

Module 1: Question 1 In the reaction of gaseous N2 O5 to yield NO2 gas and O2 gas as shown below, the following data table is obtained: 2 N2 O5 (g) → 4 NO2 (g) + O2 (g) Data Table #2 Time (sec) [N2 O5 ] [O2 ] 0 0.300 M 0 300 0.272 M 0.014 M 600 0.224 M 0.038 M 900 0.204 M 0.048 M 1200 0.186 M 0.057 M 1800 0.156 M 0.072 M 2400 0.134 M 0.083 M 3000 0.120 M 0.090 M 1. Using the [O2 ] data from the table, show the calculation of the instantaneous rate early in the reaction (0 secs to 300 sec). 2. ...

CHEM 108 PRACTICE FINAL EXAM ANSWERS WITH 100% CORRECT ANSWERS DOWNLOAD TO SCORE A+

Exam Page 1 NOTE: Answer both questions 1) When blood is analyzed we use the (liquid) blood serum so the results can been seen. 2) During the calcium ion test a white (color) precipitate (state) of calcium oxalate is formed. Answer Key NOTE: Answer both questions 1) When blood is analyzed we use the serum so the results can been seen. 2) During the calcium ion test a white (color) precipitate

Gas Laws Gases are often formed as a product of or are used as a reactant in a chemical reaction. These materials (gases) have some special properties and are subject to some special calculations in chemistry. Gases (think of air as an example) are very light, are easily expandable, are easily compressible, and completely fill a container into which they are released. These properties are due to the fact that the individual molecules of the gas are very far apart from one another, are not...

Show the calculation of the molecular weight for the following two compounds, reporting your answer to 2 places after the decimal. Al2(CO3)3 Al2(CO3)3 Al2 = 2 x 26.98 = 53.98 3C = 3 x 12.01 = 36.03 9O = 9 x 16.00 = 144 Ans: 243.01 C8H6NO4Cl C8H6NO4CI C = 8 x 12.01 = 96.08 H= 6 x 1.00 = 6 NO = 4 x 259.10 = 1036.4 CI = 35.45 = 35.45 Ans : 1173.93 -4.0 points Instructor Comments Calculation error in the first compound. In the second compound the elements are nitrogen, N and oxygen...

Show the calculation of the new temperature of a gas sample which has an original volume of 700 ml when collected at 730 mm and 35oC when the volume becomes 480 ml at 1.15 atm. 700ml/1000= 0.7 liters= Vi 730mm/700= 1.042 atm=Pi 35 ºC + 273 = 308K = Ti 480ml/ 1000 = 0.04 liters = Vf 1.15 amt= Pf (1.042) ×(0.7)= (1.15) × (0.04) (308) Tf Tf= 12.50 = 17.15K 0.729 -7.0 points Answer Key Show the calculation of the new temperature of a gas sample which has an original volume of 700...

CHEM 108 MODULE 5 EXAM WITH 100% CORRECT ANSWERS