Subsequence - Study guides, Class notes & Summaries

Knapsack without repetition - ANSWER-k(0) = 0 for w = 1 to W: if w_j >w: k(w,j) = k(w, j - 1) else: K(w,j) = max{K(w, j -1),K(w - w_j, j -1) + v_i} knapsack with repetition - ANSWER-knapsack repeat(w_i....w_n, w_i... w_n, B) k(0) = 0 for i = 1 to n if w_i <= b & k(b) <v_i + K(b-w_i) then k(b) = v_i + K(b-w_i) Longest Increasing Subsequence - ANSWER-LIS(a_1.... a_n) for i = 1 to n L(i) = 1 for j = 1 to n -1 if a_j < a_i & L(i) < 1 + L(j) L(i) = 1 + L(j) max = 1 for ...

Consider the following generalization of the Activity Selection Problem: You are given a set of n activities each with a start time si, a finish time fi, and a weight wi. Design a dynamic programming algorithm to find the weight of a set of non-conflicting activities with maximum weight. - ANSWER-Formula: (Sort by finish time) A[i] = max (from activity 1 to i) { A[i - 1] max{A[x]} + wi } (x being activity whose finish time <= activity i's start time) A contiguous subsequence of a l...

alg quiz Consider the following generalization of the Activity Selection Problem: You are given a set of n activities each with a start time si, a finish time fi, and a weight wi. Design a dynamic programming algorithm to find the weight of a set of non-conflicting activities with maximum weight. - ANSWER-Formula: (Sort by finish time) A[i] = max (from activity 1 to i) { A[i - 1] max{A[x]} + wi } (x being activity whose finish time <= activity i's start time) A contiguous subseque...

What is the running time for Longest Increasing Subsequence (LIS) - ANSWER-O(n^2) What is the recurrence for Longest Increasing Subsequence (LIS)? - ANSWER-L(i) = 1 + max{ L(j) | xj < xi} This reads as the answer to index I is 1 + the maximum over all j's between 1 and i where xj is less than xi What is the recurrence for Longest Common Subsequence (LCS) - ANSWER-L(i,j) = 1 + L(i-1, j-1) if xi = yj L(i,j) = max(L(i-1,j),L(i,j-1)) otherwise What is the running time for Longest Common...

Scripting and Programming Foundations WGU Exam Questions And Answers Editor - ANS allows you to write code Compiler - ANS Turns programming language into computer language Interpreter - ANS Same as compiler, but converts code one step at a time instead of the entire program at once Operator - ANS An object that takes two operands and does something with them Expression - ANS Something that has value Terminal vs non-terminal expression - ANS Terminal is a final valu...

4 IGORRIVIN f irst, let’s talk about what it means for some property P to be generic for some (possibly) infinite (but countable) set S. 3. Anidealist approach to randomness First, define a measure of size v on the elements of S. This should satisfy some simple axioms, such as: (1) v(x) ≥ 0 for all x ∈ S. (2) The set Sk = {x ∈ S|v(x) ≤ k} is finite for every k. Let now P be a predicate on the elements of S– think of a predicate as just a function from S to {0,1}...

Unilateral Contract Contract based on one party's making a promise that calls for action. Ex: (Only one promise, Eg: Prof. Smith promising 6 hours of work for $100.) Bilateral Contract Contract based on both parties making promises to each other. Express Contract Contract is communicated in writing, orally, or both. Implied Contract No express contract but parties' actions/relationship supports avoiding unjust enrichment. Unjust Enrichment Someone benefited un...

Strings are_____ - correct answer immutable immutable definition - correct answer The character contents can no longer be changed. == - correct answer compares instance(address of the object) equals - correct answer compares content of String Objects equalsignoreCase - correct answer ...

Base cases and recurrences for Fibonacci - Answer-if n = 0, return 0 if n = 1, return 1 return L(n-1) + L(n-2) Base case and recurrences for LIS (Longest Increasing Subsquences) - Answer-L(i) = 0 L(i) = 1 + max{L(j): aj<ai & j < i} Base case and recurrences for LCS (Longest Common Subsequence) - Answer-L(i, 0) = 0 L(0, j) = 0 if xi != yj: L(i, j) = max{L(i-1, j), L(i, j-1)} if xi = yj: L(i, j) = L(i-1, j-1) + 1 Base case and recurrences for Knapsack (No Repeat) - Answer-K(0, b) ...

AVID MC 110 - Lesson 4-5 Exam Questions and Complete Solutions If editing a group of clips to the sequence from the bin in Text view, what controls the order in which the clips will appear in the sequence? - Ans: You can control the order in which the clips appear in the stringout sequence by sorting them in the bin. You can sort the bin by the column that you want to use to determine the order of the clips, this is by name, scene/take, quality rating, start timecode, etc If editing a grou...