Introduction to Electric Circuits 9th Edition By James Svoboda, Richard Dorf (Solution Manual)
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Introduction To Electric Circuits 9e James Svobod
Introduction to Electric Circuits 9e James Svoboda, Richard Dorf (Solution Manual)
Introduction to Electric Circuits 9e James Svoboda, Richard Dorf (Solution Manual)
1-1 Chapter 1 – Electric Circuit Variables Exercises Exercise 1.2-1 Find the charge that has entered an element by time t when i = 8t2 – 4t A, t ≥ 0. Assume q(t) = 0 for t < 0. Answer: 328() 2 C3qt t t=− Solution: ()2
23 2 3 2
00 0 84 A
88() ( 0 ) ( 8 4 ) 0 2 2 C33t ttit t t
qt i d q d t t ττ τ τ τ τ=−
=+ = −+ = − = −∫∫ Exercise 1.2-2 The total charge that has entered a circuit element is q(t) = 4 sin 3 t C when t ≥ 0 and q(t) = 0 when t < 0. Determine the current in this circuit element for t > 0. Answer: () 4 s i n 3 1 2 c o s 3 Adit t tdt== Solution: () 4sin3 12cos3 Adq dit t tdt dt== = Exercise 1.3-1 Which of the three currents, i1 = 45 μA, i2 = 0.03 mA, and i3 = 25 × 10–4 A, is largest? Answer: i3 is largest. Solution: i1 = 45 μA = 45 × 10-6 A < i2 = 0.03 mA = .03 × 10-3 A = 3 × 10-5 A < i3 = 25 × 10-4 A (Introduction to Electric Circuits 9e James Svoboda, Richard Dorf)
(Solution Manual, For Complete File, Download link at the end of this File) 1-2 Exercise 1.5-1 Figure E 1.5-1 shows four circuit el ements identified by the letters A, B, C, and D. (a) Which of the devices supply 12 W? (b) Which of the devices absorb 12 W? (c) What is the value of th e power received by device B? (d) What is the value of the power delivered by device B? (e) What is the value of the power delivered by device D? Answers: (a) B and C, (b) A and D, (c)–12 W, (c) 12 W, (e)–12 W (A)+4 V
3 A–
(B)–2 V
6 A
(C)+ +6 V
2 A–
(D)–3 V
4 A+ Figure E 1.5-1 Solution: (a) B and C. The element voltage and current do not adhere to the pass ive convention in B and C so the product of the element voltage and curr ent is the power supplie d by these elements. (b) A and D. The element voltage and current a dhere to the passive convention in A and D so the product of the element voltage and current is the power delivered to, or absorbed by these elements. (c) −12 W. The element voltage and current do no t adhere to the pa ssive convention in B, so the product of the element voltage and current is the power received by this element: (2 V)(6 A) = −12 W. The power supplied by the elem ent is the negative of the power delivered to the element, 12 W. (d) 12 W (e) –12 W. The element voltage and current adhere to the passive convention in D, so the product of the element voltage and current is the power received by this element: (3 V)(4 A) = 12 W. The power supplied by the element is the negative of the power received to the element, −12 W. 1-3 Problems Section 1-2 Electric Circuits and Current Flow P1.2.1 The total charge that has entered a circuit element is q(t) = 1.25(1– e–5t) when t ≥ 0 and q(t) = 0 when t < 0. Determine the current in this circuit element for t ≥ 0. Answer: i(t) = 6.25 e–5t A Solution: ()()551.25 1 6.25tt dit e edt− −=− = A P 1.2-2 The current in a circuit element is i(t) = 4(1– e–5t) A when t ≥ 0 and i(t) = 0 when t < 0. Determine the total charge that has entered a circuit element for t ≥ 0. Hint: 0(0) ( ) 0 0tqi d ττ
−∞ −∞===∫∫ Answer: q(t) = 4 t + 0.8 e–5t– 0.8 C for t ≥ 0 Solution: () () () ()55 5
00 0 04404 1 0 4 4 455tt t ttqt i d q e d d e d t eττττ τ τ τ−− −=+ = − + = − = + −∫∫ ∫ ∫ C P 1.2-3 The current in a circuit element is i(t) = 4 sin 3 t A when t ≥ 0 and i(t) = 0 when t < 0. Determine the total charge that has entered a circuit element for t ≥ 0. Hint: 0(0) ( ) 0 0ττ τ
−∞ −∞== =∫∫tqi dd Solution: () () ()0 0044 40 4sin 5 0 cos3 cos3 C55 5tt tqt i d q d t ττ τ τ τ= + = + =− =− +∫∫ 1-4 P 1.2-4 The current in a circuit element is 02
22 4()14 8
08t
titt
t<⎧
⎪<< ⎪=⎨−<<⎪
⎪<⎩ where the units of current are A and the units of time are s. Determine the total charge that has entered a circuit element for t ≥ 0. Answer: 02
24 2 4( ) where the units of84 8
08< ⎧
⎪−< <⎪=⎨−< <⎪
⎪ < ⎩t
ttqttt
tcharge are C. Solution: () () 0ttqt i d d τττ
−∞ −∞== =∫∫ 0 C for t ≤ 2 so q(2) = 0. () () ()2 22222tt tqt i d q d ττ τ τ=+ = = =∫∫ 2t−4 C for 2 ≤ t ≤ 4. In particular, q(4) = 4 C. () () ()4 4441 4 4tt tqt i d q d ττ τ τ=+ = − + = − + =∫∫ 8−t C for 4 ≤ t ≤ 8. In particular, q(8) = 0 C. () () ()
8880 0ttqt i d q d ττ τ=+ = + =∫∫ 0 C for 8 ≤ t . P 1.2-5 The total charge q(t), in coulombs, that enters th e terminal of an element is 2( 2 )00
() 2 0 2
32ttt
qt t t
et−−< ⎧
⎪=≤ ≤⎨
⎪+>⎩ Find the current i(t) and sketch its waveform for t ≥ 0. Solution: ()()
()2200 () 2 0 2
2 2tt
dq tit i t tdt
et−−⎧ <
⎪== < < ⎨
⎪−>⎩
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