CHEM 108 (CHEM108)
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CHEM 108 PRACTICE FINAL EXAM WITH 100% CORRECT ANSWERS GRADED A
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CHEM 108 PRACTICE FINAL EXAM WITH 100% CORRECT ANSWERS GRADED A
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CHEM 108 MODULE 6 EXAM WITH 100% CORRECT ANSWERS GRADED A
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CHEM 108 MODULE 6 EXAM WITH 100% CORRECT ANSWERS GRADED A
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CHEM 108 Module 6 Exam Answers- Portage Learning
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Problem Set 1 
1. Identify each of the compounds below as ACID, BASE or SALT on the basis of their formula and 
explain your answer based on the definition given in the module: 
(a) HC6H5O2 
Acid 
(b) Be(OH)2 
Base 
(c) Mn(ClO2)2 
Salts 
(d) AgCl 
Salts 
(e) Sn(OH)4 
bases 
(f) H2CrO4 
acids 
(g) PbO2 
Salts 
(h) Ni(OH)4 
Bases 
(i) H3AsO4 
Acids 
(j) HC2H3O2 
Acids 
2. Identify the following unknown substances as ACID, BASE or SALT on the basis of their property
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CHEM 108 PRACTICE FINAL EXAM ANSWERS- PORTAGE LEARNING
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PRACTICE EXAM 
Using the following information, complete the two conversions shown below, showing all work: 
1 ft = 12 inches 1 pound = 16 oz 1 gallon = 4 quarts 
1 mile = 5280 feet 1 ton = 2000 pounds 1 quart = 2 pints 
kilo (= 1000) milli (= 1/1000) centi (= 1/100) deci (= 1/10) 
25.6 mg = ? grams 
25.6 mg x 1 g / 1000 mg = 0.0256 grams 
1.5 gal = ? qts 
1.5 gal x 4 qts / 1 gal = 6.0 qts 
Write the formula for each of the following 3 chemical compounds explaining the answer with 
appropriate c...
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CHEM 108 Module 3 Exam Answers- Portage Learning
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Module 3 exam 
Exam Page 1 
Show the calculation of the new temperature of a gas sample which has an original volume of 700 ml 
when collected at 730 mm and 35oC when the volume becomes 480 ml at 1.15 atm. 
700ml/1000= 0.7 liters= Vi 
730mm/700= 1.042 atm=Pi 
35 ºC + 273 = 308K = Ti 
480ml/ 1000 = 0.04 liters = Vf 
1.15 amt= Pf 
 (1.042) ×(0.7)= (1.15) × (0.04) 
 (308) Tf 
 Tf= 12.50 = 17.15K 
 0.729
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CHEM 108 Module 5 Exam Answers- Portage Learning
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Exam Page 1 
In the reaction of gaseous N2O5 to yield NO2 gas and O2 gas as shown below the following data table 
is obtained: 
2 N2O5 (g) → 4 NO2 (g) + O2 (g) 
Data Table #1 
Time (sec) [N2O5] [O2] 
0 0.200 M 0 
300 0.182 M 0.009 M 
600 0.166 M 0.017 M 
900 0.152 M 0.024 M 
1200 0.140 M 0.030 M 
1800 0.122 M 0.039 M 
2400 0.112 M 0.044 M 
3000 0.108 M 0.046 M 
Complete the following three problems: 
Using the [O2] data from the table show the calculation of the average rate over the measured ...
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CHEM 108 LAB 1-LAB 10 EXAM BUNDLE- PORTAGE LEARNING
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CHEM 108 LAB 1-LAB 10 EXAM BUNDLE- PORTAGE LEARNING|CHEM 108 LAB 1-LAB 10 EXAM BUNDLE- PORTAGE LEARNING|CHEM 108 LAB 1-LAB 10 EXAM BUNDLE- PORTAGE LEARNING
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CHEM 108 LAB 10 EXAM - PORTAGE LEARNING
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CHEM 108 LAB 10 EXAM - PORTAGE LEARNING|CHEM 108 LAB 10 EXAM - PORTAGE LEARNING|CHEM 108 LAB 10 EXAM - PORTAGE LEARNING
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CHEM 108 LAB 10 EXAM - PORTAGE LEARNING
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CHEM 108 LAB 10 EXAM - PORTAGE LEARNING|CHEM 108 LAB 10 EXAM - PORTAGE LEARNING|CHEM 108 LAB 10 EXAM - PORTAGE LEARNING
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CHEM 108 LAB 9 EXAM - PORTAGE LEARNING
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CHEM 108 LAB 9 EXAM - PORTAGE LEARNING|CHEM 108 LAB 9 EXAM - PORTAGE LEARNING|CHEM 108 LAB 9 EXAM - PORTAGE LEARNING
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