Chem 103 module 2 exam Study guides, Class notes & Summaries
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Portage Learning - CHEM 103 MODULE 2 Exam
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CHEM 103 Module 2 Exam (Portage Learning)
- Exam (elaborations) • 19 pages • 2023
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CHEM 103 Module 2 Exam (Portage Learning) Show the calculation of the molecular weight for the following 
compounds, reporting your answer to 2 places after the decimal. 
1. Al (SO ) 
2. C H NOBr 
2 4 3 
7 5 
1. Al (SO ) 
Al = 2 x 26.98 = 53.96 
S = 3 x 32.07 = 96.21 
O = 12 x 16.00 = 192 
2 4 3 
M2: Exam - Requires Respondus LockDown Browser + Webcam: General Chemistry I w/Lab-2021- Kozminski 
3/18 
Total Molecular Weight for Al (SO ) = 342.17 
2. C H NOBr 
C = 7 x 12.01 = 84.07 
H = 5 x 1.008 ...
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Portage Learning - CHEM 103 MODULE 2 Exam
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Portage Learning - CHEM 103 MODULE 2 Exam 
Click this link to access the Periodic Table. This may be helpful throughout the exam. 
 
 
Show the calculation of the molecular weight for the following compounds, reporting your answer to 2 places after the decimal.
![CHEM 103 Module 1 to 6 Exam Questions and Answers (Portage Learning)](/docpics/641a01c613603_2498563.jpg)
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CHEM 103 Module 1 to 6 Exam Questions and Answers (Portage Learning)
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CHEM 103 Module 1 to 6 Exam Questions and Answers (Portage Learning) Convert 845.3 to exponential form and explain your answer. 
2. Convert 3.21 x 10-5 to ordinary form and explain your answer. 
1.Convert 845.3 = larger than 1 = positive exponent, move decimal 2 places 
= 8.453 x 102 
2.Convert 3.21 x 10-5 = negative exponent = smaller than 1, move decimal 5 
places = 0. 
Question 2 
Click this link to access the Periodic Table. This may be helpful throughout 
the exam. 
Using the following info...
CHEM 103 Module 2 exam with correct answersCHEM 103 Module 2 exam with correct answersCHEM 103 Module 2 exam with correct answers
![CHEM 103 Module 1 to 6 Exam Questions and Answers (Portage Learning)](/docpics/641a30ad15c1c_2499155.jpg)
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CHEM 103 Module 1 to 6 Exam Questions and Answers (Portage Learning)
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CHEM 103 Module 1 to 6 Exam Questions and Answers (Portage Learning) Show the calculation of the mass of a 18.6 ml sample of freon with 
density of 1.49 g/ml 
2. Show the calculation of the density of crude oil if 26.3 g occupies 30.5 
ml. 
1. M = D x V = 1.49 x 18.6 = 27.7 g 
2. D = M / V = 26.3 / 30.5 = 0.862 g/ml 
Question 5 
Click this link to access the Periodic Table. This may be helpful throughout 
the exam. 
1. 3.0600 contains ? significant figures. 
2. 0.0151 contains ? significant figu...
![PORTAGE LEARNING CHEM 121 MODULE 1 EXAM 2023 100% VERIFIED CORRECTLY.](/docpics/3137917/64c1b1a7a4c2e_3137917_121_171.jpeg)
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PORTAGE LEARNING CHEM 121 MODULE 1 EXAM 2023 100% VERIFIED CORRECTLY.
- Exam (elaborations) • 7 pages • 2023 Popular
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PORTAGE LEARNING CHEM 121 MODULE 1 EXAM 2023 100% VERIFIED CORRECTLY. 
 
CHEM 121 MODULE 1 EXAM 
 
 
Question 1	 
You may find the following resources helpful: Scientific Calculator (Links to an external site.) Periodic Table 
Equation Table 
 
 
Complete the two problems below: 
1.	Convert 1005.3 to exponential form and explain your answer. 
2.	Convert 4.87 x 10-6 to ordinary form and explain your answer. 
 
1.	Convert 1005.3 = larger than 1 = positive exponent, move decimal 3 places = 1.005...
CHEM 103 Module 2 exam with correct answers.
![CHEM 103 Module 2 Exam (General Chemistry) – Portage Learning](/docpics/641b807f6a008_2504041.jpg)
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CHEM 103 Module 2 Exam (General Chemistry) – Portage Learning
- Exam (elaborations) • 19 pages • 2023
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CHEM 103 Module 2 Exam (General Chemistry) – Portage Learning. Al (SO ) 
Al = 2 x 26.98 = 53.96 
S = 3 x 32.07 = 96.21 
O = 12 x 16.00 = 192 
2 4 3 
M2: Exam - Requires Respondus LockDown Browser + Webcam: General Chemistry I w/Lab-2021- Kozminski 
3/18 
Total Molecular Weight for Al (SO ) = 342.17 
2. C H NOBr 
C = 7 x 12.01 = 84.07 
H = 5 x 1.008 = 5.04 
N = 1 x 14.01 = 14.01 
O = 1 x 16.00 = 16.00 
Br = 1 x 79.90 = 79.90 
Total Molecule Weight for C H NOBr= 199.02
![CHEM 103 MODULE 2 EXAM 202](/docpics/3986431/6572d8fc858cd_3986431_121_171.jpeg)
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CHEM 103 MODULE 2 EXAM 202
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CHEM 103 
MODULE 2 EXAM 2022 
Question 1 
Click this link to access the Periodic Table. This may be helpful throughout 
the exam. 
Show the calculation of the molecular weight for the following 
compounds, reporting your answer to 2 places after the decimal. 
1. Al2(CO3)3 
2. C8H6NO4Cl 
1. 2Al + 3C + 9O = 233.99
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