CHEM 121 Exam 2 SPRING 2024 Portage learning
Show the calculation of the molecular weight for the following two compounds, reporting your answer to 2 places after the decimal. 1. Ca3(PO4)2 2. C9H8NO4Cl Your Answer: 1. 3(40.08)+2(30.97+4(16))=310.18 g/mol Ca3(PO4)2 2. 9(12.01)+8(1.008)+14.01+4(16)+35.45 = 229.61 g/mol C9H8NO4Cl 1. 3Ca + 2P + 8O = 310.18 2. 9C + 8H + N + 4O + Cl = 229.61 Question 2 9 / 10 pts You may find the following resources helpful: Scientific Calculator Links to an external site. Periodic Table Equation Table Show the calculation of the number of moles in the given amount of the following 2 substances. Report your answer to 3 significant figures. 1. 12.0 grams of Ca3(PO4)2 2. 15.0 grams of C9H8NO4Cl Your Answer: 1. 12 g x (1mol/310.18g) = .0387 mol Ca3(PO4)2
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chem 121 exam 2 spring 2024 portage learning