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Stewart Calculus Chapter 7.2 Exercise questions detailed solution (1-49) CA$15.11   Add to cart

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Stewart Calculus Chapter 7.2 Exercise questions detailed solution (1-49)

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It has very detailed step by step solution of Stewart Calculus Chapter 7.2 Trigonometric Integration solution from question no.1 to no.49

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  • March 17, 2022
  • 21
  • 2021/2022
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alexandrkim07
NEW ART CALCblur
MIDTERM 2 PREP

f. 2 EXERCISER : TRIGONOMETRIC INTEGRA W

#I
drink v3 Robt

=
funk and attack
=
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MR da ( by wing trig identity into + coif =
1)
bet a- una
du =
made → dn=¥a
GOING BACK TD INTEGRAL,

Armie ( 1-Mid) itddd

=/ till u4cw¥a -




=
✓w -
ut du
=
§ us ¥ v5 -
+ C

=
§ vivid -

§ um 'd + C




#2
✓ union"O do
=
✓ who unspoilt do
=
✓ who a- Arquette do ( by wing trig identity any +nice __
1)
bet U= rare

dn= who do
-
→ do = -


G-
GOING BACK TO INTEGRAL ,




✓ who (1-000) conto do
=
✓¥u7u4 ¥
= -

fuk it
=
✓ v6 UH -

, =
F- Ut § us
- + r

=
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§ canso + r




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""


=L unto are auto do


=f%uñowo( carat do
"

V. Lmaooooo ( trna) do ( by winging identity aif-m.no :| )
-
=




bet U= VMO → NEED to Do INTERVAL EVALUATION AN ITV
DEFINITE INTEGRAL
du=①rOdf→df=dfp ¥1307 ¥-1451 E. (601--100)
.





GOING BACK TO INTEGRAL, Who Ya Is Is I
"" * what
V.
-0

ritorno ( fumigate Erin =/



=D 'uwtut¥8
=D 'it( 1-uYdn=f'it(tau+u4dn
.



=

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%


( Eu :& n' You ] !
"

+

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=




¥+1
=
f- -




§ + ⇐ =


360
LcM= 8.45=360


=
_÷°= É +É3_
81




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#4




if "%nedñÑdk
if "%md( 1- aikido
let w- corn - NEED 1INTERVAL EVALUATION .




¥7
du =
-

Amnon away =
,
°

con 1--0007=0
%
GOING BACK INTEGRATION
¥!ñm
TO ,




if""umr( 1- conman ,

, vimeo.in#---f'u-u5C-dn) '
'
f. of ( 1- attu 4)
du
-

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=
=




=
[ u-tgus-E.us ];
=
I -




§ + § =
¥+3 =
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#5
✓ with) cars can)dk
=

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=
✓Milton cancan ) (1- WhTTmD (by wing tiny identity calf + why =
1)
bet warmth
du =
toucan)dk → able %-)
GOING BACK TO INTEGRAL
,

✓ unitary Akan) a- irritantTold
=/ uiarcmktu -5T¥ ,


v41 UT
-
= -

du

=
¥ ✓ all -
-
zu + U
"
) du
=
¥ ✓Cui 2U" -

+ us) du

¥ [In E. n' fit ]
"
= -
+ + r


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'
=
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+




# or >
( Fe )

um
old
rn

ÑdR=tWedn_
's
bet a-for & =




"
du -1£ a- a-
= + ⇐ on
✓Édn=✓¥
rn
.

( +2$ doh =
+2 Ariadne
= -2
✓rmuum2Udn=+2✓vmU( 1- MN) du (any tiny identity
any -1MW -
- 1)
let w =
once
dw= -
rm Udn →
dn=¥L-
GOING BACK TO INTEGRAL,

rmu ( 1-Arm ) due
=
-


WH -
w -3 _¥

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