Exam (elaborations)

Solution Manual for Vibrations 3rd Edition

3 views 0 purchase

Course
Science

Institution
University Of Toronto (U Of T )

Solution Manual for Vibrations 3rd Edition Solutions to Exercises Chapter 2 Section 2.1 2.1 Examine Eqs. (2.1) and (2.5) and verify that the units (dimensions) of the different terms in the respective equations are consistent. Solution 2.1 In Eqs. (2.1), the units of JG are kgm2 and th...

[Show more]

Preview 3 out of 20 pages

View example

Uploaded on July 20, 2022
Number of pages 20
Written in 2021/2022
Type Exam (elaborations)
Contains Unknown

solution manual for vibrations 3rd editionsolution manual for vibrations 3rd editionsolution manual for vibrations 3rd editionsolution manual for vibrations 3rd editionsolution manual for vibrations 3

donatrey Member since 2 year 79 documents sold

CA$19.36

Added

Add to cart Add to wishlist

100% satisfaction guarantee
Immediately available after payment
Both online and in PDF
No strings attached

Solution Manual for Vibrations 3rd Edition by
Balachandran

,Solutions Manual

Vibrations
3rd Edition

Balakumar Balachandran and Edward B. Magrab

, Solutions to Exercises
Chapter 2
Section 2.1
2.1 Examine Eqs. (2.1) and (2.5) and verify that the units (dimensions) of the different terms in
the respective equations are consistent.
Solution 2.1
In Eqs. (2.1), the units of JG are kgm2 and the units of md2 are kgm2. In Eq. (2.5), the units
of energy are Nm, and the units of mv2 are kg(m/s)2 = kg(m/s2)m = Nm.

Section 2.2

2.2 Consider the slider mechanism of Example 2.2 and show that the rotary inertia JO about the
pivot point O is also a function of the angular displacement .
Solution 2.2
The rotary inertia is
JO  J m ( )  J m  J m  J m
l s b e

where
1 1
J  m e2 J  m b2 J  m b2
me
3 e ms s mb
3 b

 l2   l 
2
l2
J ml ( )  m l  mld 2  m l      a2  al cos( )
12 12 2  
To determine how  depends on , we use geometry. First
r2 ( )  a2  b2  2ab cos
a2  r2 ( )  b2  2r( )b cos(     )
Combining the above equations, we obtain
r2( )  r2( )  b2  2r( )bcos(     )  b2  2abcos
which leads to
b  a cos  r( ) cos(     )
and, hence,
b  a cos
cos(     )  
r( )

1

The benefits of buying summaries with Stuvia:

Guaranteed quality through customer reviews

Stuvia customers have reviewed more than 700,000 summaries. This how you know that you are buying the best documents.

Quick and easy check-out

You can quickly pay through credit card or Stuvia-credit for the summaries. There is no membership needed.

Focus on what matters

Your fellow students write the study notes themselves, which is why the documents are always reliable and up-to-date. This ensures you quickly get to the core!

Frequently asked questions

What do I get when I buy this document?

You get a PDF, available immediately after your purchase. The purchased document is accessible anytime, anywhere and indefinitely through your profile.

Satisfaction guarantee: how does it work?

Our satisfaction guarantee ensures that you always find a study document that suits you well. You fill out a form, and our customer service team takes care of the rest.

Who am I buying these notes from?

Stuvia is a marketplace, so you are not buying this document from us, but from seller donatrey. Stuvia facilitates payment to the seller.

Will I be stuck with a subscription?

No, you only buy these notes for CA$19.36. You're not tied to anything after your purchase.

Can Stuvia be trusted?

4.6 stars on Google & Trustpilot (+1000 reviews)

79650 documents were sold in the last 30 days

Founded in 2010, the go-to place to buy study notes for 14 years now

Start selling

Exam (elaborations)

Solution Manual for Vibrations 3rd Edition

Document information

Subjects

Written for

Seller

Reviews received

Content preview