Class notes
Physics 1300 - 2D kinematics
- Course
- Physics 1300
- Institution
- University Of Guelph (U Of G )
phys 1300 - 2D kinematics, uofg sept 2023 - dec 2023
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Average Speed= -stanee
2I
Sample problem .
diameter 10 min
Swimmer cross circular
swimming pool of a 225
a) Calculate the
spes to
Speedar-average
= 0 .
82 m/s
3) at the same how take
average speed ,
long would the swimmer to swim
around the
edge of the pool ?
because know the
information given to must the
we
only us , we
rearrange
to
formula use what we have
d
Ot =
Speedau
=
(TT) 10 m m
>
- because we are
doing the whole pool circumfrance
,
0 82 m/s
.
= 64S
#
Checkpoint
car
goes arg Speed of
. 20 mis
for half an hour . Truck
goes arg speed
same time Which travelled
of 72 kemh
for .
further?
convert km/h
to
Cancel
(t) Trucke (Speedarg)
d
(Speedarg) d (t)
totes
car = :
outuni re = =
= (30 min) /20 m/s) x = (72 /em/k) 10. Sk).
= 36000 m = 36 /em = 36 /em
· Both Cars travelled the Same distance
, 2 D Kinematics
&X = X
,
-X , Chorizontal displacement)
&
y
:
Y2 Y ,
(vertical displacements
↑ :
position
↓ =
displacement
Or : Ux &
Oy lyz X
,
= r
, 2 Y X2 = "2
Sample problem : 4 I .
1) Total distance travelled
22m ,
36 22 + 34 = 56m travelled
T
NE +X -
34 m , 65'SE
36
+
y
Start-- 65
when
using components you ,
must
always
- (
.... I declare the xRy direction , I treat them
end
separately. This allows
you
to
find displacement
2) Displacement
OF :
0x20y X
,
= 22 m cos 36 Y = 22 Sin 136)
& findd = 17 . 8 m = 12 4 . m
x2 = 34cos(69) = 34 Sin (68)
42
0X = 17 . 8 + 14 4 . m = 32 Im
.
=
14 .
4 M = 30 8 . m
Oy = 12 4-30 8. . : -
17 P
. m
↳ The
ye component
is often
negative in this
measured as ,
case it is measured
negative
because we made our (South)
y-component facing down
DF = (32 2) .
"
+ ( -
17 . 4)
=
37 m
magnitude
O = tan" (
= 24
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