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PRAXIS Math Practice 5003.

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PRAXIS Math Practice 5003.

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  • July 2, 2024
  • 19
  • 2023/2024
  • Exam (elaborations)
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PRAXIS Math Practice 5003
3. Which of the following expressions is equivalent to the expression 21−6x for all
values of x ?
5−2(8−3x)
6+3(5−2x)
25−(4−6x)
3(4−2x)−9
7(3−2x)−8x - CORRECT ANSWER-6+3(5−2x)
Option (B) is correct. Using the distributive property, 6+3(5−2x)=6+15−6x=21−6x.
None of the other selections is equivalent to this.

5. A right circular cylinder with base B is shown. If a plane that is neither parallel
nor perpendicular to base B passes through the cylinder, which of the following
could be the shape of the intersection of the plane and the cylinder?

An ellipse with circumference less than the circumference of B
An ellipse with circumference greater than the circumference of B
An ellipse with circumference equal to the circumference of B
A circle with circumference less than the circumference of B
A circle with circumference greater than the circumference of B - CORRECT
ANSWER-Correct Answer: B
Option (B) is correct. A plane that is parallel to the base intersects the cylinder in
a circle, but because the intersecting plane is not parallel, the intersection is an
ellipse. One of the axes of the ellipse is equal to the diameter of the base, but the
other axis (in the direction of the tilt) is larger than the diameter. That means that
the circumference of the ellipse is greater than the circumference of the base.

6. If 5(2x+1)=3(x+4)−5, what is the value of x ? - CORRECT ANSWER-2/7
Solve the equation by first using the distributive property: 5(2x+1)=3(x+4)−5
becomes 10x+5=3x+12−5. Combining similar terms yields the equation
10x+5=3x+7. After subtracting 3x from both sides of the equation to get 7x + 5 =
7, subtracting 5 from both sides yields the equivalent equation 7x =2. The answer
is found by dividing each side of this equation by 7.

8. If x6 is between 3 and 4, which of the following could be the value of x ?

,14
17
20
25
26 - CORRECT ANSWER-25
Option (C) is correct. When the numbers 3 and 4 are written as fractions with a
denominator of 6, we need to find a value of x which satisfies the inequality
186<x6<246. This requires a number that lies between 18 and 24. The only
number among the given choices that does this is 20.

10. If triangle ABC in the xy-plane shown above is shifted 7 units to the right and
4 units up, what would be the coordinates of point A after the shift?

(1, -2)
(4, -2)
(4, 2)
(5, -2)
(5, 2)

A Start (-2)(-2) - CORRECT ANSWER-(5, 2)

11. 1.4, 1.8, 2.2, 2.0, 1.0, 1.9, 1.2, 2.1, 1.7
What is the median of the numbers in the list above?

1.2
1.4
1.7
1.8
1.9 - CORRECT ANSWER-1.8
Option (D) is correct. The median of an ordered set of data is the number
positioned where there are an equal number less than the number and greater
than the number (that is, the number in the "middle"). Rearranging the nine
numbers from least to greatest, the list becomes 1.0, 1.2, 1.4, 1.7, 1.8, 1.9, 2.0,
2.1, 2.2, where 1.8 is the fifth (middle) number in the list.

12. If 1/7x−2=1, then x=

, -7
3
9
15
21 - CORRECT ANSWER-Correct Answer: E
Option (E) is correct. Solve this equation by first adding 2 to both sides, resulting
in an equivalent equation 1/7x=3. Multiplying both sides of this equation by 7
yields 7(1/7x)=7(3) or x=21.

13. 1/4, 9/8, 2/3, 1/2, k, π
Question:
The five numbers shown above are listed in order from least to greatest. Which
of the following could be the value of k
Indicate all such values.
A. 2
B. .516
C. 238
D. 7‾‾√
E. 17‾‾‾√ - CORRECT ANSWER-A. 2 C. 238 D. 17‾‾‾√
The correct answers are (A), (C), and (D).

This problem can be answered using estimation. The value of k lies between
2312 (a number slightly less than 2 ) and π (a number slightly more than 3).
Since 516<1 and 17‾‾‾√>4, they can be eliminated easily. The other three choices
are greater than or equal to 2 and less than 3, which are in the necessary
interval.

15. Which of the following sequence of steps, when completed, will solve the
equation −6+3y=1 for y ?

Subtract 1 from both sides of the equation, then divide both sides of the new
equation by −6.
Subtract 1 from both sides of the equation, then divide both sides by 6.
Add 6 to both sides of the equation, then divide both sides by 3.
Add 6 to both sides, then subtract 3 from both sides.

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