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BC Calculus Test 2 Derivative rules and Rectalinear motion Questions and Answers CA$19.37   Add to cart
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BC Calculus Test 2 Derivative rules and Rectalinear motion Questions and Answers
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BC Calculus Test 2 Derivative rules and Rectalinear motion Questions and Answers Derivative Notation D(x)f(x) means the derivative wrt x With the big bar it means to evaluate at a specific value Second derivative is derivative of derivative Previous Play Next Rewind 10 seconds Mo...

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  • October 21, 2024
  • 4
  • 2024/2025
  • Exam (elaborations)
  • Questions & answers

Subjects

  • bc calculus test 2 derivative rules and rectalinea
  • power rule proof for negative integers look at fx
  • prove the derivative of a constant start out with

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BC Calculus Test 2 Derivative rules and
Rectalinear motion Questions and
Answers
Higher order derivatives - answer

Derivative Notation - answer D(x)f(x) means the derivative wrt x
With the big bar it means to evaluate at a specific value
Second derivative is derivative of derivative

Derivative Rules - answer

Power rule proof for negative integers - answer look at f(x) = x^(-n) as 1/x^n, then
use the quotient rule

Prove the derivative of a constant - answer Start out with limit definition, then when
subtracting you know something is a real zero vs approaching zero

Prove sum rule - answer

Prove derivative times constant - answer

Derivatives of trig functions - answer Tangent: Split into sine and cosine, then
product
cotangent: Same as tangent to split
Secant: Split into 1/cosine

Other way for cotangent is to split into 1/tan

Can also do def. of derivative with tangent and then use an identity and multiply by
jonjugate

Related Rates - answer Question will specify some specific rate and so then you do
the dy/dx for the specific variables, then based on the problem, you will be able to use
other equations to find the answer

Chain rule - answer When doing the chain rule, when you have that second function,
take the value of that funtion and plug it into the derivative at the next,
If you have two functions and one of the variables in the primary function can be related
with another, you can do the chain rule of dA/dr * dr/dt and multiply by the derivative of
the secondary function to get the relation of the first and the other variable.

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