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Chemistry IA (CH2040) UCF Questions and Correct Answers the Latest Update

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  • Course
  • Chemistry IA
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  • Chemistry IA

UNIT 4 Combustion of Methane: CH4(g) + 2 02 -> C02 (g) + 2 H20 (g) a) If we have five molecules of CH4 and eight molecules of 02, which is the limiting reactant? 02 is limiting reactant because it yields the least amount of product UNIT 4 N2 (g) + 3 H2 (g) -> 2 NH3 (g) Find mol of NH...

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  • November 11, 2024
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  • 2024/2025
  • Exam (elaborations)
  • Questions & answers
  • Chemistry IA
  • Chemistry IA
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Chemistry IA (CH2040) UCF Questions and
Correct Answers the Latest Update
UNIT 4

Combustion of Methane:

CH4(g) + 2 02 -> C02 (g) + 2 H20 (g)

a) If we have five molecules of CH4 and eight molecules of 02, which is the limiting reactant?

✓ 02 is limiting reactant because it yields the least amount of product



UNIT 4

N2 (g) + 3 H2 (g) -> 2 NH3 (g)

Find mol of NH3 (reactant and excess)

✓ H2 is the limiting reactant because it yields 2 molecules of NH3 while N2 yields 6
molecules of NH3



UNIT 4

How many moles of Si3N4 can be made from 1.20 moles of of Si and 1.00 moles of N2 in the

following reaction?

3 Si + 2 N2 -> Si3N4

✓ LOOK IN WEBCOURSES



UNIT 4

Percent Yield Formula:

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✓ %yield: actual yield/ theoretical yield



UNIT 4

64.0g of methanol, CH3OH, were expected to be produced through the reaction:

C0 (g) + 2 H2 (g) -> CH3OH (l)

One student got 56.0g of methanol, for the reaction in the laboratory. What is the % yield of

methanol?

✓ 87.5%



UNIT 4

Benzene, C6H6, reacts with bromine to form bromobenzene, C6H5Br and hydrogen bromide.

Reaction of 8.00 g benzene with excess bromine yield 12.85g bromobenzene. Calculate

%yield of bromobenzene.

✓ 79.9%



UNIT 4

Combustion Reactions:

✓ reaction of substance with O2 to form one or more oxygen containing compounds, often
including water.

✓ Compounds containing C & H & O always form C02 and H20 upon complete
combustion.



UNIT 4


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