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PHYS 1080 CLASS NOTES
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This detailed physics notes document compiles key concepts, equations, and visual aids from lectures and textbook material, providing a complete study resource. Covering topics such as kinematics, forces, momentum, energy, rotational motion, fluid dynamics, and thermodynamics, the notes offer cle...

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  • December 16, 2024
  • 23
  • 2024/2025
  • Class notes
  • James howard
  • All classes

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, is constant and want to find :
displacement
Duse when acceleration
~ velocity
Unit Conversions Kinematic Equations time

displacement
at3
no
·
·
mass conversion velocity-time :
Uf =
Vi +
given

332500/1000
Find time taken or
↳ 8/ =

Sky Vit + /2 at 2}
Ky
2 ⑧
distance travelled
Gram to d
position-time
= .




kilogram 1 000
: : =




S
↳
Kilogram to Gram :
G =

Kg
x
1000 3 (3kg)(1000) =
3000
g
·

velocity displacement
- : (vf)" (vil" +
= 2ad3 FindingUtof obetled
ut] Where i
·




·
time conversion Constant Xf Xi
Velocity
: = + derived from position-time



Se/601
↳
seconds to mins : Mins =

- 60 see in min



Se(3,00
3600 see in hour
In
seconds to hours :
Hours =
#
d = Vit +at

)
↳
39 4hrs) ↓ noaccelerationa
mins to hours : Mins = Chours) 1601 160) =
240mins
d =
Vit
·

Length conversion
↓Xi +
xi

↳
Cm to M: Metres
= / , so 39 isoom/100 = Sm Xf Xi
-
= Vit
↓
↳
m +o cm :
(m =
(m)(100) 329iSm)(100) =
500 em Xf =
Xi + Vit

L
cubic cm to cubic m : (cm3) = (m3)(100

Vector Addition
A
7 Finding Magnitude of X1Y component
of a vector
B
Vectors :
quantity wh both and direction (e velocity , displacement
↳ head to tail
& is adjacent (c
magnitude .


g .
force,
V ↳
A B v =
1/sin/cos0 or ooposite (sin
-
Adjacent to 0 Cos
<P ( 3)
+ =
- to component you
.
g
=
e .




to find
Ooposite to G = Sin trying
O
Vector Subtraction

10 ↳ head to tail NEGATIVE
>
a XB



Components of Vector
L
↳
breaks vector down into parts


Projectile
↳
Motion Equations
X-axis (horizontal) and y-axis (vertical
L
O R V Sin (20)



Inovsn
· =
is
always the vector makes wh X-axis
angle
G


Position -

Time Graphs
2g
(t) velocity 1-) velocity
( + acceleration

M
·

e
30 Eof N
-D .


.
g
Total Displacement for vector wh 2 components
t

① If
velocity , Find
④
change
in Find total displacement wh
mag-direction
( +) there is
1-) velocity velocity a

( acceleration

a = BY At D =
(dy(2 (dy)2
+




②
Find displacement (distance travelled
diag only numorater
- always y on
Vit + at
2
⑤ Use tan
constant constant
1) velocity
d= to find angle
(H)
velocity
③ Break down into X and
y components
0 =
tan" ( % a)
coslsin based



3
· determine
DX =
DCosO on
adjacent looposite from
it makes wix-axis
angle
Dy DSinG
=

(set equal)




3
used to find :
Relative Speed

·
-


how fast distance between objects is
Constant Speed increasing or
decreasing
L
Xf =
Xi + ut /how fast can
-


chasing problems
chaser overtake ?
·
Acceleration

12at difference in speeds
-




↳
Xf = vt +

, Kinematic Equation breakdown Set up variable equations when :

& Identify what you're being
① d =
vit +
112 at
2
·

unknown asked to find
quantity
·

relationships between quantities ② Assign a variable to unknown
use when :
you only have one velocity value , can be used to find
acceleration , distance , or time
③ Write out equation that connect
· involves dependant changing quantity
known values to unknown

② Uf =
Vit at ④ Solve equation


use when displacement isn't required , how
long it will take to reach
:



when you know
max
height ,
a is
g
Newtons 2nd Law Motion F
of : =
m x a


③ v vi2 = + had ↳
acceleration of an
object depends on two variables
,
the net force
acting on object
and the mass of object
use when : time isn't required and you have Uf and Vi
,
can
aid distance
finding acceleration
in or
·
Force
appliedDangle wh NO friction

↳ Find horizontal component of Force


Magnitude Change in Velocity (DU) line distance from Up to Of Forizontal (F) (sin/cos) &
:
of
straight
=




L if perpidicular then use
pythagoreum
gives Vi , Uf and t
·
Unknown force but ,


↳D
if not then :
L Understand
equations needed Tan =%a
①
Break initial velocity into X and
y ③ F = mxa Sin = In
L (v) (Cos/Sin) &
↓ cos
= In
& Break final velocity and y

BYDt
into X
② a =


LD (V) (Cos/sin) ⑦

① DV = (Vf) (Vil-




③ Find Change
in velocity for both xly components

LD (DVx) (Vfx) (Vix)
-
=




↳
(DUy) (Vfy) (iy)
= -

Newtons Law of Universal Gravitation

④ Find
Magnitude use when dealing
wl gravitional force between 2
:


masses not on surface of Earth
=
(Vx)2 + (y)2
gravitation
constant mass
(6 .
67x10-") mass of

Angle of Tension : determined by direction of tension G Mm
person
relative to some sense of direction F =

R2
Chorizontal or vertical)
weight radius
Ask yourself where does the pull /displacement) create tension ( force due
: to


what axis ? gravity)
and
along

Translational Equilibrium : all forces balance out and Fret
object is not
accelerating .




↳
·
subtract if
sum of all forces possing
(horizontal + vertical) must =
add if in same direction
going
·




Three forces where one is unknown 2 .


.
g Fret =
Forizontal
-


Ffriction
① Resolve each force into horizontal and vertical components , even unknown Fnet =
Fuertical +
Fnormal
& ·
(9 81m/s ?
Set all horizontal (X) components to zero find equation I in newtons and law for vertical is
,
solve to a
gravity .




③
Set all find equation 2
vertical (y) components to zero
,
solve to


& stack both equations (Sin numorater
on top of each other as



⑤
Solve for
using tan
⑥
Plug O into either equations to find R

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