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PEARSON EDEXCEL GCE A-LEVEL PHYSICS 6PH01 ADVANCED SUBSIDIARY UNIT 1 PHYSICS ON THE GO SUMMER EXAM 2024 (AUTHENTIC MARKING SCHEME ATTACHED). £7.16
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PEARSON EDEXCEL GCE A-LEVEL PHYSICS 6PH01 ADVANCED SUBSIDIARY UNIT 1 PHYSICS ON THE GO SUMMER EXAM 2024 (AUTHENTIC MARKING SCHEME ATTACHED).
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PEARSON EDEXCEL GCE A-LEVEL PHYSICS 6PH01 ADVANCED SUBSIDIARY UNIT 1 PHYSICS ON THE GO SUMMER EXAM 2024 (AUTHENTIC MARKING SCHEME ATTACHED).

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  • March 7, 2024
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  • 2023/2024
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Edexcel GCE
Physics
Advanced Subsidiary
Unit 1: Physics on the Go

Tuesday 20 May 2014 – Morning Paper Reference

Time: 1 hour 30 minutes 6PH01/01
You must have: Total Marks
Ruler, protractor




PEARSON EDEXCEL GCE A-LEVEL PHYSICS 6PH01
ADVANCED SUBSIDIARY UNIT 1 PHYSICS ON THE GO
SUMMER EXAM 2024

(AUTHENTIC MARKING SCHEME ATTACHED).
Turn over

P43118A *P43118A0128*
©2014 Pearson Education Ltd.
1/1/1/1/

, SECTION A

Answer ALL questions.

For questions 1–10, in Section A, select one answer from A to D and put a cross in
the box . If you change your mind, put a line through the box and then
mark your new answer with a cross .


1 Select the answer in which both quantities are vectors.
A acceleration, speed
B displacement, velocity

C mass, time

D power, weight

(Total for Question 1 = 1 mark)

2 A tennis ball hits a wall perpendicularly at a speed of 4 m síµ and rebounds at the same
speed.




4 m síµ




Taking the initial velocity as positive, the change in velocity is
A –4 m síµ
B –8 m síµ

C 0 m síµ

D 8 m síµ

(Total for Question 2 = 1 mark)




2
*P43118A0228*

,3 A mass of 0.05 kg is lifted at a slow steady speed by a 5 W electric motor.

The height the mass rises in 8 s is found using

5
A 0.05 ×9.81×8
5×8
B 0.05 × 9.81
C 0.05 × 9.81
5×8
D 0.05 × 9.81 × 8
5
(Total for Question 3 = 1 mark)

4 A child slides down four frictionless slides A, B, C and D.




A B C D




The speed of the child at the bottom of slides A, B, C and D is given by vA, vB, vC and vD
respectively.
Choose the correct statement.

A vA = vB = vC = vD

B vA > vB and vC > vD
C vA > vB > vC = vD

D vA > vC and vB > vD

(Total for Question 4 = 1 mark)




3
*P43118A0328* Turn over

, 5 $VSULQJZLWKDVSULQJFRQVWDQWµ1P±µ is extended. The elastic potential
energy VWRUHGLVµ-
The extension of the wire is found using

A 1.6
140

B 2×1.6
140
C 1.6
140
D 2 ×1.6
140
(Total for Question 5 = 1 mark)

6 Q and R are drops of two different fluids which have been placed on one end of a tile.
The tile is then tilted.
The diagram shows how the drops spread down the tile.

Q R
start position




Which could be a correct explanation for the different lengths shown?
A R has a greater viscosity than Q.

B R has a greater density than Q.

C R has a greater temperature than Q.

D All of the above.

(Total for Question 6 = 1 mark)




4
*P43118A0428*

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