Summary
Summary Gravitational and electric fields notes
- Institution
- WJEC
Unit 4 a level physics notes
[Show more]
Seller
Follow
Content preview
Forces and field strengths.EQUATIONS - Question one-
Gravitational Force ME = 5-97×1024 kg
ME MM
I Newtons Law of gravitation - MM = 7-37×1022 Kg
F= ¥eo 'r? • gravity acts between any 2 objects with mass. P mass = 100kg
F α M, M 2 342×103 km 38×103 km 6=6-67×10-"
E= Far, ALWAYS ATTRACTIVE
4T EO r2
T =
GmiM2 opposite direction (-)
• Force of gravity is an example of an inverse square relationship:
r2
VE-4¥ • C) indicates that force acts in opposite direction to distance.
co r moon → p
gravitational constant = 6-67×10-" ① Earth → P 2
1 Q2 F = 6- 67×10-11 × 5.97×1024×100 F = - 6--67×10-11 ✗ 7.3
PE:*,
r gravitational F α - GM, m² mass of two objects (342×10672 (38×
force between r² F = - 0-34
W = GAVE 2 bodies distance between F = 0 - 34
(WEIGHT) as r increases 2 objects i. {F = 0.34 - 0-34 = ON
F decreases
GM,M2
F = IPS Question two - NEED TO USE VECT
r2 DEFINITION of Newtons Law of gravity: F α plroduct of masses Mm
350×106 m
g: GM The force of attraction between two point masses between 2 points
x
r2 is proportional to the product of the masses of the two
F α 7 EF 80×106 m
points and is inversely proportional to the square of between
Vg:-GI 6.2N
the distance between them. distance? them
r 4×10-3N
M, Mz ME
PE = - GM, Mr
n F Differences between forces, F- = GM/Mz ① Moon → sat
W= mΔVg gravitational and electrostatic? F- = 6- 67×
r2
• gravitational forces are only
r
Constants attractive where as electrostatic
M, and Mz are both attracting eachother forces can be repulsive and h O a 6.2N F = 4 -013
Me = 9.11×10-31 because of newtons 3rd law → one force attractive.
applied between 2 objects. • gravitational deals with masses ② Earth → sa
6=6-67×10-11 electrostatic deals with charges. F = 6-67
SIMILARITIES of 4×010-3N
Electrostatic force CAN BE REPULSIVE
Eo = 8-85×10-12 AND ATTRACTIVE gravitational + electrostatic
F α ⟂ coulombs law ~ point charges • both obey inverse O = tan-' (8) F = 6- 2N
F- α Q, 2 1 82
square law
charge of two objects • both have infinite EF = (6-2)-+ (4×
force between F= 7 1 Q2 range EF = a²+b²
two point charges 4T EO r2 0=0- 037° f
distance between
constant two point charges
= 9.0×109
The benefits of buying summaries with Stuvia:
Guaranteed quality through customer reviews
Stuvia customers have reviewed more than 700,000 summaries. This how you know that you are buying the best documents.
Quick and easy check-out
You can quickly pay through credit card for the summaries. There is no membership needed.
Focus on what matters
Your fellow students write the study notes themselves, which is why the documents are always reliable and up-to-date. This ensures you quickly get to the core!
Frequently asked questions
What do I get when I buy this document?
You get a PDF, available immediately after your purchase. The purchased document is accessible anytime, anywhere and indefinitely through your profile.
Satisfaction guarantee: how does it work?
Our satisfaction guarantee ensures that you always find a study document that suits you well. You fill out a form, and our customer service team takes care of the rest.
Who am I buying these notes from?
Stuvia is a marketplace, so you are not buying this document from us, but from seller careyneale2005. Stuvia facilitates payment to the seller.
Will I be stuck with a subscription?
No, you only buy these notes for £2.99. You're not tied to anything after your purchase.
Can Stuvia be trusted?
4.6 stars on Google & Trustpilot (+1000 reviews)
73216 documents were sold in the last 30 days
Founded in 2010, the go-to place to buy revision notes and other study material for 14 years now