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Principles of Physics SAQ exemplar answers

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This document contains the answers for the Principles of Physics SAQ document.

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  • October 3, 2024
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ANSWERS TO SAQS
Subject: Physics
Unit: Principles of Physics
Topic: 1-2 Principles of Physics
Level: 3




© DistanceLearningCentre.com, 2022 1

, Subject: Physics
Unit: Principles of Physics
Topic: Principles of Physics
Level: 3
ANSWERS TO SAQs



SAQ 1:

1. List as many different types of energy as you can. Try to think of an
example of each type of energy that you come up with.

2.

a) A 20 N crate is lifted 5 m from the floor onto a shelf at a speed of
Topic 1 15ms-1. How much kinetic energy is used to lift the crate? Assume
that the force of gravity is 10ms-2

b) How much potential energy does the 20 N crate have whilst sat
on the self?

3.
a) A 30N force is used to pull a block along a friction-free surface
for 10m. How much work has been done?

b) A travel kettle has a power of 1kW. It boils a cup of water in 80
seconds. How much energy is transferred?

c) A person whose mass is 80kg runs up two flights of stairs,
totalling 20m high, in 10 seconds. What is the average power of
the person?

4. Draw a Sankey diagram to represent a filament lamp where only
10% of the electrical energy is converted into light energy.


Answers:

1.

• Gravitational Potential – satellite in orbit
• Kinetic – a ball rolling down a hill
• Elastic Potential - stretched hair bobble
• Sound – car horn
• Thermal/Heat – toaster
• Electric – between 2 charged particles
• Magnetic – Earth
• Chemical – food
• Light – lightbulb
• Nuclear – Nuclear power plant

You may find other types as well




© DistanceLearningCentre.com, 2022 2

, Subject: Physics
Unit: Principles of Physics
Topic: Principles of Physics
Level: 3
ANSWERS TO SAQs



2.

a)

To calculate KE determine mass first

Mass (kg) = weight (N) ÷ Acceleration of gravity (ms-2)

Mass = 20 N ÷ 10 ms-2
Mass = 2 Kg
𝟏
KE (J) = 𝟐 mass (Kg) x Velocity (ms)2
KE = 1 Kg x (15 ms-1)2
KE = 1 Kg x 225 ms-1
KE = 225 J

b)

PE (J) = mass (Kg) x gravity (ms-2) x height (m)

PE = 2 Kg x 10 (ms-2) x 5 (m)

PE = 100 J

3.

a) Work done = Force x distance moved
W = 30 x 10

W = 300J

b) Power = Work done (energy transferred) / time

W=Pxt

W = 1000 x 80

W = 80,000J

c) Power = Work done (energy transferred) / time

Assuming all work done is transferred into the Gravitational potential
energy (GPE) of the person:

Energy transferred = final GPE (mgh)

Power = mass x gravitational field strength x height / time

Power = (80 x 10 x 20) / 10




© DistanceLearningCentre.com, 2022 3

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