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Summary Comprehensive final exam review: EVERYTHING you need to know from student who got 93% in Orgo 2223. Includes notes from all prep 101 sessions. CA$58.07   Add to cart

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Summary Comprehensive final exam review: EVERYTHING you need to know from student who got 93% in Orgo 2223. Includes notes from all prep 101 sessions.

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Comprehensive final exam review: EVERYTHING you need to know from student who got 93% in Orgo 2223. Includes notes from all prep 101 sessions.

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  • August 12, 2023
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CHEM 2223 FINAL EXAM
REVIEW
2pm April 22nd, 2023

,Carbohydrates
Monosaccharides
 Glycoprotein: proteins + short, branched carbs
o Cell-surface receptors
 Proteoglycan: proteins + long, linear carbs
o Connective tissue
 Peptidoglycan: short oligopeptides cross-linking long, linear carbs
o Cell walls of bacteria
 Lipopolysaccharides: fatty acids + carbs
o Outer membrane of gram-negative bacteria
 Empirical formula: CH2O
 Molecular formula: Cn(H2O)n
 Aldose = aldehyde
o Anomeric C connected to 1H
 Ketose = ketone
o Anomeric C not connected to an H (2C, 1OH, 1O)
 “ulose” = ketone
 Glyceraldehyde: D = +; L = -
 D/L enantiomer: switch position of OH on every chiral C
 Cyclization to hemiacetal = nucleophilic addition
 Anomers:
o α = OH on anomeric C on opposite side as CH2OH
o β = OH on anomeric C on same side as CH2OH
 At equilibrium, anomer with OH on anomeric C in more stable equatorial position
present at higher abundance
 Hemiacetal = OH, OR will mutarotate
 Acetal = OR, OR will not mutarotate
 Acetal formation: hemiacetal + ROH (O-glycoside) or NR2H (N-glycoside)
o SN1 via C+ intermediate
o Makes both α and β but won’t mutarotate once formed

Fischer to Haworth:
i) Number carbons in Fischer
ii) Draw Haworth structure for aldose = pyranose (6-mem ring, including O) or ketose =
furanose (5-mem ring, including O with C1 branched off C2)
iii) Number carbons in Haworth ring
iv) Draw in C6: D = up, L = down
v) Draw in OH on anomeric C: α = opposite C6, β = same as C6
vi) Fill in remaining OH (right = down, left = up)
 Oxidation:


1

, o Bromine water = oxidize just aldehyde to COOH
o HNO3 = oxidize aldehyde and primary alcohol on C6 to COOH
 Reduction: reduce aldehyde to CH2OH or ketone to OH, H
o NaBH4
 Glucose = epimer of mannose = const. isomer of fructose
o Deprot Cα, will get mix of all 3
o Epimerization: Deprot Cα, form enolate C-/C=C, reprotonate Cα on opposite face
o Isomerization: 2 tautomerizations
 Deprot Cα, form C-, form O- (C=C), protonate O-, deprotonate other OH,
form C=O to form C-, protonate C-
 Aldol Reaction:
i) Deprot Cα
ii) C- attacks C=O of another equivalent
iii) Protonate O-
iv) Forms β hydroxy ketone
 Retro-aldol: cleave between α and β
Kiliani Fischer
 Extends chain one carbon at a time
 # rounds of synthesis = # carbons added just below C1 aldehyde
 Makes new chiral center: 2 products
 Step 1: nuc addition of CN- to carbonyl
 Historic:
o Aqueous acid to hydrolyze CN to COOH
o Spontaneously form lactone (cyclic ester)
o NaOH to hydrolyze to carboxylate salt
o Recrystalize salts (diastereomers with diff physical properties)
o Protonate COO- (forms lactone = cyclic ester)
o Reduce ester to aldehyde with Na/Hg
 Modern:
o Add H2 + Pd/BaSO4 catalyst to reduce nitrile to imine
o Add aqueous acid to hydrolyze imine to aldehyde
o Separate by HPLC
o Fewer steps / recrystallization / separations
o Fewer toxic reagents




2

, Disaccharides
 Disaccharides: two monosaccharides (aldoses or ketoses) connected via an acetal linkage
= glycoside
o At least one sugar’s anomeric carbon is involved in the acetal, though both may
be involved
 Acetals are cleaved by acid
 Acetals are stable in neutral and basic conditions (unlike hemiacetals)
 Acetals do not interconvert with their open chain forms
o Do not mutarotate
o Are not reducing
 If one part of the disaccharide molecule is a hemiacetal (ie., one anomeric carbon is not
involved in the acetal) then the whole molecule will mutarotate and will be a reducing
sugar
Disaccharides of D-Glucose: Maltose and Cellobiose
 Both have hemiacetals: mutarotate and are reducing
 Maltose joined by α 1,4
 Cellobiose joined by β 1, 4
Lactose
 Lactose = D-galactose + D-glucose joined β(1,4)
 Lactase aka. β-galactosidase cleaves lactose linkage
o Lactose intolerant individuals deficient in this enzyme
Sucrose
 Sucrose = D-glucose + D-fructose
o Linkage = α(1,2) at glucose, β(2, 1) at fructose
 No hemiacetals (both anomeric carbons involved in acetal) so does not mutarotate and is
not reducing
 Sucrose (disaccharide) = “invert sugar” because when hydrolyzed to monosaccharides
(glucose and fructose), the direction of optical rotation changes / inverts
o Sucrose rotates PPL +
o Glucose + fructose mixture rotates PPL –
 Glucose + fructose mixture is twice as sweet tasting than sucrose




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