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Mathematics 1A Tutorial

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Mathematics 1A Tutorial

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  • March 31, 2021
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EN1911 (Mathematics 1A) Numerical Integration Tutorial 1


Tutorial - Numerical Integration

Trapeziodal
𝑥𝑛

∫ 𝑓(𝑥) 𝑑𝑥 ≈ (𝑦 + 2𝑦1 + 2𝑦2 + ⋯ + 2𝑦𝑛−2 + 2𝑦𝑛−1 + 𝑦𝑛 )
𝑥0 2 0
Simpsons
𝑥𝑛
ℎ 𝑥𝑛 − 𝑥0
∫ 𝑓(𝑥) 𝑑𝑥 ≈ (𝑦 + 4𝑦1 + 2𝑦2 + ⋯ + 2𝑦𝑛−2 + 4𝑦𝑛−1 + 𝑦𝑛 ) where ℎ=
𝑥0 3 0 𝑛

1 𝑑𝑥
1. Approximate ∫0 using the Trapezoidal Rule using 5 data points (step size is 0.25).
1+𝑥 2


2. Repeat Q1 using Simpson’s rule.

1.5
3. Approximate ∫0 𝑥 sin(𝑥) 𝑑𝑥 using the Trapezoidal Rule with step size 0.25.

4. Repeat Q3 using Simpson’s rule.

5. Use Simpson’s rule to approximate the definite integral of the function 𝑓(𝑥) over the
interval 𝑥 = 2 to 𝑥 = 2.6, given the values of the function in the table below.

𝑥 2.0 2.1 2.2 2.3 2.4 2.5 2.6
𝑦 = 𝑓(𝑥) 3.2 2.7 4.1 3.8 3.5 4.6 5.2

6. Use Simpson’s rule with step size ℎ = 0.5 to approximate the integral
3
∫1 √1 + 𝑥 3 𝑑𝑥


1
7. The increase in the voltage on a capacitor is given by 𝑉 = 𝐶 ∫ 𝐼(𝑡) 𝑑𝑡.
For a 10 𝐹 capacitor (recall that F = 10–6F) the following data is recorded for the
current 𝐼(𝑡) against time 𝑡; use this data and Simpson’s rule to estimate the voltage
increase across the capacitor after 2ms.

time (10–3 s) 0.0 0.5 1.0 1.5 2.0
–3
current (10 amp) 2.5 1.75 1.25 0.90 0.70


Answers

1. Sum is 6.2624  Integral is 0.783
2. Sum is 9.4247  Integral is 0.785
3. Sum is 7.1772  Integral is 0.897
4. Sum is 10.6959  Integral is 0.891
5. Sum is 68  Integral is 2.267
6. Sum is 37.3818  Integral is 6.230
7. Sum is 16.3  Integral is 2.7167 (in 𝐶). Divide by 𝐶 = 10 𝐹 to get 𝑉 = 0.272 𝑉

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