MATH 533 Week 8 Final Exam Set 3 | Already Graded A+
MATH 533 Week 8 Final Exam Set 3 | Already graded A+
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MATH 533 Week 8 Final Exam Set 3 (100% CORRECT Solution) | Already graded A+
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MATH 533 Week 8 Final Exam Set 3 | Already graded A+
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MATH 533 Week 8 Final Exam Set 3 | Already Graded A+
MATH 533 Week 8 Final Exam Set 3 (100% CORRECT Solution) | Already graded A+
MATH 533 Week 8 Final Exam Set 3 (100% CORRECT Solution) | Already graded A+
math 533 week 8 final exam set 3 100 correct solution | already graded a
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MATH 533 Week 8 Final Exam Set 3 | Already graded A+
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MATH 533 Week 8 Final Exam Set 3
Answer The length of time to do a cable installation by
Multi-Cable Inc. is normally distributed with a mean of 42.8
minutes & a standard deviation of 6.2 minutes. What
percentage of installations take less than 30 minutes?
x = The length of time to do a cable installation
= 42.8
= 6.20
Answer Accident claims are checked for completeness by
branch offices of Fortune Insurance before they are sent to
a regional office for payment. Historically 80% of the
claims are complete when they reach the regional office.
You select a random sample of 20 claims that have arrived at
the regional office. Find the probability that:
X = Number of completed forms in sample
n = 20
p = 0.80
Answer Until this year the mean braking distance of a Nikton automobile moving at 60
miles per hour was 175 feet. Nikton engineers have developed what they consider a better
braking system. They test the new brake system on a random sample of 81 cars &
determine the sample mean braking distance. The results are:
x = 167 feet s = 27 feet
a. Compute the 90% confidence interval for the mean
braking distance. Interpret this interval.
s
x z𝛼 ( )
n
2
27
167 (1.645)( )
81
167 4.935
162.1 171.9
We are 90% confident that the population mean breaking distance
is between 162.1 ft & 171.9 ft.
b. How many cars should be tested if Nikton wants to be 90%
confident of being within 2 feet of the population mean
braking distance? Assume the sample size will be larger than
30.
( z 𝛼 )2
2
(1.645)2 (27 )2
n = 2
= = 493.17 = 494
2 (2 )
B 2
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