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Summary CIE A-level Biology: Classification, Biodiversity and Conservation (A*) £8.56   Add to cart

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Summary CIE A-level Biology: Classification, Biodiversity and Conservation (A*)

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Hi everyone:)) Here are my CIE A2 level Biology topic notes for the syllabus. These notes are tailored to the A level syllabus as well as the mark scheme as if you do enough past paper questions you will see a recurring pattern with the types of questions asked about each topic. My notes include s...

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  • Chapter 18
  • September 1, 2022
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  • 2022/2023
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SPEARMAN RANK -

correlation co -




efficient rs


Mld8UMS the
strength Of a correlation between two sets of paired data [ variable n and
y
)

>
Vs valves between -
1 and I

> -

I [ perfect c- ) correlation I 0 ( no Corre lotion ) -11 ( perfect Ct > correlation )
,




data ( in order ) another group data ( in order )
comparing group
one of to of


• ordinal data
requires ☒
can be converted to ordinal

Date NOT distributed
normally -




It
÷

does not need to be a linear relationship
minimum no .


Of paired observation = 5 Moms Moms Biology Biology
best 10-30 Student score rdhk score rank di


Si 57 3
Slept :
there is no
statistically significant correlation between 83 7


NULL measurement 1 and measurement 2 Sz 45 I 37 I 0


53 7- 2 7 41 2 5 2


there is 54 8 8.5
significant correlation between 7- 8
statistically
no no 85 0-5 0


and 53 2 3
correlation
biology scores moms scores .
Ss 56

56 6 3 5 85 8.5 3-5 1
OR
St 86 9 77 6 3



Alternative There 2 Sg 98 8 7
is
Statistically significant correlation 10 10
= 0


5 9 4
Sq 5




-
between biology scores and moms scores .
70

2
Sio 71 6 59 4


n= number of
2
step 2 :
Rs
=
I -

6-2 di individuals in the
'




n
} n
sample
-




↳ with identicle
-



t.rs ≤ 1 scores divide
by no .
of


di subjects
difference in the rank the two
.




of
=




meotsnrements made on an individual
n = 10

Edi 2=68.5
}
Step : rank each set of data
→ In
Biology ,
a
probability of 5% is adopted so
,


as a standard convention
step 4 :
conch / ate rs

only chose p = 0.05 Rs =
1-
6 (68-5)
103 -
10
Step 5 :
calculate critical value s
-




r o 585
-
-




If calculated rs is < Vs critical value = ACCEPT NULL HYPOTHESIS If the loiknloted value of Rs > rs critical value

↳ There is NO
significant correction REJECT NULL HYPOTHESIS
[
=




The
probability the correlation is one to chance is greater then 5% likely biological 5 ↳
significant correlation between and

[[
a
y
treason
The probability of the correlation occurred

due choice < 5%
likely correlation due to chance to

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