Summary
Summary AQA A Level Chemistry Rate Equations Notes
- Institution
- AQA
AQA A Level Chemistry Rate Equations Summarised Notes. Made these on iPad from textbook, youtube videos and exam questions.
[Show more]
Seller
Follow
Content preview
RATE EQUATIONSCALCULATING RATE FROM A GRAPH
in
Rate can be found from the gradient orange
a
cuse a
bigger section of the
graph
Rate can also be found from the of a tangent
foot on a curved line of best fit.
↳ With curves, draw a
tangent
across the
4 extend the line right graph
4 the gradient is the rate at the specific point on the curve.
y
"a tangent
THE RATE EQUATION ORDERS
The rate equation links rate with entrations of substances
rate =
k(AT"(B]*
conc. of substance
rate/moldmn-s- -
e.g. in
following
equ. A + B -> c+ D
rate constant
units vary
ORDERS OF REACTION
↳ an order is the power to which
- -
a conc. is raised to in the rate equation. It tells us how the cone of
the substance affects the rate.
·
ICROORDER: changes in conc. that have no effect on rate
e.g.
if (A] doubles then rate doesn't change.
·PORACR: changes in conc has a proportional change on rate e.g. if [A] doubles then rate
doubles.
,·
INPORDER: changes in conc. has a
squared proportional change on a rate e.g. if [A] doubles then rate
quadruples.
!orders can
only be determined by an experiment, you can't work it out by looking at an equation.
The Rate Equation Rate a Constant
The rate equ. Links rate with cone of substances.
rate constant K -
a constant no that allows us to ->
only fixed at a particular temperature,
equate rate a conc. if the temperature changes so does the
rate constant. ('K'increases when temp
increases).
- the larger the value of is, the faster the rate of reaction.
↳
we increase the temperature, the panicles have kinetic collide often, this increases
as more
energy a more
the rate
rate k/A]"/B]*
=
↳
but the cone of the substances remain constant.
↳to make this
equ balance the value of multicoreace.
CALCULATING RATE
be calculated the rate equation.
rate can
by using
·
EXAMPLE: The following reaction was carried out in a lab.
2
NO,g +
O,(g) ->
2NOc(g)
It was found that the reaction is "order with respect to NO and I order with respect to 02. Calculate
the rate of reaction given the conc. of NO 3x10% and 0, is 1x10%. The rate constant in
700,000 mol "dm's-'
↳ 1: write rate expression
rate k(No] [0,]'
=
↳ 2: substitute the numbers
rate= 700,000 x (3x10%'x((x10) =
6.3x10 "moldmn"s
The benefits of buying summaries with Stuvia:
Guaranteed quality through customer reviews
Stuvia customers have reviewed more than 700,000 summaries. This how you know that you are buying the best documents.
Quick and easy check-out
You can quickly pay through credit card for the summaries. There is no membership needed.
Focus on what matters
Your fellow students write the study notes themselves, which is why the documents are always reliable and up-to-date. This ensures you quickly get to the core!
Frequently asked questions
What do I get when I buy this document?
You get a PDF, available immediately after your purchase. The purchased document is accessible anytime, anywhere and indefinitely through your profile.
Satisfaction guarantee: how does it work?
Our satisfaction guarantee ensures that you always find a study document that suits you well. You fill out a form, and our customer service team takes care of the rest.
Who am I buying these notes from?
Stuvia is a marketplace, so you are not buying this document from us, but from seller jeliahh. Stuvia facilitates payment to the seller.
Will I be stuck with a subscription?
No, you only buy these notes for £4.49. You're not tied to anything after your purchase.
Can Stuvia be trusted?
4.6 stars on Google & Trustpilot (+1000 reviews)
79976 documents were sold in the last 30 days
Founded in 2010, the go-to place to buy revision notes and other study material for 14 years now